Reverse a string in Java
0 likes • Nov 20, 2022 • 1 view
JavaScript
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const levenshteinDistance = (s, t) => {if (!s.length) return t.length;if (!t.length) return s.length;const arr = [];for (let i = 0; i <= t.length; i++) {arr[i] = [i];for (let j = 1; j <= s.length; j++) {arr[i][j] =i === 0? j: Math.min(arr[i - 1][j] + 1,arr[i][j - 1] + 1,arr[i - 1][j - 1] + (s[j - 1] === t[i - 1] ? 0 : 1));}}return arr[t.length][s.length];};levenshteinDistance('duck', 'dark'); // 2
const deepMerge = (a, b, fn) =>[...new Set([...Object.keys(a), ...Object.keys(b)])].reduce((acc, key) => ({ ...acc, [key]: fn(key, a[key], b[key]) }),{});deepMerge({ a: true, b: { c: [1, 2, 3] } },{ a: false, b: { d: [1, 2, 3] } },(key, a, b) => (key === 'a' ? a && b : Object.assign({}, a, b)));// { a: false, b: { c: [ 1, 2, 3 ], d: [ 1, 2, 3 ] } }
var d = new Date();var d = new Date(milliseconds);var d = new Date(dateString);var d = new Date(year, month, day, hours, minutes, seconds, milliseconds);
class DoublyLinkedList {constructor() {this.nodes = [];}get size() {return this.nodes.length;}get head() {return this.size ? this.nodes[0] : null;}get tail() {return this.size ? this.nodes[this.size - 1] : null;}insertAt(index, value) {const previousNode = this.nodes[index - 1] || null;const nextNode = this.nodes[index] || null;const node = { value, next: nextNode, previous: previousNode };if (previousNode) previousNode.next = node;if (nextNode) nextNode.previous = node;this.nodes.splice(index, 0, node);}insertFirst(value) {this.insertAt(0, value);}insertLast(value) {this.insertAt(this.size, value);}getAt(index) {return this.nodes[index];}removeAt(index) {const previousNode = this.nodes[index - 1] || null;const nextNode = this.nodes[index + 1] || null;if (previousNode) previousNode.next = nextNode;if (nextNode) nextNode.previous = previousNode;return this.nodes.splice(index, 1);}clear() {this.nodes = [];}reverse() {this.nodes = this.nodes.reduce((acc, { value }) => {const nextNode = acc[0] || null;const node = { value, next: nextNode, previous: null };if (nextNode) nextNode.previous = node;return [node, ...acc];}, []);}*[Symbol.iterator]() {yield* this.nodes;}}const list = new DoublyLinkedList();list.insertFirst(1);list.insertFirst(2);list.insertFirst(3);list.insertLast(4);list.insertAt(3, 5);list.size; // 5list.head.value; // 3list.head.next.value; // 2list.tail.value; // 4list.tail.previous.value; // 5[...list.map(e => e.value)]; // [3, 2, 1, 5, 4]list.removeAt(1); // 2list.getAt(1).value; // 1list.head.next.value; // 1[...list.map(e => e.value)]; // [3, 1, 5, 4]list.reverse();[...list.map(e => e.value)]; // [4, 5, 1, 3]list.clear();list.size; // 0
// Time Complexity : O(N)// Space Complexity : O(1)var isMonotonic = function(nums) {let isMono = null;for(let i = 1; i < nums.length; i++) {if(isMono === null) {if(nums[i - 1] < nums[i]) isMono = 0;else if(nums[i - 1] > nums[i]) isMono = 1;continue;}if(nums[i - 1] < nums[i] && isMono !== 0) {return false;}else if(nums[i - 1] > nums[i] && isMono !== 1) {return false;}}return true;};let nums1 = [1,2,2,3]let nums2 = [6,5,4,4]let nums3 = [1,3,2]console.log(isMonotonic(nums1));console.log(isMonotonic(nums2));console.log(isMonotonic(nums3));
router.post("/", async (req, res) => {const { email, password } = req.body;try {if (!email) return res.status(400).json({ msg: "An email is required" });if (!password)return res.status(400).json({ msg: "A password is required" });const user = await User.findOne({ email }).select("_id password");if (!user) return res.status(400).json({ msg: "Invalid credentials" });const match = await bcrypt.compare(password, user.password);if (!match) return res.status(400).json({ msg: "Invalid credentials" });const accessToken = genAccessToken({ id: user._id });const refreshToken = genRefreshToken({ id: user._id });res.cookie("token", refreshToken, {expires: new Date(Date.now() + 604800),httpOnly: true,});res.json({ accessToken });} catch (err) {console.log(err.message);res.status(500).json({ msg: "Error logging in user" });}});