• Mar 11, 2021 •C S
1 like • 2 views
if (process.env.NODE_ENV === "production") { app.use(express.static("client/build")); app.get("*", (req, res) => { res.sendFile(path.resolve(__dirname, "client", "build", "index.html")); }); }
• Mar 10, 2022 •LeifMessinger
0 likes • 1 view
//Use at https://mee6.xyz/leaderboard/732262089447702588 //Higher the spammy stat, the more spammy that person is. //This is because mee doesn't give experience to people who post more comments in a minute. function statBlock(title, value){ let elm = document.createElement("div"); elm.className = "leaderboardPlayerStatBlock"; let titleElm = document.createElement("div"); titleElm.className = "leaderboardPlayerStatName"; titleElm.textContent = title; let valueElm = document.createElement("div"); valueElm.className = "leaderboardPlayerStatValue"; valueElm.textContent = value; elm.appendChild(titleElm); elm.appendChild(valueElm); elm.remove = function(){ this.parentElement.removeChild(this); } return elm; } for(let player of Array.from(document.getElementsByClassName("leaderboardPlayer"))){ if(player.spamminess) player.spamminess.remove(); let messages = null; let experience = null; const statBlockArray = Array.from(player.querySelectorAll(".leaderboardPlayerStatBlock")); for(let statBlock of statBlockArray){ const statName = statBlock.querySelector(".leaderboardPlayerStatName").textContent; const text = statBlock.querySelector(".leaderboardPlayerStatValue").textContent; const number = ((text.includes("k"))? (text.replace("k","") * 1000.0) : +(text)); if(statName.includes("MESSAGES")){ messages = number; }else if(statName.includes("EXPERIENCE")){ experience = number; } } const stats = player.querySelector(".leaderboardPlayerStats"); const messagesElement = stats.firstChild; const spamminess = ((messages/experience)*2000.0).toFixed(2); player.spamminess = stats.insertBefore(statBlock("SPAMMINESS", spamminess), messagesElement); }
• Jan 25, 2023 •C S
0 likes • 13 views
// Vanilla JS Solution: var app = document.getElementById('app'); var typewriter = new Typewriter(app, { loop: true }); typewriter .typeString("I'm John and I'm a super cool web developer") .pauseFor(3000) .deleteChars(13) // "web developer" = 13 characters .typeString("person to talk with!") // Will display "I'm John and I'm a super cool person to talk with!" .start(); // React Solution: import Typewriter from 'typewriter-effect'; <Typewriter options={{ loop: true }} onInit={typewriter => { typewriter .typeString("I'm John and I'm a super cool web developer") .pauseFor(3000) .deleteChars(13) // "web developer" = 13 characters .typeString("person to talk with!") // Will display "I'm John and I'm a super cool person to talk with!" .start(); }} />
• Nov 19, 2022 •CodeCatch
// There are n rings and each ring is either red, green, or blue. The rings are distributed across ten rods labeled from 0 to 9. // You are given a string rings of length 2n that describes the n rings that are placed onto the rods. Every two characters in rings forms a color-position pair that is used to describe each ring where: // The first character of the ith pair denotes the ith ring's color ('R', 'G', 'B'). // The second character of the ith pair denotes the rod that the ith ring is placed on ('0' to '9'). // For example, "R3G2B1" describes n == 3 rings: a red ring placed onto the rod labeled 3, a green ring placed onto the rod labeled 2, and a blue ring placed onto the rod labeled 1. // Return the number of rods that have all three colors of rings on them. let rings = "B0B6G0R6R0R6G9"; var countPoints = function(rings) { let sum = 0; // Always 10 Rods for (let i = 0; i < 10; i++) { if (rings.includes(`B${i}`) && rings.includes(`G${i}`) && rings.includes(`R${i}`)) { sum+=1; } } return sum; }; console.log(countPoints(rings));
• Oct 15, 2022 •CodeCatch
1 like • 324 views
const express = require('express') const app = express() const port = 3000 app.get('/', (req, res) => { res.send('Hello World!') }) app.listen(port, () => { console.log(`Example app listening on port ${port}`) })
0 likes • 2 views
const union = (...arr) => [...new Set(arr.flat())]; // Example union([1, 2], [2, 3], [3]); // [1, 2, 3]