• Oct 9, 2023 •Helper
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import React, { useState, useEffect } from 'react'; import Link from 'next/link'; export default function CookieBanner() { // Initialize with a default value (false if not previously set in localStorage) const [cookieConsent, setCookieConsent] = useState(() => localStorage.getItem('cookieConsent') === 'true' ? true : false ); useEffect(() => { const newCookieConsent = cookieConsent ? 'granted' : 'denied'; window.gtag('consent', 'update', { analytics_storage: newCookieConsent }); localStorage.setItem('cookieConsent', String(cookieConsent)); }, [cookieConsent]); return !cookieConsent && ( <div> <div> <p> We use cookies to enhance the user experience.{' '} <Link href='/privacy/'>View privacy policy</Link> </p> </div> <div> <button type="button" onClick={() => setCookieConsent(false)}>Decline</button> <button type="button" onClick={() => setCookieConsent(true)}>Allow</button> </div> </div> ) }
• Nov 19, 2022 •CodeCatch
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// There are n rings and each ring is either red, green, or blue. The rings are distributed across ten rods labeled from 0 to 9. // You are given a string rings of length 2n that describes the n rings that are placed onto the rods. Every two characters in rings forms a color-position pair that is used to describe each ring where: // The first character of the ith pair denotes the ith ring's color ('R', 'G', 'B'). // The second character of the ith pair denotes the rod that the ith ring is placed on ('0' to '9'). // For example, "R3G2B1" describes n == 3 rings: a red ring placed onto the rod labeled 3, a green ring placed onto the rod labeled 2, and a blue ring placed onto the rod labeled 1. // Return the number of rods that have all three colors of rings on them. let rings = "B0B6G0R6R0R6G9"; var countPoints = function(rings) { let sum = 0; // Always 10 Rods for (let i = 0; i < 10; i++) { if (rings.includes(`B${i}`) && rings.includes(`G${i}`) && rings.includes(`R${i}`)) { sum+=1; } } return sum; }; console.log(countPoints(rings));
• Nov 16, 2023 •LeifMessinger
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function filePath(file){ let folders = file.getParents(); const parents = []; function makePathString(folderArray){ let path = ""; folderArray.forEach((folder)=>{ path += "/" + folder.getName(); }); return path; } while (folders.hasNext()) { const folder = folders.next(); //This should hopefully remove that folder from the iterator parents.unshift(folder); } return makePathString(parents); } function myFunction() { const myEmail = Session.getEffectiveUser().getEmail(); Logger.log("My email is " + myEmail); // Log the name of every file in the user's Drive. var fileIterator = DriveApp.getFiles(); const files = []; //List of [File, size] entries const filesMaxSize = 10; while (fileIterator.hasNext()) { var file = fileIterator.next(); const owner = file.getOwner(); //Only files I own if((!(owner)) || (!(owner.getEmail)) || owner.getEmail() != myEmail){ continue; } const entry = [file, file.getSize()]; function slideUp(arr, index){ //Let's keep sliding it up so we don't have to sort it at the end. for(let i = index; i > 0; --i){ //Stops at 1 const nextFile = arr[i-1]; if(nextFile[1] > entry[1]){ break; }else{ //Swap with the next file to slide the file up const temp = arr[i]; arr[i] = arr[i - 1]; arr[i - 1] = temp; } } } if(files.length < filesMaxSize){ files.push(entry); slideUp(files, files.length - 1); }else{ if(entry[1] > files[files.length - 1][1]){ //If it's bigger than the smallest file in the list. files[files.length - 1] = entry; //Replace the smallest file slideUp(files, files.length - 1); //Slide it up } } } for(let i = 0; i < filesMaxSize; ++i){ const file = files[i][0]; const size = files[i][1]; Logger.log(size + "\t" + filePath(file) + "/" + file.getName() + "\t" + file.getOwner().getName()); } }
//JavaScript program to swap two variables //take input from the users let a = prompt('Enter the first variable: '); let b = prompt('Enter the second variable: '); // XOR operator a = a ^ b b = a ^ b a = a ^ b console.log(`The value of a after swapping: ${a}`); console.log(`The value of b after swapping: ${b}`);
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const union = (...arr) => [...new Set(arr.flat())]; // Example union([1, 2], [2, 3], [3]); // [1, 2, 3]
• Jan 26, 2023 •AustinLeath
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function printHeap(heap, index, level) { if (index >= heap.length) { return; } console.log(" ".repeat(level) + heap[index]); printHeap(heap, 2 * index + 1, level + 1); printHeap(heap, 2 * index + 2, level + 1); } //You can call this function by passing in the heap array and the index of the root node, which is typically 0, and level = 0. let heap = [3, 8, 7, 15, 17, 30, 35, 2, 4, 5, 9]; printHeap(heap,0,0)