Color Gradient
• Skrome
0 likes • Mar 10, 2021
Python
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from collections import Counterdef find_parity_outliers(nums):return [x for x in numsif x % 2 != Counter([n % 2 for n in nums]).most_common()[0][0]]find_parity_outliers([1, 2, 3, 4, 6]) # [1, 3]
prime_lists=[] # a list to store the prime numbersdef prime(n): # define prime numbersif n <= 1:return False# divide n by 2... up to n-1for i in range(2, n):if n % i == 0: # the remainder should'nt be a 0return Falseelse:prime_lists.append(n)return Truefor n in range(30,1000): # calling function and passing starting point =30 coz we need primes >30prime(n)check=0 # a var to limit the output to 10 onlyfor n in prime_lists:for x in prime_lists:val= n *xif (val > 1000 ):check=check +1if (check <10) :print("the num is:", val , "=",n , "* ", x )break
# importing the modulesimport osimport shutil# getting the current working directorysrc_dir = os.getcwd()# printing current directoryprint(src_dir)# copying the filesshutil.copyfile('test.txt', 'test.txt.copy2') #copy src to dst# printing the list of new filesprint(os.listdir())
# Python program to reverse a linked list# Time Complexity : O(n)# Space Complexity : O(n) as 'next'#variable is getting created in each loop.# Node classclass Node:# Constructor to initialize the node objectdef __init__(self, data):self.data = dataself.next = Noneclass LinkedList:# Function to initialize headdef __init__(self):self.head = None# Function to reverse the linked listdef reverse(self):prev = Nonecurrent = self.headwhile(current is not None):next = current.nextcurrent.next = prevprev = currentcurrent = nextself.head = prev# Function to insert a new node at the beginningdef push(self, new_data):new_node = Node(new_data)new_node.next = self.headself.head = new_node# Utility function to print the linked LinkedListdef printList(self):temp = self.headwhile(temp):print temp.data,temp = temp.next# Driver program to test above functionsllist = LinkedList()llist.push(20)llist.push(4)llist.push(15)llist.push(85)print "Given Linked List"llist.printList()llist.reverse()print "\nReversed Linked List"llist.printList()
# Python program for implementation of Selection# Sortimport sysA = [64, 25, 12, 22, 11]# Traverse through all array elementsfor i in range(len(A)):# Find the minimum element in remaining# unsorted arraymin_idx = ifor j in range(i+1, len(A)):if A[min_idx] > A[j]:min_idx = j# Swap the found minimum element with# the first elementA[i], A[min_idx] = A[min_idx], A[i]# Driver code to test aboveprint ("Sorted array")for i in range(len(A)):print("%d" %A[i]),
def when(predicate, when_true):return lambda x: when_true(x) if predicate(x) else xdouble_even_numbers = when(lambda x: x % 2 == 0, lambda x : x * 2)print(double_even_numbers(2)) # 4print(double_even_numbers(1)) # 1