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Remove i'th character

Nov 19, 2022CodeCatch

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# Python code to demonstrate
# method to remove i'th character
# Naive Method
# Initializing String
test_str = "CodeCatch"
# Printing original string
print ("The original string is : " + test_str)
# Removing char at pos 3
# using loop
new_str = ""
for i in range(len(test_str)):
if i != 2:
new_str = new_str + test_str[i]
# Printing string after removal
print ("The string after removal of i'th character : " + new_str)

Palindrome checker

Nov 19, 2022CodeCatch

0 likes • 6 views

# function which return reverse of a string
def isPalindrome(s):
return s == s[::-1]
# Driver code
s = "malayalam"
ans = isPalindrome(s)
if ans:
print("Yes")
else:
print("No")

UNT CSCE 2100 Question 1

Nov 18, 2022AustinLeath

0 likes • 8 views

#question1.py
def rose(n) :
if n==0 :
yield []
else :
for k in range(0,n) :
for l in rose(k) :
for r in rose(n-1-k) :
yield [l]+[r]+[r]
def start(n) :
for x in rose(n) :
print(x) #basically I am printing x for each rose(n) file
print("starting program: \n")
start(2) # here is where I call the start function

delay time lambda

Nov 19, 2022CodeCatch

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from time import sleep
def delay(fn, ms, *args):
sleep(ms / 1000)
return fn(*args)
delay(lambda x: print(x), 1000, 'later') # prints 'later' after one second
my_list = [1, 2, 3, 4, 5]
removed_element = my_list.pop(2) # Remove and return element at index 2
print(removed_element) # 3
print(my_list) # [1, 2, 4, 5]
last_element = my_list.pop() # Remove and return the last element
print(last_element) # 5
print(my_list) # [1, 2, 4]

Sieve of Eratosthenes

Nov 19, 2022CodeCatch

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# Given a number n, print all primes smaller than or equal to n. It is also given that n is a small number.
# For example, if n is 10, the output should be “2, 3, 5, 7”. If n is 20, the output should be “2, 3, 5, 7, 11, 13, 17, 19”.
# Python program to print all primes smaller than or equal to
# n using Sieve of Eratosthenes
def SieveOfEratosthenes(n):
# Create a boolean array "prime[0..n]" and initialize
# all entries it as true. A value in prime[i] will
# finally be false if i is Not a prime, else true.
prime = [True for i in range(n + 1)]
p = 2
while (p * p <= n):
# If prime[p] is not changed, then it is a prime
if (prime[p] == True):
# Update all multiples of p
for i in range(p * 2, n + 1, p):
prime[i] = False
p += 1
prime[0]= False
prime[1]= False
# Print all prime numbers
for p in range(n + 1):
if prime[p]:
print (p)
# driver program
if __name__=='__main__':
n = 30
print("Following are the prime numbers smaller")
print("than or equal to ", n)
print("than or equal to ", n)
SieveOfEratosthenes(n)