const countSubstrings = (str, searchValue) => {
  let count = 0,
    i = 0;
  while (true) {
    const r = str.indexOf(searchValue, i);
    if (r !== -1) [count, i] = [count + 1, r + 1];
    else return count;
  }
};

countSubstrings('tiktok tok tok tik tok tik', 'tik'); // 3
countSubstrings('tutut tut tut', 'tut'); // 4

// There are n rings and each ring is either red, green, or blue. The rings are distributed across ten rods labeled from 0 to 9.

// You are given a string rings of length 2n that describes the n rings that are placed onto the rods. Every two characters in rings forms a color-position pair that is used to describe each ring where:

// The first character of the ith pair denotes the ith ring's color ('R', 'G', 'B').
// The second character of the ith pair denotes the rod that the ith ring is placed on ('0' to '9').
// For example, "R3G2B1" describes n == 3 rings: a red ring placed onto the rod labeled 3, a green ring placed onto the rod labeled 2, and a blue ring placed onto the rod labeled 1.

// Return the number of rods that have all three colors of rings on them.


let rings = "B0B6G0R6R0R6G9";
var countPoints = function(rings) {
    
    let sum = 0;
    
	// Always 10 Rods
    for (let i = 0; i < 10; i++) {
        if (rings.includes(`B${i}`) && rings.includes(`G${i}`) && rings.includes(`R${i}`)) {
            sum+=1;
        }
    }
    
    return sum;
    
};

console.log(countPoints(rings));

const getURLParameters = url =>
(url.match(/([^?=&]+)(=([^&]*))/g) || []).reduce(
    (a, v) => (
      (a[v.slice(0, v.indexOf('='))] = v.slice(v.indexOf('=') + 1)), a
    ),
    {}
);

// Get the text that the user has selected
const getSelectedText = () => window.getSelection().toString();
getSelectedText();

const getSearchTerm = delimiter => {
	let searchTerm = "";

	for (let i = 1; i < commands.length - 1; i++)
	searchTerm = searchTerm + commands[i] + delimiter;

	searchTerm += commands[commands.length - 1];

	return searchTerm;
	};

//Use at https://mee6.xyz/leaderboard/732262089447702588
//Higher the spammy stat, the more spammy that person is.
//This is because mee doesn't give experience to people who post more comments in a minute.
function statBlock(title, value){
	let elm = document.createElement("div");
	elm.className = "leaderboardPlayerStatBlock";
	let titleElm = document.createElement("div");
	titleElm.className = "leaderboardPlayerStatName";
	titleElm.textContent = title;
	let valueElm = document.createElement("div");
	valueElm.className = "leaderboardPlayerStatValue";
	valueElm.textContent = value;
	elm.appendChild(titleElm);
	elm.appendChild(valueElm);
	elm.remove = function(){
	this.parentElement.removeChild(this);
	}
	return elm;
}
for(let player of Array.from(document.getElementsByClassName("leaderboardPlayer"))){
	if(player.spamminess) player.spamminess.remove();
	let messages = null;
	let experience = null;
	const statBlockArray = Array.from(player.querySelectorAll(".leaderboardPlayerStatBlock"));
	for(let statBlock of statBlockArray){
	const statName = statBlock.querySelector(".leaderboardPlayerStatName").textContent;
	const text = statBlock.querySelector(".leaderboardPlayerStatValue").textContent;
	const number = ((text.includes("k"))? (text.replace("k","") * 1000.0) : +(text));
	if(statName.includes("MESSAGES")){
	messages = number;
	}else if(statName.includes("EXPERIENCE")){
	experience = number;
	}
	}
	const stats = player.querySelector(".leaderboardPlayerStats");
	const messagesElement = stats.firstChild;

	const spamminess = ((messages/experience)*2000.0).toFixed(2);
	
	player.spamminess = stats.insertBefore(statBlock("SPAMMINESS", spamminess), messagesElement);
}