• Jan 20, 2021 •Ntindle
0 likes • 4 views
print(“Hello World”)
• Nov 18, 2022 •AustinLeath
0 likes • 8 views
#question1.py def rose(n) : if n==0 : yield [] else : for k in range(0,n) : for l in rose(k) : for r in rose(n-1-k) : yield [l]+[r]+[r] def start(n) : for x in rose(n) : print(x) #basically I am printing x for each rose(n) file print("starting program: \n") start(2) # here is where I call the start function
• Jun 26, 2025 •AustinLeath
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def format_timestamp(timestamp_epoch): """ Convert epoch timestamp to formatted datetime string without using datetime package. Args: timestamp_epoch (int/float): Unix epoch timestamp (seconds since 1970-01-01 00:00:00 UTC) Returns: str: Formatted datetime string in 'YYYY-MM-DD HH:MM:SS' format """ # Constants for time calculations SECONDS_PER_DAY = 86400 SECONDS_PER_HOUR = 3600 SECONDS_PER_MINUTE = 60 # Handle negative timestamps and convert to integer timestamp = int(timestamp_epoch) # Calculate days since epoch and remaining seconds days_since_epoch = timestamp // SECONDS_PER_DAY remaining_seconds = timestamp % SECONDS_PER_DAY # Calculate hours, minutes, seconds hours = remaining_seconds // SECONDS_PER_HOUR remaining_seconds %= SECONDS_PER_HOUR minutes = remaining_seconds // SECONDS_PER_MINUTE seconds = remaining_seconds % SECONDS_PER_MINUTE # Calculate date (simplified, ignoring leap seconds) year = 1970 days = days_since_epoch while days >= 365: is_leap = (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0) days_in_year = 366 if is_leap else 365 if days >= days_in_year: days -= days_in_year year += 1 # Month lengths (non-leap year for simplicity, adjusted later for leap years) month_lengths = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0): month_lengths[1] = 29 month = 0 while days >= month_lengths[month]: days -= month_lengths[month] month += 1 # Convert to 1-based indexing for month and day month += 1 day = days + 1 # Format the output string return f"{year:04d}-{month:02d}-{day:02d} {hours:02d}:{minutes:02d}:{seconds:02d}" # Example timestamp (Unix epoch seconds) timestamp = 1697054700 formatted_date = format_timestamp(timestamp) print(formatted_date + " UTC") # Output: 2023-10-11 18:45:00
• Nov 19, 2022 •CodeCatch
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def check_prop(fn, prop): return lambda obj: fn(obj[prop]) check_age = check_prop(lambda x: x >= 18, 'age') user = {'name': 'Mark', 'age': 18} check_age(user) # True
• May 31, 2023 •CodeCatch
# Function to multiply two matrices def multiply_matrices(matrix1, matrix2): # Check if the matrices can be multiplied if len(matrix1[0]) != len(matrix2): print("Error: The number of columns in the first matrix must be equal to the number of rows in the second matrix.") return None # Create the result matrix filled with zeros result = [[0 for _ in range(len(matrix2[0]))] for _ in range(len(matrix1))] # Perform matrix multiplication for i in range(len(matrix1)): for j in range(len(matrix2[0])): for k in range(len(matrix2)): result[i][j] += matrix1[i][k] * matrix2[k][j] return result # Example matrices matrix1 = [[1, 2, 3], [4, 5, 6], [7, 8, 9]] matrix2 = [[10, 11], [12, 13], [14, 15]] # Multiply the matrices result_matrix = multiply_matrices(matrix1, matrix2) # Display the result if result_matrix is not None: print("Result:") for row in result_matrix: print(row)
• Feb 26, 2023 •wabdelh
#You are given a two-digit integer n. Return the sum of its digits. #Example #For n = 29 the output should be solution (n) = 11 def solution(n): return (n//10 + n%10)