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Nov 19, 2022CodeCatch
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Caesar Encryption

Mar 10, 2021Skrome

0 likes • 1 view

import string
def caesar(text, shift, alphabets):
def shift_alphabet(alphabet):
return alphabet[shift:] + alphabet[:shift]
shifted_alphabets = tuple(map(shift_alphabet, alphabets))
final_alphabet = "".join(alphabets)
final_shifted_alphabet = "".join(shifted_alphabets)
table = str.maketrans(final_alphabet, final_shifted_alphabet)
return text.translate(table)
plain_text = "Hey Skrome, welcome to CodeCatch"
print(caesar(plain_text, 8, [string.ascii_lowercase, string.ascii_uppercase, string.punctuation]))

Using logic with sets

Nov 18, 2022AustinLeath

0 likes • 1 view

#Sets
U = {0,1,2,3,4,5,6,7,8,9}
P = {1,2,3,4}
Q = {4,5,6}
R = {3,4,6,8,9}
def set2bits(xs,us) :
bs=[]
for x in us :
if x in xs :
bs.append(1)
else:
bs.append(0)
assert len(us) == len(bs)
return bs
def union(set1,set2) :
finalSet = set()
bitList1 = set2bits(set1, U)
bitList2 = set2bits(set2, U)
for i in range(len(U)) :
if(bitList1[i] or bitList2[i]) :
finalSet.add(i)
return finalSet
def intersection(set1,set2) :
finalSet = set()
bitList1 = set2bits(set1, U)
bitList2 = set2bits(set2, U)
for i in range(len(U)) :
if(bitList1[i] and bitList2[i]) :
finalSet.add(i)
return finalSet
def compliment(set1) :
finalSet = set()
bitList = set2bits(set1, U)
for i in range(len(U)) :
if(not bitList[i]) :
finalSet.add(i)
return finalSet
def implication(a,b):
return union(compliment(a), b)
###########################################################################################
###################### Problems 1-6 #######################################
###########################################################################################
#p \/ (q /\ r) = (p \/ q) /\ (p \/ r)
def prob1():
return union(P, intersection(Q,R)) == intersection(union(P,Q), union(P,R))
#p /\ (q \/ r) = (p /\ q) \/ (p /\ r)
def prob2():
return intersection(P, union(Q,R)) == union(intersection(P,Q), intersection(P,R))
#~(p /\ q) = ~p \/ ~q
def prob3():
return compliment(intersection(P,R)) == union(compliment(P), compliment(R))
#~(p \/ q) = ~p /\ ~q
def prob4():
return compliment(union(P,Q)) == intersection(compliment(P), compliment(Q))
#(p=>q) = (~q => ~p)
def prob5():
return implication(P,Q) == implication(compliment(Q), compliment(P))
#(p => q) /\ (q => r) => (p => r)
def prob6():
return implication(intersection(implication(P,Q), implication(Q,R)), implication(P,R))
print("Problem 1: ", prob1())
print("Problem 2: ", prob2())
print("Problem 3: ", prob3())
print("Problem 4: ", prob4())
print("Problem 5: ", prob5())
print("Problem 6: ", prob6())
'''
Problem 1: True
Problem 2: True
Problem 3: True
Problem 4: True
Problem 5: True
Problem 6: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}
'''

screencap.py

Jan 23, 2021asnark

0 likes • 0 views

"""
Take screenshots at x interval - make a movie of doings on a computer.
"""
import time
from datetime import datetime
import ffmpeg
import pyautogui
while True:
epoch_time = int(time.time())
today = datetime.now().strftime("%Y_%m_%d")
filename = str(epoch_time) + ".png"
print("taking screenshot: {0}".format(filename))
myScreenshot = pyautogui.screenshot()
myScreenshot.save(today + "/" + filename)
time.sleep(5)
#
# and then tie it together with: https://github.com/kkroening/ffmpeg-python/blob/master/examples/README.md#assemble-video-from-sequence-of-frames
#
"""
import ffmpeg
(
ffmpeg
.input('./2021_01_22/*.png', pattern_type='glob', framerate=25)
.filter('deflicker', mode='pm', size=10)
.filter('scale', size='hd1080', force_original_aspect_ratio='increase')
.output('movie.mp4', crf=20, preset='slower', movflags='faststart', pix_fmt='yuv420p')
.run()
)
"""

Propositional logic with itertools

Nov 18, 2022AustinLeath

0 likes • 5 views

from itertools import product
V='∀'
E='∃'
def tt(f,n) :
xss=product((0,1),repeat=n)
print('function:',f.__name__)
for xs in xss : print(*xs,':',int(f(*xs)))
print('')
# p \/ (q /\ r) = (p \/ q) /\ (p \/ r)
def prob1(p,q,r) :
x=p or (q and r)
y= (p or q) and (p or r)
return x==y
tt(prob1,3)
# p/\(q\/r)=(p/\q)\/(p/\r)
def prob2(p,q,r) :
x=p and ( q or r )
y=(p and q) or (p and r)
return x==y
tt(prob2,3)
#~(p/\q)=(~p\/~q)
def prob3(p,q) :
x=not (p and q)
y=(not p) or (not q)
return x==y
tt(prob3,2)
#(~(p\/q))=((~p)/\~q)
def prob4(p, q):
x = not(p or q)
y = not p and not q
return x == y
tt(prob4, 2)
#(p/\(p=>q)=>q)
def prob5(p,q):
x= p and ( not p or q)
return not x or q
tt(prob5,2)
# (p=>q)=((p\/q)=q)
def prob6(p,q) :
x = (not p or q)
y=((p or q) == q)
return x==y
tt(prob6,2)
#((p=>q)=(p\/q))=q
def prob7(p,q):
if ((not p or q)==(p or q))==q:
return 1
tt(prob7,2)
#(p=>q)=((p/\q)=p)
def prob8(p,q):
if (not p or q)==((p and q)==p):
return 1
tt(prob8,2)
#((p=>q)=(p/\q))=p
def prob9(p,q):
if ((not p or q)==(p and q))==p:
return '1'
tt(prob9,2)
#(p=>q)/\(q=>r)=>(p=>r)
def prob10(p,q,r) :
x = not ((not p or q) and (not q or r)) or (not p or r)
return x
tt(prob10, 3)
# (p = q) /\ (q => r) => (p => r)
#answer 1
def prob11(p,q,r) :
x = not((p is q) and (not q or r)) or (not p or r)
return x
tt(prob11, 3)
#(p=q)/\(q=>r)=>(p=>r)
#answer 2
def prob11(p,q,r):
x=(p==q) and (not q or r)
y=not p or r
return not x or y
tt(prob11,3)
#((p=>q)/\(q=r))=>(p=>r)
def prob12(p,q,r):
x=(not p or q) and ( q==r )
y=not p or r
return not x or y
tt(prob12,3)
#(p=>q)=>((p/\r)=>(q/\r))
def prob13(p,q,r):
x=not p or q
y=(not(p and r) or ( q and r))
return not x or y
tt(prob13,3)
#Question#2----------------------------------------
#(p=>q)=>r=p=>(q=>r)
def prob14(p,q,r):
x=(not(not p or q) or r)
y=(not p or (not q or r))
return x==y
tt(prob14,3)
def prob15(p, q):
x = not(p and q)
y = not p and not q
return x == y
tt(prob15, 2)
def prob16(p, q):
x = not(p or q)
y = not p or not q
return x == y
tt(prob16, 2)
def prob17(p):
x = p
y = not p
return x == y
tt(prob17, 1)

primes numbers finder

Mar 12, 2021mo_ak

0 likes • 1 view

prime_lists=[] # a list to store the prime numbers
def prime(n): # define prime numbers
if n <= 1:
return False
# divide n by 2... up to n-1
for i in range(2, n):
if n % i == 0: # the remainder should'nt be a 0
return False
else:
prime_lists.append(n)
return True
for n in range(30,1000): # calling function and passing starting point =30 coz we need primes >30
prime(n)
check=0 # a var to limit the output to 10 only
for n in prime_lists:
for x in prime_lists:
val= n *x
if (val > 1000 ):
check=check +1
if (check <10) :
print("the num is:", val , "=",n , "* ", x )
break

Calculator

Nov 19, 2022CodeCatch

0 likes • 0 views

""" Calculator
----------------------------------------
"""
def addition ():
print("Addition")
n = float(input("Enter the number: "))
t = 0 //Total number enter
ans = 0
while n != 0:
ans = ans + n
t+=1
n = float(input("Enter another number (0 to calculate): "))
return [ans,t]
def subtraction ():
print("Subtraction");
n = float(input("Enter the number: "))
t = 0 //Total number enter
sum = 0
while n != 0:
ans = ans - n
t+=1
n = float(input("Enter another number (0 to calculate): "))
return [ans,t]
def multiplication ():
print("Multiplication")
n = float(input("Enter the number: "))
t = 0 //Total number enter
ans = 1
while n != 0:
ans = ans * n
t+=1
n = float(input("Enter another number (0 to calculate): "))
return [ans,t]
def average():
an = []
an = addition()
t = an[1]
a = an[0]
ans = a / t
return [ans,t]
// main...
while True:
list = []
print(" My first python program!")
print(" Simple Calculator in python by Malik Umer Farooq")
print(" Enter 'a' for addition")
print(" Enter 's' for substraction")
print(" Enter 'm' for multiplication")
print(" Enter 'v' for average")
print(" Enter 'q' for quit")
c = input(" ")
if c != 'q':
if c == 'a':
list = addition()
print("Ans = ", list[0], " total inputs ",list[1])
elif c == 's':
list = subtraction()
print("Ans = ", list[0], " total inputs ",list[1])
elif c == 'm':
list = multiplication()
print("Ans = ", list[0], " total inputs ",list[1])
elif c == 'v':
list = average()
print("Ans = ", list[0], " total inputs ",list[1])
else:
print ("Sorry, invilid character")
else:
break