hex to rgb
0 likes • Nov 19, 2022
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import mathdef factorial(n):print(math.factorial(n))return (math.factorial(n))factorial(5)factorial(10)factorial(15)
def get_ldap_user(member_cn, user, passwrd):'''Get an LDAP user and return the SAMAccountName'''#---- Setting up the Connection#account used for binding - Avoid putting these in version controlbindDN = str(user) + "@unt.ad.unt.edu"bindPass = passwrd#set some tuneables for the LDAP library.ldap.set_option(ldap.OPT_X_TLS_REQUIRE_CERT, ldap.OPT_X_TLS_ALLOW)#ldap.set_option(ldap.OPT_X_TLS_CACERTFILE, CACERTFILE)conn = ldap.initialize('ldaps://unt.ad.unt.edu')conn.protocol_version = 3conn.set_option(ldap.OPT_REFERRALS, 0)#authenticate the connection so that you can make additional queriestry:result = conn.simple_bind_s(bindDN, bindPass)except ldap.INVALID_CREDENTIALS:result = "Invalid credentials for %s" % usersys.exit()#build query in the form of (uid=user)ldap_query = '(|(displayName=' + member_cn + ')(cn='+ member_cn + ')(name=' + member_cn + '))'ldap_info = conn.search_s('DC=unt,DC=ad,DC=unt,DC=edu', ldap.SCOPE_SUBTREE, filterstr=ldap_query)sAMAccountName = str(ldap_info[0][1]['sAMAccountName']).replace("[b'", "").replace("']","")return sAMAccountName
""" Currency Converter----------------------------------------"""import urllib.requestimport jsondef currency_converter(currency_from, currency_to, currency_input):yql_base_url = "https://query.yahooapis.com/v1/public/yql"yql_query = 'select%20*%20from%20yahoo.finance.xchange%20where%20pair' \'%20in%20("'+currency_from+currency_to+'")'yql_query_url = yql_base_url + "?q=" + yql_query + "&format=json&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys"try:yql_response = urllib.request.urlopen(yql_query_url)try:json_string = str(yql_response.read())json_string = json_string[2:json_string = json_string[:-1]print(json_string)yql_json = json.loads(json_string)last_rate = yql_json['query']['results']['rate']['Rate']currency_output = currency_input * float(last_rate)return currency_outputexcept (ValueError, KeyError, TypeError):print(yql_query_url)return "JSON format error"except IOError as e:print(str(e))currency_input = 1#currency codes : http://en.wikipedia.org/wiki/ISO_4217currency_from = "USD"currency_to = "TRY"rate = currency_converter(currency_from, currency_to, currency_input)print(rate)
# Python program for implementation of Bogo Sortimport random# Sorts array a[0..n-1] using Bogo sortdef bogoSort(a):n = len(a)while (is_sorted(a)== False):shuffle(a)# To check if array is sorted or notdef is_sorted(a):n = len(a)for i in range(0, n-1):if (a[i] > a[i+1] ):return Falsereturn True# To generate permuatation of the arraydef shuffle(a):n = len(a)for i in range (0,n):r = random.randint(0,n-1)a[i], a[r] = a[r], a[i]# Driver code to test abovea = [3, 2, 4, 1, 0, 5]bogoSort(a)print("Sorted array :")for i in range(len(a)):print ("%d" %a[i]),
from itertools import productV='∀'E='∃'def tt(f,n) :xss=product((0,1),repeat=n)print('function:',f.__name__)for xs in xss : print(*xs,':',int(f(*xs)))print('')# p \/ (q /\ r) = (p \/ q) /\ (p \/ r)def prob1(p,q,r) :x=p or (q and r)y= (p or q) and (p or r)return x==ytt(prob1,3)# p/\(q\/r)=(p/\q)\/(p/\r)def prob2(p,q,r) :x=p and ( q or r )y=(p and q) or (p and r)return x==ytt(prob2,3)#~(p/\q)=(~p\/~q)def prob3(p,q) :x=not (p and q)y=(not p) or (not q)return x==ytt(prob3,2)#(~(p\/q))=((~p)/\~q)def prob4(p, q):x = not(p or q)y = not p and not qreturn x == ytt(prob4, 2)#(p/\(p=>q)=>q)def prob5(p,q):x= p and ( not p or q)return not x or qtt(prob5,2)# (p=>q)=((p\/q)=q)def prob6(p,q) :x = (not p or q)y=((p or q) == q)return x==ytt(prob6,2)#((p=>q)=(p\/q))=qdef prob7(p,q):if ((not p or q)==(p or q))==q:return 1tt(prob7,2)#(p=>q)=((p/\q)=p)def prob8(p,q):if (not p or q)==((p and q)==p):return 1tt(prob8,2)#((p=>q)=(p/\q))=pdef prob9(p,q):if ((not p or q)==(p and q))==p:return '1'tt(prob9,2)#(p=>q)/\(q=>r)=>(p=>r)def prob10(p,q,r) :x = not ((not p or q) and (not q or r)) or (not p or r)return xtt(prob10, 3)# (p = q) /\ (q => r) => (p => r)#answer 1def prob11(p,q,r) :x = not((p is q) and (not q or r)) or (not p or r)return xtt(prob11, 3)#(p=q)/\(q=>r)=>(p=>r)#answer 2def prob11(p,q,r):x=(p==q) and (not q or r)y=not p or rreturn not x or ytt(prob11,3)#((p=>q)/\(q=r))=>(p=>r)def prob12(p,q,r):x=(not p or q) and ( q==r )y=not p or rreturn not x or ytt(prob12,3)#(p=>q)=>((p/\r)=>(q/\r))def prob13(p,q,r):x=not p or qy=(not(p and r) or ( q and r))return not x or ytt(prob13,3)#Question#2----------------------------------------#(p=>q)=>r=p=>(q=>r)def prob14(p,q,r):x=(not(not p or q) or r)y=(not p or (not q or r))return x==ytt(prob14,3)def prob15(p, q):x = not(p and q)y = not p and not qreturn x == ytt(prob15, 2)def prob16(p, q):x = not(p or q)y = not p or not qreturn x == ytt(prob16, 2)def prob17(p):x = py = not preturn x == ytt(prob17, 1)
# Python code to demonstrate# method to remove i'th character# Naive Method# Initializing Stringtest_str = "CodeCatch"# Printing original stringprint ("The original string is : " + test_str)# Removing char at pos 3# using loopnew_str = ""for i in range(len(test_str)):if i != 2:new_str = new_str + test_str[i]# Printing string after removalprint ("The string after removal of i'th character : " + new_str)