• Nov 19, 2022 •CodeCatch
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//JavaScript program to swap two variables //take input from the users let a = prompt('Enter the first variable: '); let b = prompt('Enter the second variable: '); // XOR operator a = a ^ b b = a ^ b a = a ^ b console.log(`The value of a after swapping: ${a}`); console.log(`The value of b after swapping: ${b}`);
const permutations = arr => { if (arr.length <= 2) return arr.length === 2 ? [arr, [arr[1], arr[0]]] : arr; return arr.reduce( (acc, item, i) => acc.concat( permutations([...arr.slice(0, i), ...arr.slice(i + 1)]).map(val => [ item, ...val, ]) ), [] ); }; permutations([1, 33, 5]); // [ [1, 33, 5], [1, 5, 33], [33, 1, 5], [33, 5, 1], [5, 1, 33], [5, 33, 1] ]
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//JavaScript program to swap two variables //take input from the users let a = prompt('Enter the first variable: '); let b = prompt('Enter the second variable: '); //using destructuring assignment [a, b] = [b, a]; console.log(`The value of a after swapping: ${a}`); console.log(`The value of b after swapping: ${b}`);
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const getURLParameters = url => (url.match(/([^?=&]+)(=([^&]*))/g) || []).reduce( (a, v) => ( (a[v.slice(0, v.indexOf('='))] = v.slice(v.indexOf('=') + 1)), a ), {} );
// There are n rings and each ring is either red, green, or blue. The rings are distributed across ten rods labeled from 0 to 9. // You are given a string rings of length 2n that describes the n rings that are placed onto the rods. Every two characters in rings forms a color-position pair that is used to describe each ring where: // The first character of the ith pair denotes the ith ring's color ('R', 'G', 'B'). // The second character of the ith pair denotes the rod that the ith ring is placed on ('0' to '9'). // For example, "R3G2B1" describes n == 3 rings: a red ring placed onto the rod labeled 3, a green ring placed onto the rod labeled 2, and a blue ring placed onto the rod labeled 1. // Return the number of rods that have all three colors of rings on them. let rings = "B0B6G0R6R0R6G9"; var countPoints = function(rings) { let sum = 0; // Always 10 Rods for (let i = 0; i < 10; i++) { if (rings.includes(`B${i}`) && rings.includes(`G${i}`) && rings.includes(`R${i}`)) { sum+=1; } } return sum; }; console.log(countPoints(rings));
• Jan 26, 2023 •AustinLeath
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function printHeap(heap, index, level) { if (index >= heap.length) { return; } console.log(" ".repeat(level) + heap[index]); printHeap(heap, 2 * index + 1, level + 1); printHeap(heap, 2 * index + 2, level + 1); } //You can call this function by passing in the heap array and the index of the root node, which is typically 0, and level = 0. let heap = [3, 8, 7, 15, 17, 30, 35, 2, 4, 5, 9]; printHeap(heap,0,0)