• May 31, 2023 •CodeCatch
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def generate_floyds_triangle(num_rows): triangle = [] number = 1 for row in range(num_rows): current_row = [] for _ in range(row + 1): current_row.append(number) number += 1 triangle.append(current_row) return triangle def display_floyds_triangle(triangle): for row in triangle: for number in row: print(number, end=" ") print() # Prompt the user for the number of rows num_rows = int(input("Enter the number of rows for Floyd's Triangle: ")) # Generate Floyd's Triangle floyds_triangle = generate_floyds_triangle(num_rows) # Display Floyd's Triangle display_floyds_triangle(floyds_triangle)
• Nov 18, 2022 •AustinLeath
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# List lst = [1, 2, 3, 'Alice', 'Alice'] # One-Liner indices = [i for i in range(len(lst)) if lst[i]=='Alice'] # Result print(indices) # [3, 4]
• Oct 4, 2023 •AustinLeath
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weigh = lambda a,b: sum(b)-sum(a) FindCoin = lambda A: 0 if (n := len(A)) == 1 else (m := n//3) * (w := 1 + weigh(A[:m], A[2*m:])) + FindCoin(A[m*w:m*(w+1)]) print(FindCoin([1,1,1,1,1,1,1,2,1]))
• Apr 15, 2021 •NoahEaton
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import anytree as at import random as rm # Generate a tree with node_count many nodes. Each has a number key that shows when it was made and a randomly selected color, red or white. def random_tree(node_count): # Generates the list of nodes nodes = [] for i in range(node_count): test = rm.randint(1,2) if test == 1: nodes.append(at.Node(str(i),color="white")) else: nodes.append(at.Node(str(i),color="red")) #Creates the various main branches for i in range(node_count): for j in range(i, len(nodes)): test = rm.randint(1,len(nodes)) if test == 1 and nodes[j].parent == None and (not nodes[i] == nodes[j]): nodes[j].parent = nodes[i] #Collects all the main branches into a single tree with the first node being the root for i in range(1, node_count): if nodes[i].parent == None and (not nodes[i] == nodes[0]): nodes[i].parent = nodes[0] return nodes[0]
• Feb 26, 2023 •wabdelh
#You are given a two-digit integer n. Return the sum of its digits. #Example #For n = 29 the output should be solution (n) = 11 def solution(n): return (n//10 + n%10)
import calendar # Prompt user for year and month year = int(input("Enter the year: ")) month = int(input("Enter the month: ")) # Create a calendar object cal = calendar.monthcalendar(year, month) # Display the calendar print(calendar.month_name[month], year) print("Mon Tue Wed Thu Fri Sat Sun") for week in cal: for day in week: if day == 0: print(" ", end="") else: print(str(day).rjust(2), " ", end="") print()