• Oct 15, 2022 •CodeCatch
1 like • 344 views
const express = require('express') const app = express() const port = 3000 app.get('/', (req, res) => { res.send('Hello World!') }) app.listen(port, () => { console.log(`Example app listening on port ${port}`) })
• Feb 6, 2021 •LeifMessinger
0 likes • 3 views
class SequentialQueue{ //if you want it to go backwards, too bad next(){ return this.i++; } constructor(start = 0){ this.i = start; } } const que = new SequentialQueue(0); for(let i = 0; i < 10; i++){ console.log(que.next()); }
• Nov 19, 2022 •CodeCatch
0 likes • 2 views
const gcd = (...arr) => { const _gcd = (x, y) => (!y ? x : gcd(y, x % y)); return [...arr].reduce((a, b) => _gcd(a, b)); }; gcd(8, 36); // 4 gcd(...[12, 8, 32]); // 4
0 likes • 5 views
const linearSearch = (arr, item) => { for (const i in arr) { if (arr[i] === item) return +i; } return -1; }; linearSearch([2, 9, 9], 9); // 1 linearSearch([2, 9, 9], 7); // -1
• Nov 20, 2022 •Helper
new StringBuilder(hi).reverse().toString()
const longestPalindrome = (s) => { if(s.length === 1) return s const odd = longestOddPalindrome(s) const even = longestEvenPalindrome(s) if(odd.length >= even.length) return odd if(even.length > odd.length) return even }; const longestOddPalindrome = (s) => { let longest = 0 let longestSubStr = "" for(let i = 1; i < s.length; i++) { let currentLongest = 1 let currentLongestSubStr = "" let left = i - 1 let right = i + 1 while(left >= 0 && right < s.length) { const leftLetter = s[left] const rightLetter = s[right] left-- right++ if(leftLetter === rightLetter) { currentLongest += 2 currentLongestSubStr = s.slice(left+1, right) } else break } if(currentLongest > longest) { if(currentLongestSubStr) longestSubStr = currentLongestSubStr else longestSubStr = s[i] longest = currentLongest } } return longestSubStr } const longestEvenPalindrome = (s) => { let longest = 0 let longestSubStr = "" for(let i = 0; i < s.length - 1; i++) { if(s[i] !== s[i+1]) continue; let currentLongest = 2 let currentLongestSubStr = "" let left = i - 1 let right = i + 2 while(left >= 0 && right < s.length) { const leftLetter = s[left] const rightLetter = s[right] left-- right++ if(leftLetter === rightLetter) { currentLongest += 2 currentLongestSubStr = s.slice(left+1, right) } else break } if(currentLongest > longest) { if(currentLongestSubStr) longestSubStr = currentLongestSubStr else longestSubStr = s[i] + s[i+1] longest = currentLongest } } return longestSubStr } console.log(longestPalindrome("babad"))