• Nov 18, 2022 •AustinLeath
0 likes • 9 views
#Python 3: Fibonacci series up to n def fib(n): a, b = 0, 1 while a < n: print(a, end=' ') a, b = b, a+b print() fib(1000)
• May 31, 2023 •CodeCatch
0 likes • 3 views
import itertools def compute_permutations(string): # Generate all permutations of the string permutations = itertools.permutations(string) # Convert each permutation tuple to a string permutations = [''.join(permutation) for permutation in permutations] return permutations # Prompt the user for a string string = input("Enter a string: ") # Compute permutations permutations = compute_permutations(string) # Display the permutations print("Permutations:") for permutation in permutations: print(permutation)
• Nov 19, 2022 •CodeCatch
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""" Rock Paper Scissors ---------------------------------------- """ import random import os import re os.system('cls' if os.name=='nt' else 'clear') while (1 < 2): print "\n" print "Rock, Paper, Scissors - Shoot!" userChoice = raw_input("Choose your weapon [R]ock], [P]aper, or [S]cissors: ") if not re.match("[SsRrPp]", userChoice): print "Please choose a letter:" print "[R]ock, [S]cissors or [P]aper." continue // Echo the user's choice print "You chose: " + userChoice choices = ['R', 'P', 'S'] opponenetChoice = random.choice(choices) print "I chose: " + opponenetChoice if opponenetChoice == str.upper(userChoice): print "Tie! " #if opponenetChoice == str("R") and str.upper(userChoice) == "P" elif opponenetChoice == 'R' and userChoice.upper() == 'S': print "Scissors beats rock, I win! " continue elif opponenetChoice == 'S' and userChoice.upper() == 'P': print "Scissors beats paper! I win! " continue elif opponenetChoice == 'P' and userChoice.upper() == 'R': print "Paper beat rock, I win! " continue else: print "You win!"
• Sep 14, 2024 •rgannedo-6205
0 likes • 2 views
https://codecatch.net/post/06c9f5b7-1e00-40dc-b436-b8cccc4b69be
• Dec 18, 2025 •CodeCatch
def insertion_sort(arr): # Traverse through 1 to len(arr) for i in range(1, len(arr)): key = arr[i] # Move elements of arr[0..i-1], that are greater than key, # to one position ahead of their current position j = i - 1 while j >= 0 and key < arr[j]: arr[j + 1] = arr[j] j -= 1 arr[j + 1] = key # Example usage: arr = [12, 11, 13, 5, 6, 7, 8, 10] insertion_sort(arr) print("Sorted array is:", arr)
0 likes • 7 views
def when(predicate, when_true): return lambda x: when_true(x) if predicate(x) else x double_even_numbers = when(lambda x: x % 2 == 0, lambda x : x * 2) print(double_even_numbers(2)) # 4 print(double_even_numbers(1)) # 1