• Mar 26, 2023 •AustinLeath
0 likes • 1 view
import os # Get the current directory current_dir = os.getcwd() # Loop through each file in the current directory for filename in os.listdir(current_dir): # Check if the file name starts with a number followed by a period and a space if filename[0].isdigit() and filename[1] == '.' and filename[2] == ' ': # Remove the number, period, and space from the file name new_filename = filename[3:] # Rename the file os.rename(os.path.join(current_dir, filename), os.path.join(current_dir, new_filename))
• Feb 26, 2023 •wabdelh
#You are given a two-digit integer n. Return the sum of its digits. #Example #For n = 29 the output should be solution (n) = 11 def solution(n): return (n//10 + n%10)
• May 31, 2023 •CodeCatch
def generate_pascals_triangle(num_rows): triangle = [] for row in range(num_rows): # Initialize the row with 1 current_row = [1] # Calculate the values for the current row if row > 0: previous_row = triangle[row - 1] for i in range(len(previous_row) - 1): current_row.append(previous_row[i] + previous_row[i + 1]) # Append 1 at the end of the row current_row.append(1) # Add the current row to the triangle triangle.append(current_row) return triangle def display_pascals_triangle(triangle): for row in triangle: for number in row: print(number, end=" ") print() # Prompt the user for the number of rows num_rows = int(input("Enter the number of rows for Pascal's Triangle: ")) # Generate Pascal's Triangle pascals_triangle = generate_pascals_triangle(num_rows) # Display Pascal's Triangle display_pascals_triangle(pascals_triangle)
• Nov 19, 2022 •CodeCatch
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from math import pi def rads_to_degrees(rad): return (rad * 180.0) / pi rads_to_degrees(pi / 2) # 90.0
• Sep 6, 2020 •C S
def Fibonacci(n): if n<0: print("Incorrect input") # First Fibonacci number is 0 elif n==1: return 0 # Second Fibonacci number is 1 elif n==2: return 1 else: return Fibonacci(n-1)+Fibonacci(n-2) # Driver Program print(Fibonacci(9))
def max_n(lst, n = 1): return sorted(lst, reverse = True)[:n] max_n([1, 2, 3]) # [3] max_n([1, 2, 3], 2) # [3, 2]