• Nov 18, 2022 •AustinLeath
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//use this with canvas file finder function NewTab(testing) { window.open(testing, "_blank"); } for(test in results) { var testing = 'https://unt.instructure.com/files/' + test + '/download'; NewTab(testing); }
• Nov 19, 2022 •CodeCatch
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function Welcome(props) { return <h1>Hello, {props.name}</h1>; } function App() { return ( <div> <Welcome name="Sara" /> <Welcome name="Cahal" /> <Welcome name="Edite" /> </div> ); } ReactDOM.render( <App />, document.getElementById('root') );
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class LinkedList { constructor() { this.nodes = []; } get size() { return this.nodes.length; } get head() { return this.size ? this.nodes[0] : null; } get tail() { return this.size ? this.nodes[this.size - 1] : null; } insertAt(index, value) { const previousNode = this.nodes[index - 1] || null; const nextNode = this.nodes[index] || null; const node = { value, next: nextNode }; if (previousNode) previousNode.next = node; this.nodes.splice(index, 0, node); } insertFirst(value) { this.insertAt(0, value); } insertLast(value) { this.insertAt(this.size, value); } getAt(index) { return this.nodes[index]; } removeAt(index) { const previousNode = this.nodes[index - 1]; const nextNode = this.nodes[index + 1] || null; if (previousNode) previousNode.next = nextNode; return this.nodes.splice(index, 1); } clear() { this.nodes = []; } reverse() { this.nodes = this.nodes.reduce( (acc, { value }) => [{ value, next: acc[0] || null }, ...acc], [] ); } *[Symbol.iterator]() { yield* this.nodes; } } const list = new LinkedList(); list.insertFirst(1); list.insertFirst(2); list.insertFirst(3); list.insertLast(4); list.insertAt(3, 5); list.size; // 5 list.head.value; // 3 list.head.next.value; // 2 list.tail.value; // 4 [...list.map(e => e.value)]; // [3, 2, 1, 5, 4] list.removeAt(1); // 2 list.getAt(1).value; // 1 list.head.next.value; // 1 [...list.map(e => e.value)]; // [3, 1, 5, 4] list.reverse(); [...list.map(e => e.value)]; // [4, 5, 1, 3] list.clear(); list.size; // 0
• Nov 8, 2023 •LeifMessinger
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function copyString(text){ async function navigatorClipboardCopy(text){ if(document.location.protocol != "https:"){ return false; } return new Promise((resolve, reject)=>{ navigator.clipboard.writeText(text).then(()=>{resolve(true);}, ()=>{resolve(false);}); }); } function domCopy(text){ if(!(document.execCommand)){ console.warn("They finally deprecated document.execCommand!"); } const input = document.createElement('textarea'); input.value = text; document.body.appendChild(input); input.select(); const success = document.execCommand('copy'); document.body.removeChild(input); return success; } function promptCopy(){ prompt("Copy failed. Might have ... somewhere. Check console.", text); console.log(text); } function done(){ alert("Copied to clipboard"); } navigatorClipboardCopy(text).catch(()=>{return false;}).then((success)=>{ if(success){ done(); }else{ if(domCopy(text)){ done(); }else{ promptCopy(); } } }); }
// There are n rings and each ring is either red, green, or blue. The rings are distributed across ten rods labeled from 0 to 9. // You are given a string rings of length 2n that describes the n rings that are placed onto the rods. Every two characters in rings forms a color-position pair that is used to describe each ring where: // The first character of the ith pair denotes the ith ring's color ('R', 'G', 'B'). // The second character of the ith pair denotes the rod that the ith ring is placed on ('0' to '9'). // For example, "R3G2B1" describes n == 3 rings: a red ring placed onto the rod labeled 3, a green ring placed onto the rod labeled 2, and a blue ring placed onto the rod labeled 1. // Return the number of rods that have all three colors of rings on them. let rings = "B0B6G0R6R0R6G9"; var countPoints = function(rings) { let sum = 0; // Always 10 Rods for (let i = 0; i < 10; i++) { if (rings.includes(`B${i}`) && rings.includes(`G${i}`) && rings.includes(`R${i}`)) { sum+=1; } } return sum; }; console.log(countPoints(rings));
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const quickSort = arr => { const a = [...arr]; if (a.length < 2) return a; const pivotIndex = Math.floor(arr.length / 2); const pivot = a[pivotIndex]; const [lo, hi] = a.reduce( (acc, val, i) => { if (val < pivot || (val === pivot && i != pivotIndex)) { acc[0].push(val); } else if (val > pivot) { acc[1].push(val); } return acc; }, [[], []] ); return [...quickSort(lo), pivot, ...quickSort(hi)]; }; quickSort([1, 6, 1, 5, 3, 2, 1, 4]); // [1, 1, 1, 2, 3, 4, 5, 6]