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import itertoolsimport stringimport timedef guess_password(real):chars = string.ascii_lowercase + string.ascii_uppercase + string.digits + string.punctuationattempts = 0for password_length in range(1, 9):for guess in itertools.product(chars, repeat=password_length):startTime = time.time()attempts += 1guess = ''.join(guess)if guess == real:return 'password is {}. found in {} guesses.'.format(guess, attempts)loopTime = (time.time() - startTime);print(guess, attempts, loopTime)print("\nIt will take A REALLY LONG TIME to crack a long password. Try this out with a 3 or 4 letter password and see how this program works.\n")val = input("Enter a password you want to crack that is 9 characters or below: ")print(guess_password(val.lower()))
def calculate_values():value1 = 10value2 = 20return value1, value2result1, result2 = calculate_values()print("Result 1:", result1)print("Result 2:", result2)
def when(predicate, when_true):return lambda x: when_true(x) if predicate(x) else xdouble_even_numbers = when(lambda x: x % 2 == 0, lambda x : x * 2)print(double_even_numbers(2)) # 4print(double_even_numbers(1)) # 1
def sum_of_powers(end, power = 2, start = 1):return sum([(i) ** power for i in range(start, end + 1)])sum_of_powers(10) # 385sum_of_powers(10, 3) # 3025sum_of_powers(10, 3, 5) # 2925
def print_pyramid_pattern(n):# outer loop to handle number of rows# n in this casefor i in range(0, n):# inner loop to handle number of columns# values changing acc. to outer loopfor j in range(0, i+1):# printing starsprint("* ",end="")# ending line after each rowprint("\r")print_pyramid_pattern(10)
list_1 = [1,2,3,4,5,6,7,8,9]cubed = map(lambda x: pow(x,3), list_1)print(list(cubed))#Results#[1, 8, 27, 64, 125, 216, 343, 512, 729]