• Nov 19, 2022 •CodeCatch
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const geometricProgression = (end, start = 1, step = 2) => Array.from({ length: Math.floor(Math.log(end / start) / Math.log(step)) + 1, }).map((_, i) => start * step ** i); geometricProgression(256); // [1, 2, 4, 8, 16, 32, 64, 128, 256] geometricProgression(256, 3); // [3, 6, 12, 24, 48, 96, 192] geometricProgression(256, 1, 4); // [1, 4, 16, 64, 256]
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const formatDuration = ms => { if (ms < 0) ms = -ms; const time = { day: Math.floor(ms / 86400000), hour: Math.floor(ms / 3600000) % 24, minute: Math.floor(ms / 60000) % 60, second: Math.floor(ms / 1000) % 60, millisecond: Math.floor(ms) % 1000 }; return Object.entries(time) .filter(val => val[1] !== 0) .map(([key, val]) => `${val} ${key}${val !== 1 ? 's' : ''}`) .join(', '); }; formatDuration(1001); // '1 second, 1 millisecond' formatDuration(34325055574); // '397 days, 6 hours, 44 minutes, 15 seconds, 574 milliseconds'
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const levenshteinDistance = (s, t) => { if (!s.length) return t.length; if (!t.length) return s.length; const arr = []; for (let i = 0; i <= t.length; i++) { arr[i] = [i]; for (let j = 1; j <= s.length; j++) { arr[i][j] = i === 0 ? j : Math.min( arr[i - 1][j] + 1, arr[i][j - 1] + 1, arr[i - 1][j - 1] + (s[j - 1] === t[i - 1] ? 0 : 1) ); } } return arr[t.length][s.length]; }; levenshteinDistance('duck', 'dark'); // 2
• Jan 26, 2023 •AustinLeath
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function printHeap(heap, index, level) { if (index >= heap.length) { return; } console.log(" ".repeat(level) + heap[index]); printHeap(heap, 2 * index + 1, level + 1); printHeap(heap, 2 * index + 2, level + 1); } //You can call this function by passing in the heap array and the index of the root node, which is typically 0, and level = 0. let heap = [3, 8, 7, 15, 17, 30, 35, 2, 4, 5, 9]; printHeap(heap,0,0)
• Feb 11, 2021 •LeifMessinger
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function spam(times = 1,log = true){ for(let i = 0; i < times; i++){ $.get("backend-search.php", {term: (" "+Date.now())}).done(function(data){ if(log) console.log(data); }); } } spam(100000);
const binomialCoefficient = (n, k) => { if (Number.isNaN(n) || Number.isNaN(k)) return NaN; if (k < 0 || k > n) return 0; if (k === 0 || k === n) return 1; if (k === 1 || k === n - 1) return n; if (n - k < k) k = n - k; let res = n; for (let j = 2; j <= k; j++) res *= (n - j + 1) / j; return Math.round(res); }; binomialCoefficient(8, 2); // 28