• Nov 19, 2022 •CodeCatch
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# Python program for Plotting Fibonacci # spiral fractal using Turtle import turtle import math def fiboPlot(n): a = 0 b = 1 square_a = a square_b = b # Setting the colour of the plotting pen to blue x.pencolor("blue") # Drawing the first square x.forward(b * factor) x.left(90) x.forward(b * factor) x.left(90) x.forward(b * factor) x.left(90) x.forward(b * factor) # Proceeding in the Fibonacci Series temp = square_b square_b = square_b + square_a square_a = temp # Drawing the rest of the squares for i in range(1, n): x.backward(square_a * factor) x.right(90) x.forward(square_b * factor) x.left(90) x.forward(square_b * factor) x.left(90) x.forward(square_b * factor) # Proceeding in the Fibonacci Series temp = square_b square_b = square_b + square_a square_a = temp # Bringing the pen to starting point of the spiral plot x.penup() x.setposition(factor, 0) x.seth(0) x.pendown() # Setting the colour of the plotting pen to red x.pencolor("red") # Fibonacci Spiral Plot x.left(90) for i in range(n): print(b) fdwd = math.pi * b * factor / 2 fdwd /= 90 for j in range(90): x.forward(fdwd) x.left(1) temp = a a = b b = temp + b # Here 'factor' signifies the multiplicative # factor which expands or shrinks the scale # of the plot by a certain factor. factor = 1 # Taking Input for the number of # Iterations our Algorithm will run n = int(input('Enter the number of iterations (must be > 1): ')) # Plotting the Fibonacci Spiral Fractal # and printing the corresponding Fibonacci Number if n > 0: print("Fibonacci series for", n, "elements :") x = turtle.Turtle() x.speed(100) fiboPlot(n) turtle.done() else: print("Number of iterations must be > 0")
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# Python code to demonstrate # method to remove i'th character # Naive Method # Initializing String test_str = "CodeCatch" # Printing original string print ("The original string is : " + test_str) # Removing char at pos 3 # using loop new_str = "" for i in range(len(test_str)): if i != 2: new_str = new_str + test_str[i] # Printing string after removal print ("The string after removal of i'th character : " + new_str)
• May 31, 2023 •CodeCatch
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import itertools def compute_permutations(string): # Generate all permutations of the string permutations = itertools.permutations(string) # Convert each permutation tuple to a string permutations = [''.join(permutation) for permutation in permutations] return permutations # Prompt the user for a string string = input("Enter a string: ") # Compute permutations permutations = compute_permutations(string) # Display the permutations print("Permutations:") for permutation in permutations: print(permutation)
• Nov 18, 2022 •AustinLeath
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#question1.py def rose(n) : if n==0 : yield [] else : for k in range(0,n) : for l in rose(k) : for r in rose(n-1-k) : yield [l]+[r]+[r] def start(n) : for x in rose(n) : print(x) #basically I am printing x for each rose(n) file print("starting program: \n") start(2) # here is where I call the start function
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# Given a number n, print all primes smaller than or equal to n. It is also given that n is a small number. # For example, if n is 10, the output should be “2, 3, 5, 7”. If n is 20, the output should be “2, 3, 5, 7, 11, 13, 17, 19”. # Python program to print all primes smaller than or equal to # n using Sieve of Eratosthenes def SieveOfEratosthenes(n): # Create a boolean array "prime[0..n]" and initialize # all entries it as true. A value in prime[i] will # finally be false if i is Not a prime, else true. prime = [True for i in range(n + 1)] p = 2 while (p * p <= n): # If prime[p] is not changed, then it is a prime if (prime[p] == True): # Update all multiples of p for i in range(p * 2, n + 1, p): prime[i] = False p += 1 prime[0]= False prime[1]= False # Print all prime numbers for p in range(n + 1): if prime[p]: print (p) # driver program if __name__=='__main__': n = 30 print("Following are the prime numbers smaller") print("than or equal to ", n) print("than or equal to ", n) SieveOfEratosthenes(n)
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mydict = {'carl':40, 'alan':2, 'bob':1, 'danny':0} # How to sort a dict by value Python 3> sort = {key:value for key, value in sorted(mydict.items(), key=lambda kv: (kv[1], kv[0]))} print(sort) # How to sort a dict by key Python 3> sort = {key:mydict[key] for key in sorted(mydict.keys())} print(sort)