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integer to roman numeral

Nov 19, 2022CodeCatch
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Multiply Two Matrices

May 31, 2023CodeCatch

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# Function to multiply two matrices
def multiply_matrices(matrix1, matrix2):
# Check if the matrices can be multiplied
if len(matrix1[0]) != len(matrix2):
print("Error: The number of columns in the first matrix must be equal to the number of rows in the second matrix.")
return None
# Create the result matrix filled with zeros
result = [[0 for _ in range(len(matrix2[0]))] for _ in range(len(matrix1))]
# Perform matrix multiplication
for i in range(len(matrix1)):
for j in range(len(matrix2[0])):
for k in range(len(matrix2)):
result[i][j] += matrix1[i][k] * matrix2[k][j]
return result
# Example matrices
matrix1 = [[1, 2, 3],
[4, 5, 6],
[7, 8, 9]]
matrix2 = [[10, 11],
[12, 13],
[14, 15]]
# Multiply the matrices
result_matrix = multiply_matrices(matrix1, matrix2)
# Display the result
if result_matrix is not None:
print("Result:")
for row in result_matrix:
print(row)

Bitwise Lambda Overflow Calculations

Aug 12, 2024AustinLeath

0 likes • 5 views

magnitude = lambda bits: 1_000_000_000_000_000_000 % (2 ** bits)
sign = lambda bits: -1 ** (1_000_000_000_000_000_000 // (2 ** bits))
print("64 bit sum:", magnitude(64) * sign(64))
print("32 bit sum:", magnitude(32) * sign(32))
print("16 bit sum:", magnitude(16) * sign(16))

Binary search algorithm

Nov 19, 2022CodeCatch

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""" Binary Search Algorithm
----------------------------------------
"""
#iterative implementation of binary search in Python
def binary_search(a_list, item):
"""Performs iterative binary search to find the position of an integer in a given, sorted, list.
a_list -- sorted list of integers
item -- integer you are searching for the position of
"""
first = 0
last = len(a_list) - 1
while first <= last:
i = (first + last) / 2
if a_list[i] == item:
return ' found at position '.format(item=item, i=i)
elif a_list[i] > item:
last = i - 1
elif a_list[i] < item:
first = i + 1
else:
return ' not found in the list'.format(item=item)
#recursive implementation of binary search in Python
def binary_search_recursive(a_list, item):
"""Performs recursive binary search of an integer in a given, sorted, list.
a_list -- sorted list of integers
item -- integer you are searching for the position of
"""
first = 0
last = len(a_list) - 1
if len(a_list) == 0:
return ' was not found in the list'.format(item=item)
else:
i = (first + last) // 2
if item == a_list[i]:
return ' found'.format(item=item)
else:
if a_list[i] < item:
return binary_search_recursive(a_list[i+1:], item)
else:
return binary_search_recursive(a_list[:i], item)

Currency Converter

Nov 19, 2022CodeCatch

0 likes • 10 views

""" Currency Converter
----------------------------------------
"""
import urllib.request
import json
def currency_converter(currency_from, currency_to, currency_input):
yql_base_url = "https://query.yahooapis.com/v1/public/yql"
yql_query = 'select%20*%20from%20yahoo.finance.xchange%20where%20pair' \
'%20in%20("'+currency_from+currency_to+'")'
yql_query_url = yql_base_url + "?q=" + yql_query + "&format=json&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys"
try:
yql_response = urllib.request.urlopen(yql_query_url)
try:
json_string = str(yql_response.read())
json_string = json_string[2:
json_string = json_string[:-1]
print(json_string)
yql_json = json.loads(json_string)
last_rate = yql_json['query']['results']['rate']['Rate']
currency_output = currency_input * float(last_rate)
return currency_output
except (ValueError, KeyError, TypeError):
print(yql_query_url)
return "JSON format error"
except IOError as e:
print(str(e))
currency_input = 1
#currency codes : http://en.wikipedia.org/wiki/ISO_4217
currency_from = "USD"
currency_to = "TRY"
rate = currency_converter(currency_from, currency_to, currency_input)
print(rate)

Untitled

Sep 14, 2024rgannedo-6205

0 likes • 2 views

https://codecatch.net/post/06c9f5b7-1e00-40dc-b436-b8cccc4b69be

Selection sort

Nov 19, 2022CodeCatch

0 likes • 0 views

# Python program for implementation of Selection
# Sort
import sys
A = [64, 25, 12, 22, 11]
# Traverse through all array elements
for i in range(len(A)):
# Find the minimum element in remaining
# unsorted array
min_idx = i
for j in range(i+1, len(A)):
if A[min_idx] > A[j]:
min_idx = j
# Swap the found minimum element with
# the first element
A[i], A[min_idx] = A[min_idx], A[i]
# Driver code to test above
print ("Sorted array")
for i in range(len(A)):
print("%d" %A[i]),