• Nov 19, 2022 •CodeCatch
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// There are n rings and each ring is either red, green, or blue. The rings are distributed across ten rods labeled from 0 to 9. // You are given a string rings of length 2n that describes the n rings that are placed onto the rods. Every two characters in rings forms a color-position pair that is used to describe each ring where: // The first character of the ith pair denotes the ith ring's color ('R', 'G', 'B'). // The second character of the ith pair denotes the rod that the ith ring is placed on ('0' to '9'). // For example, "R3G2B1" describes n == 3 rings: a red ring placed onto the rod labeled 3, a green ring placed onto the rod labeled 2, and a blue ring placed onto the rod labeled 1. // Return the number of rods that have all three colors of rings on them. let rings = "B0B6G0R6R0R6G9"; var countPoints = function(rings) { let sum = 0; // Always 10 Rods for (let i = 0; i < 10; i++) { if (rings.includes(`B${i}`) && rings.includes(`G${i}`) && rings.includes(`R${i}`)) { sum+=1; } } return sum; }; console.log(countPoints(rings));
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const heapsort = arr => { const a = [...arr]; let l = a.length; const heapify = (a, i) => { const left = 2 * i + 1; const right = 2 * i + 2; let max = i; if (left < l && a[left] > a[max]) max = left; if (right < l && a[right] > a[max]) max = right; if (max !== i) { [a[max], a[i]] = [a[i], a[max]]; heapify(a, max); } }; for (let i = Math.floor(l / 2); i >= 0; i -= 1) heapify(a, i); for (i = a.length - 1; i > 0; i--) { [a[0], a[i]] = [a[i], a[0]]; l--; heapify(a, 0); } return a; }; heapsort([6, 3, 4, 1]); // [1, 3, 4, 6]
class LinkedList { constructor() { this.nodes = []; } get size() { return this.nodes.length; } get head() { return this.size ? this.nodes[0] : null; } get tail() { return this.size ? this.nodes[this.size - 1] : null; } insertAt(index, value) { const previousNode = this.nodes[index - 1] || null; const nextNode = this.nodes[index] || null; const node = { value, next: nextNode }; if (previousNode) previousNode.next = node; this.nodes.splice(index, 0, node); } insertFirst(value) { this.insertAt(0, value); } insertLast(value) { this.insertAt(this.size, value); } getAt(index) { return this.nodes[index]; } removeAt(index) { const previousNode = this.nodes[index - 1]; const nextNode = this.nodes[index + 1] || null; if (previousNode) previousNode.next = nextNode; return this.nodes.splice(index, 1); } clear() { this.nodes = []; } reverse() { this.nodes = this.nodes.reduce( (acc, { value }) => [{ value, next: acc[0] || null }, ...acc], [] ); } *[Symbol.iterator]() { yield* this.nodes; } } const list = new LinkedList(); list.insertFirst(1); list.insertFirst(2); list.insertFirst(3); list.insertLast(4); list.insertAt(3, 5); list.size; // 5 list.head.value; // 3 list.head.next.value; // 2 list.tail.value; // 4 [...list.map(e => e.value)]; // [3, 2, 1, 5, 4] list.removeAt(1); // 2 list.getAt(1).value; // 1 list.head.next.value; // 1 [...list.map(e => e.value)]; // [3, 1, 5, 4] list.reverse(); [...list.map(e => e.value)]; // [4, 5, 1, 3] list.clear(); list.size; // 0
• Mar 11, 2021 •C S
1 like • 6 views
if (process.env.NODE_ENV === "production") { app.use(express.static("client/build")); app.get("*", (req, res) => { res.sendFile(path.resolve(__dirname, "client", "build", "index.html")); }); }
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const arithmeticProgression = (n, lim) => Array.from({ length: Math.ceil(lim / n) }, (_, i) => (i + 1) * n ); arithmeticProgression(5, 25); // [5, 10, 15, 20, 25]
//JavaScript program to swap two variables //take input from the users let a = prompt('Enter the first variable: '); let b = prompt('Enter the second variable: '); //using destructuring assignment [a, b] = [b, a]; console.log(`The value of a after swapping: ${a}`); console.log(`The value of b after swapping: ${b}`);