• Nov 19, 2022 •CodeCatch
0 likes • 3 views
const powerset = arr => arr.reduce((a, v) => a.concat(a.map(r => r.concat(v))), [[]]); powerset([1, 2]); // [[], [1], [2], [1, 2]]
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// Time Complexity : O(N) // Space Complexity : O(1) var isMonotonic = function(nums) { let isMono = null; for(let i = 1; i < nums.length; i++) { if(isMono === null) { if(nums[i - 1] < nums[i]) isMono = 0; else if(nums[i - 1] > nums[i]) isMono = 1; continue; } if(nums[i - 1] < nums[i] && isMono !== 0) { return false; } else if(nums[i - 1] > nums[i] && isMono !== 1) { return false; } } return true; }; let nums1 = [1,2,2,3] let nums2 = [6,5,4,4] let nums3 = [1,3,2] console.log(isMonotonic(nums1)); console.log(isMonotonic(nums2)); console.log(isMonotonic(nums3));
• Nov 18, 2022 •AustinLeath
//use this with canvas file finder function NewTab(testing) { window.open(testing, "_blank"); } for(test in results) { var testing = 'https://unt.instructure.com/files/' + test + '/download'; NewTab(testing); }
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const bucketSort = (arr, size = 5) => { const min = Math.min(...arr); const max = Math.max(...arr); const buckets = Array.from( { length: Math.floor((max - min) / size) + 1 }, () => [] ); arr.forEach(val => { buckets[Math.floor((val - min) / size)].push(val); }); return buckets.reduce((acc, b) => [...acc, ...b.sort((a, b) => a - b)], []); }; bucketSort([6, 3, 4, 1]); // [1, 3, 4, 6]
• Oct 15, 2022 •CodeCatch
2 likes • 10 views
var invertTree = function(root) { const reverseNode = node => { if (node == null) { return null } reverseNode(node.left); reverseNode(node.right); let holdLeft = node.left; node.left = node.right; node.right = holdLeft; return node; } return reverseNode(root); };
//JavaScript program to swap two variables //take input from the users let a = prompt('Enter the first variable: '); let b = prompt('Enter the second variable: '); //using destructuring assignment [a, b] = [b, a]; console.log(`The value of a after swapping: ${a}`); console.log(`The value of b after swapping: ${b}`);