Factorial of N
0 likes • Nov 19, 2022
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import subprocess #for the praat callsimport os #for ffmpeg and the pause call at the end#Even if we wanted all videos being rendered asynchronously, we couldn't see progress or errorsimport glob #for the ambiguous filesimport tempfileaudioFileDirectory = 'Audio Files'timeList = {}fileList = glob.glob(audioFileDirectory + '\\*.wav')pipeList = {}for fileName in fileList:arglist = ['Praat.exe', '--run', 'crosscorrelateMatch.praat', 'zeussound.wav', fileName, "0" , "300"]print(' '.join(arglist))pipe = subprocess.Popen(arglist, stdout=subprocess.PIPE)pipeList[fileName[len(audioFileDirectory)+1:-4]] = pipe #+1 because of back slash, -4 because .wav#for fileName, pipe in pipeList.items():# text = pipe.communicate()[0].decode('utf-8')# timeList[fileName] = float(text[::2])for fileName, pipe in pipeList.items():if float(pipe.communicate()[0].decode('utf-8')[::2]) > .0003: #.000166 is not a match, and .00073 is a perfect match. .00053 is a tested matcharglist = ['Praat.exe', '--run', 'crosscorrelate.praat', 'zeussound.wav', audioFileDirectory + '\\' + fileName + '.wav', "0" , "300"]print(' '.join(arglist))text = subprocess.Popen(arglist, stdout=subprocess.PIPE).communicate()[0].decode('utf-8')timeList[fileName] = float(text[::2])clipLength = 10for fileName, time in timeList.items():arglist = ['ffmpeg', '-i', '"'+fileName+'.mp4"', '-ss', str(time-clipLength), '-t', str(clipLength*2), '-acodec', 'copy' , '-vcodec', 'copy', '"ZEUS'+ fileName + '.mp4"']print(' '.join(arglist))os.system(' '.join(arglist))tempFile = tempfile.NamedTemporaryFile(delete=False)for fileName in glob.glob('ZEUS*.mp4'):tempFile.write(("file '" + os.path.realpath(fileName) + "'\n").encode());tempFile.seek(0)print(tempFile.read())tempFile.close()arglist = ['ffmpeg', '-safe', '0', '-f', 'concat', '-i', '"'+tempFile.name+'"', '-c', 'copy', 'ZeusMontage.mp4']print(' '.join(arglist))os.system(' '.join(arglist))os.unlink(tempFile.name) #Delete the temp file#print(timeList)os.system('PAUSE')
# Python program for Bitonic Sort. Note that this program# works only when size of input is a power of 2.# The parameter dir indicates the sorting direction, ASCENDING# or DESCENDING; if (a[i] > a[j]) agrees with the direction,# then a[i] and a[j] are interchanged.*/def compAndSwap(a, i, j, dire):if (dire==1 and a[i] > a[j]) or (dire==0 and a[i] > a[j]):a[i],a[j] = a[j],a[i]# It recursively sorts a bitonic sequence in ascending order,# if dir = 1, and in descending order otherwise (means dir=0).# The sequence to be sorted starts at index position low,# the parameter cnt is the number of elements to be sorted.def bitonicMerge(a, low, cnt, dire):if cnt > 1:k = cnt/2for i in range(low , low+k):compAndSwap(a, i, i+k, dire)bitonicMerge(a, low, k, dire)bitonicMerge(a, low+k, k, dire)# This funcion first produces a bitonic sequence by recursively# sorting its two halves in opposite sorting orders, and then# calls bitonicMerge to make them in the same orderdef bitonicSort(a, low, cnt,dire):if cnt > 1:k = cnt/2bitonicSort(a, low, k, 1)bitonicSort(a, low+k, k, 0)bitonicMerge(a, low, cnt, dire)# Caller of bitonicSort for sorting the entire array of length N# in ASCENDING orderdef sort(a,N, up):bitonicSort(a,0, N, up)# Driver code to test abovea = [3, 7, 4, 8, 6, 2, 1, 5]n = len(a)up = 1sort(a, n, up)print ("\n\nSorted array is")for i in range(n):print("%d" %a[i]),
list_1 = [1,2,3,4,5,6,7,8,9]cubed = map(lambda x: pow(x,3), list_1)print(list(cubed))#Results#[1, 8, 27, 64, 125, 216, 343, 512, 729]
""" Binary Search Algorithm----------------------------------------"""#iterative implementation of binary search in Pythondef binary_search(a_list, item):"""Performs iterative binary search to find the position of an integer in a given, sorted, list.a_list -- sorted list of integersitem -- integer you are searching for the position of"""first = 0last = len(a_list) - 1while first <= last:i = (first + last) / 2if a_list[i] == item:return ' found at position '.format(item=item, i=i)elif a_list[i] > item:last = i - 1elif a_list[i] < item:first = i + 1else:return ' not found in the list'.format(item=item)#recursive implementation of binary search in Pythondef binary_search_recursive(a_list, item):"""Performs recursive binary search of an integer in a given, sorted, list.a_list -- sorted list of integersitem -- integer you are searching for the position of"""first = 0last = len(a_list) - 1if len(a_list) == 0:return ' was not found in the list'.format(item=item)else:i = (first + last) // 2if item == a_list[i]:return ' found'.format(item=item)else:if a_list[i] < item:return binary_search_recursive(a_list[i+1:], item)else:return binary_search_recursive(a_list[:i], item)
# Python program for Plotting Fibonacci# spiral fractal using Turtleimport turtleimport mathdef fiboPlot(n):a = 0b = 1square_a = asquare_b = b# Setting the colour of the plotting pen to bluex.pencolor("blue")# Drawing the first squarex.forward(b * factor)x.left(90)x.forward(b * factor)x.left(90)x.forward(b * factor)x.left(90)x.forward(b * factor)# Proceeding in the Fibonacci Seriestemp = square_bsquare_b = square_b + square_asquare_a = temp# Drawing the rest of the squaresfor i in range(1, n):x.backward(square_a * factor)x.right(90)x.forward(square_b * factor)x.left(90)x.forward(square_b * factor)x.left(90)x.forward(square_b * factor)# Proceeding in the Fibonacci Seriestemp = square_bsquare_b = square_b + square_asquare_a = temp# Bringing the pen to starting point of the spiral plotx.penup()x.setposition(factor, 0)x.seth(0)x.pendown()# Setting the colour of the plotting pen to redx.pencolor("red")# Fibonacci Spiral Plotx.left(90)for i in range(n):print(b)fdwd = math.pi * b * factor / 2fdwd /= 90for j in range(90):x.forward(fdwd)x.left(1)temp = aa = bb = temp + b# Here 'factor' signifies the multiplicative# factor which expands or shrinks the scale# of the plot by a certain factor.factor = 1# Taking Input for the number of# Iterations our Algorithm will runn = int(input('Enter the number of iterations (must be > 1): '))# Plotting the Fibonacci Spiral Fractal# and printing the corresponding Fibonacci Numberif n > 0:print("Fibonacci series for", n, "elements :")x = turtle.Turtle()x.speed(100)fiboPlot(n)turtle.done()else:print("Number of iterations must be > 0")
def get_ldap_user(member_cn, user, passwrd):'''Get an LDAP user and return the SAMAccountName'''#---- Setting up the Connection#account used for binding - Avoid putting these in version controlbindDN = str(user) + "@unt.ad.unt.edu"bindPass = passwrd#set some tuneables for the LDAP library.ldap.set_option(ldap.OPT_X_TLS_REQUIRE_CERT, ldap.OPT_X_TLS_ALLOW)#ldap.set_option(ldap.OPT_X_TLS_CACERTFILE, CACERTFILE)conn = ldap.initialize('ldaps://unt.ad.unt.edu')conn.protocol_version = 3conn.set_option(ldap.OPT_REFERRALS, 0)#authenticate the connection so that you can make additional queriestry:result = conn.simple_bind_s(bindDN, bindPass)except ldap.INVALID_CREDENTIALS:result = "Invalid credentials for %s" % usersys.exit()#build query in the form of (uid=user)ldap_query = '(|(displayName=' + member_cn + ')(cn='+ member_cn + ')(name=' + member_cn + '))'ldap_info = conn.search_s('DC=unt,DC=ad,DC=unt,DC=edu', ldap.SCOPE_SUBTREE, filterstr=ldap_query)sAMAccountName = str(ldap_info[0][1]['sAMAccountName']).replace("[b'", "").replace("']","")return sAMAccountName