• Nov 19, 2022 •CodeCatch
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def print_pyramid_pattern(n): # outer loop to handle number of rows # n in this case for i in range(0, n): # inner loop to handle number of columns # values changing acc. to outer loop for j in range(0, i+1): # printing stars print("* ",end="") # ending line after each row print("\r") print_pyramid_pattern(10)
• Oct 10, 2025 •AustinLeath
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#Original def output_json_log_data_to_file(filename, record_dictionary_list): with open(filename, 'w') as outputFile: for record in record_dictionary_list: json.dump(record, outputFile) outputFile.write('\n') #Atomic def output_json_log_data_to_file(filename, record_dictionary_list): # Use atomic file operations to prevent race conditions with readers # Write to temporary file first, then atomically rename to target file tmp_filename = filename + '.tmp' with open(tmp_filename, 'w') as outputFile: for record in record_dictionary_list: json.dump(record, outputFile) outputFile.write('\n') # Atomic rename - this prevents readers from seeing partial writes shutil.move(tmp_filename, filename)
• May 31, 2023 •CodeCatch
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# Prompt user for base and height base = float(input("Enter the base of the triangle: ")) height = float(input("Enter the height of the triangle: ")) # Calculate the area area = (base * height) / 2 # Display the result print("The area of the triangle is:", area)
from collections import defaultdict def collect_dictionary(obj): inv_obj = defaultdict(list) for key, value in obj.items(): inv_obj[value].append(key) return dict(inv_obj) ages = { 'Peter': 10, 'Isabel': 10, 'Anna': 9, } collect_dictionary(ages) # { 10: ['Peter', 'Isabel'], 9: ['Anna'] }
• Nov 18, 2022 •AustinLeath
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# question3.py from itertools import product V='∀' E='∃' def tt(f,n) : xss=product((0,1),repeat=n) print('function:',f.__name__) for xs in xss : print(*xs,':',int(f(*xs))) print('') # this is the logic for part A (p\/q\/r) /\ (p\/q\/~r) /\ (p\/~q\/r) /\ (p\/~q\/~r) /\ (~p\/q\/r) /\ (~p\/q\/~r) /\ (~p\/~q\/r) /\ (~p\/~q\/~r) def parta(p,q,r) : a=(p or q or r) and (p or q or not r) and (p or not q or r)and (p or not q or not r) b=(not p or q or r ) and (not p or q or not r) and (not p or not q or r) and (not p or not q or not r) c= a and b return c def partb(p,q,r) : a=(p or q and r) and (p or not q or not r) and (p or not q or not r)and (p or q or not r) b=(not p or q or r ) and (not p or q or not r) and (not p or not q or r) and (not p or not q or not r) c= a and b return c print("part A:") tt(parta,3) print("part B:") tt(partb,3)
# Python program for Plotting Fibonacci # spiral fractal using Turtle import turtle import math def fiboPlot(n): a = 0 b = 1 square_a = a square_b = b # Setting the colour of the plotting pen to blue x.pencolor("blue") # Drawing the first square x.forward(b * factor) x.left(90) x.forward(b * factor) x.left(90) x.forward(b * factor) x.left(90) x.forward(b * factor) # Proceeding in the Fibonacci Series temp = square_b square_b = square_b + square_a square_a = temp # Drawing the rest of the squares for i in range(1, n): x.backward(square_a * factor) x.right(90) x.forward(square_b * factor) x.left(90) x.forward(square_b * factor) x.left(90) x.forward(square_b * factor) # Proceeding in the Fibonacci Series temp = square_b square_b = square_b + square_a square_a = temp # Bringing the pen to starting point of the spiral plot x.penup() x.setposition(factor, 0) x.seth(0) x.pendown() # Setting the colour of the plotting pen to red x.pencolor("red") # Fibonacci Spiral Plot x.left(90) for i in range(n): print(b) fdwd = math.pi * b * factor / 2 fdwd /= 90 for j in range(90): x.forward(fdwd) x.left(1) temp = a a = b b = temp + b # Here 'factor' signifies the multiplicative # factor which expands or shrinks the scale # of the plot by a certain factor. factor = 1 # Taking Input for the number of # Iterations our Algorithm will run n = int(input('Enter the number of iterations (must be > 1): ')) # Plotting the Fibonacci Spiral Fractal # and printing the corresponding Fibonacci Number if n > 0: print("Fibonacci series for", n, "elements :") x = turtle.Turtle() x.speed(100) fiboPlot(n) turtle.done() else: print("Number of iterations must be > 0")