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LeetCode Flood Fill

0 likes • Oct 15, 2022
Python
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when predicate lambda

CodeCatch
0 likes • Nov 19, 2022
Python
def when(predicate, when_true):
return lambda x: when_true(x) if predicate(x) else x
double_even_numbers = when(lambda x: x % 2 == 0, lambda x : x * 2)
print(double_even_numbers(2)) # 4
print(double_even_numbers(1)) # 1

Propositional logic with itertools

AustinLeath
0 likes • Nov 18, 2022
Python
from itertools import product
V='∀'
E='∃'
def tt(f,n) :
xss=product((0,1),repeat=n)
print('function:',f.__name__)
for xs in xss : print(*xs,':',int(f(*xs)))
print('')
# p \/ (q /\ r) = (p \/ q) /\ (p \/ r)
def prob1(p,q,r) :
x=p or (q and r)
y= (p or q) and (p or r)
return x==y
tt(prob1,3)
# p/\(q\/r)=(p/\q)\/(p/\r)
def prob2(p,q,r) :
x=p and ( q or r )
y=(p and q) or (p and r)
return x==y
tt(prob2,3)
#~(p/\q)=(~p\/~q)
def prob3(p,q) :
x=not (p and q)
y=(not p) or (not q)
return x==y
tt(prob3,2)
#(~(p\/q))=((~p)/\~q)
def prob4(p, q):
x = not(p or q)
y = not p and not q
return x == y
tt(prob4, 2)
#(p/\(p=>q)=>q)
def prob5(p,q):
x= p and ( not p or q)
return not x or q
tt(prob5,2)
# (p=>q)=((p\/q)=q)
def prob6(p,q) :
x = (not p or q)
y=((p or q) == q)
return x==y
tt(prob6,2)
#((p=>q)=(p\/q))=q
def prob7(p,q):
if ((not p or q)==(p or q))==q:
return 1
tt(prob7,2)
#(p=>q)=((p/\q)=p)
def prob8(p,q):
if (not p or q)==((p and q)==p):
return 1
tt(prob8,2)
#((p=>q)=(p/\q))=p
def prob9(p,q):
if ((not p or q)==(p and q))==p:
return '1'
tt(prob9,2)
#(p=>q)/\(q=>r)=>(p=>r)
def prob10(p,q,r) :
x = not ((not p or q) and (not q or r)) or (not p or r)
return x
tt(prob10, 3)
# (p = q) /\ (q => r) => (p => r)
#answer 1
def prob11(p,q,r) :
x = not((p is q) and (not q or r)) or (not p or r)
return x
tt(prob11, 3)
#(p=q)/\(q=>r)=>(p=>r)
#answer 2
def prob11(p,q,r):
x=(p==q) and (not q or r)
y=not p or r
return not x or y
tt(prob11,3)
#((p=>q)/\(q=r))=>(p=>r)
def prob12(p,q,r):
x=(not p or q) and ( q==r )
y=not p or r
return not x or y
tt(prob12,3)
#(p=>q)=>((p/\r)=>(q/\r))
def prob13(p,q,r):
x=not p or q
y=(not(p and r) or ( q and r))
return not x or y
tt(prob13,3)
#Question#2----------------------------------------
#(p=>q)=>r=p=>(q=>r)
def prob14(p,q,r):
x=(not(not p or q) or r)
y=(not p or (not q or r))
return x==y
tt(prob14,3)
def prob15(p, q):
x = not(p and q)
y = not p and not q
return x == y
tt(prob15, 2)
def prob16(p, q):
x = not(p or q)
y = not p or not q
return x == y
tt(prob16, 2)
def prob17(p):
x = p
y = not p
return x == y
tt(prob17, 1)

Number guessing game

CodeCatch
0 likes • Nov 19, 2022
Python
""" Number Guessing Game
----------------------------------------
"""
import random
attempts_list = []
def show_score():
if len(attempts_list) <= 0:
print("There is currently no high score, it's yours for the taking!")
else:
print("The current high score is {} attempts".format(min(attempts_list)))
def start_game():
random_number = int(random.randint(1, 10))
print("Hello traveler! Welcome to the game of guesses!")
player_name = input("What is your name? ")
wanna_play = input("Hi, {}, would you like to play the guessing game? (Enter Yes/No) ".format(player_name))
// Where the show_score function USED to be
attempts = 0
show_score()
while wanna_play.lower() == "yes":
try:
guess = input("Pick a number between 1 and 10 ")
if int(guess) < 1 or int(guess) > 10:
raise ValueError("Please guess a number within the given range")
if int(guess) == random_number:
print("Nice! You got it!")
attempts += 1
attempts_list.append(attempts)
print("It took you {} attempts".format(attempts))
play_again = input("Would you like to play again? (Enter Yes/No) ")
attempts = 0
show_score()
random_number = int(random.randint(1, 10))
if play_again.lower() == "no":
print("That's cool, have a good one!")
break
elif int(guess) > random_number:
print("It's lower")
attempts += 1
elif int(guess) < random_number:
print("It's higher")
attempts += 1
except ValueError as err:
print("Oh no!, that is not a valid value. Try again...")
print("({})".format(err))
else:
print("That's cool, have a good one!")
if __name__ == '__main__':
start_game()

screencap.py

asnark
0 likes • Jan 23, 2021
Python
"""
Take screenshots at x interval - make a movie of doings on a computer.
"""
import time
from datetime import datetime
import ffmpeg
import pyautogui
while True:
epoch_time = int(time.time())
today = datetime.now().strftime("%Y_%m_%d")
filename = str(epoch_time) + ".png"
print("taking screenshot: {0}".format(filename))
myScreenshot = pyautogui.screenshot()
myScreenshot.save(today + "/" + filename)
time.sleep(5)
#
# and then tie it together with: https://github.com/kkroening/ffmpeg-python/blob/master/examples/README.md#assemble-video-from-sequence-of-frames
#
"""
import ffmpeg
(
ffmpeg
.input('./2021_01_22/*.png', pattern_type='glob', framerate=25)
.filter('deflicker', mode='pm', size=10)
.filter('scale', size='hd1080', force_original_aspect_ratio='increase')
.output('movie.mp4', crf=20, preset='slower', movflags='faststart', pix_fmt='yuv420p')
.run()
)
"""

Untitled

sebastianagauyao2002-61a8
0 likes • Apr 21, 2023
Python
print("hellur")
import copy
begining = [False,False,False,False,False,None,True,True,True,True,True]
#False = black True = white
its = [0]
def swap(layout, step):
layoutCopy = copy.deepcopy(layout)
layoutCopy[(step[0]+step[1])], layoutCopy[step[1]] = layoutCopy[step[1]], layoutCopy[(step[0]+step[1])]
return layoutCopy
def isSolved(layout):
for i in range(len(layout)):
if(layout[i] == False):
return (i >= (len(layout)/2))
def recurse(layout, its, steps = []):
if isSolved(layout):
its[0] += 1
print(layout,list(x[0] for x in steps))
return
step = None
for i in range(len(layout)):
if(layout[i] == None):
if(i >= 1): #If the empty space could have something to the left
if(layout[i - 1] == False):
step = [-1,i]
recurse(swap(layout,step), its, (steps+[step]))
if(i > 1): #If the empty space could have something 2 to the left
if(layout[i - 2] == False):
step = [-2,i]
recurse(swap(layout,step), its, (steps+[step]))
if(i < (len(layout)-1)): #If the empty space could have something to the right
if(layout[i + 1] == True):
step = [1,i]
recurse(swap(layout,step), its, (steps+[step]))
if(i < (len(layout)-2)): #If the empty space could have something to the right
if(layout[i + 2] == True):
step = [2,i]
recurse(swap(layout,step), its, (steps+[step]))
its[0] += 1
#return None
recurse(begining,its,[])
print(its[0])