• Oct 15, 2022 •CodeCatch
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my_list = ["blue", "red", "green"] #1- Using sort or srted directly or with specifc keys my_list.sort() #sorts alphabetically or in an ascending order for numeric data my_list = sorted(my_list, key=len) #sorts the list based on the length of the strings from shortest to longest. # You can use reverse=True to flip the order #2- Using locale and functools import locale from functools import cmp_to_key my_list = sorted(my_list, key=cmp_to_key(locale.strcoll))
• Nov 19, 2022 •CodeCatch
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def clamp_number(num, a, b): return max(min(num, max(a, b)), min(a, b)) clamp_number(2, 3, 5) # 3 clamp_number(1, -1, -5) # -1
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# Python code to find the URL from an input string # Using the regular expression import re def Find(string): # findall() has been used # with valid conditions for urls in string regex = r"(?i)\b((?:https?://|www\d{0,3}[.]|[a-z0-9.\-]+[.][a-z]{2,4}/)(?:[^\s()<>]+|\(([^\s()<>]+|(\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\s()<>]+\)))*\)|[^\s`!()\[\]{};:'\".,<>?«»“”‘’]))" url = re.findall(regex,string) return [x[0] for x in url] # Driver Code string = 'My Profile: https://codecatch.net' print("Urls: ", Find(string))
• Dec 18, 2025 •CodeCatch
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def insertion_sort(arr): # Traverse through 1 to len(arr) for i in range(1, len(arr)): key = arr[i] # Move elements of arr[0..i-1], that are greater than key, # to one position ahead of their current position j = i - 1 while j >= 0 and key < arr[j]: arr[j + 1] = arr[j] j -= 1 arr[j + 1] = key # Example usage: arr = [12, 11, 13, 5, 6, 7, 8, 10] insertion_sort(arr) print("Sorted array is:", arr)
• May 31, 2023 •CodeCatch
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import calendar # Prompt user for year and month year = int(input("Enter the year: ")) month = int(input("Enter the month: ")) # Create a calendar object cal = calendar.monthcalendar(year, month) # Display the calendar print(calendar.month_name[month], year) print("Mon Tue Wed Thu Fri Sat Sun") for week in cal: for day in week: if day == 0: print(" ", end="") else: print(str(day).rjust(2), " ", end="") print()
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def when(predicate, when_true): return lambda x: when_true(x) if predicate(x) else x double_even_numbers = when(lambda x: x % 2 == 0, lambda x : x * 2) print(double_even_numbers(2)) # 4 print(double_even_numbers(1)) # 1