• Aug 30, 2024 •C S
1 like • 19 views
# Acronyms ## Computer Numerical Control (CNC) - Typicalldfdfsdffdafdasgfdgfgfdfdafdasfdafda
• Jan 26, 2023 •AustinLeath
0 likes • 7 views
function printHeap(heap, index, level) { if (index >= heap.length) { return; } console.log(" ".repeat(level) + heap[index]); printHeap(heap, 2 * index + 1, level + 1); printHeap(heap, 2 * index + 2, level + 1); } //You can call this function by passing in the heap array and the index of the root node, which is typically 0, and level = 0. let heap = [3, 8, 7, 15, 17, 30, 35, 2, 4, 5, 9]; printHeap(heap,0,0)
• Sep 13, 2023 •C S
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/** * @param {number[]} nums * @param {number} target * @return {number[]} */ var twoSum = function(nums, target) { for(let i = 0; i < nums.length; i++) { for(let j = 0; j < nums.length; j++) { if(nums[i] + nums[j] === target && i !== j) { return [i, j] } } } };
• Nov 19, 2022 •CodeCatch
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const longestPalindrome = (s) => { if(s.length === 1) return s const odd = longestOddPalindrome(s) const even = longestEvenPalindrome(s) if(odd.length >= even.length) return odd if(even.length > odd.length) return even }; const longestOddPalindrome = (s) => { let longest = 0 let longestSubStr = "" for(let i = 1; i < s.length; i++) { let currentLongest = 1 let currentLongestSubStr = "" let left = i - 1 let right = i + 1 while(left >= 0 && right < s.length) { const leftLetter = s[left] const rightLetter = s[right] left-- right++ if(leftLetter === rightLetter) { currentLongest += 2 currentLongestSubStr = s.slice(left+1, right) } else break } if(currentLongest > longest) { if(currentLongestSubStr) longestSubStr = currentLongestSubStr else longestSubStr = s[i] longest = currentLongest } } return longestSubStr } const longestEvenPalindrome = (s) => { let longest = 0 let longestSubStr = "" for(let i = 0; i < s.length - 1; i++) { if(s[i] !== s[i+1]) continue; let currentLongest = 2 let currentLongestSubStr = "" let left = i - 1 let right = i + 2 while(left >= 0 && right < s.length) { const leftLetter = s[left] const rightLetter = s[right] left-- right++ if(leftLetter === rightLetter) { currentLongest += 2 currentLongestSubStr = s.slice(left+1, right) } else break } if(currentLongest > longest) { if(currentLongestSubStr) longestSubStr = currentLongestSubStr else longestSubStr = s[i] + s[i+1] longest = currentLongest } } return longestSubStr } console.log(longestPalindrome("babad"))
• Mar 11, 2021 •C S
router.post("/", async (req, res) => { const { email, password } = req.body; try { if (!email) return res.status(400).json({ msg: "An email is required" }); if (!password) return res.status(400).json({ msg: "A password is required" }); const user = await User.findOne({ email }).select("_id password"); if (!user) return res.status(400).json({ msg: "Invalid credentials" }); const match = await bcrypt.compare(password, user.password); if (!match) return res.status(400).json({ msg: "Invalid credentials" }); const accessToken = genAccessToken({ id: user._id }); const refreshToken = genRefreshToken({ id: user._id }); res.cookie("token", refreshToken, { expires: new Date(Date.now() + 604800), httpOnly: true, }); res.json({ accessToken }); } catch (err) { console.log(err.message); res.status(500).json({ msg: "Error logging in user" }); } });
const getURLParameters = url => (url.match(/([^?=&]+)(=([^&]*))/g) || []).reduce( (a, v) => ( (a[v.slice(0, v.indexOf('='))] = v.slice(v.indexOf('=') + 1)), a ), {} );