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key of minimum value

Nov 19, 2022CodeCatch
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Input 2D Matrix

Nov 19, 2022CodeCatch

0 likes • 2 views

# Input for row and column
R = int(input())
C = int(input())
# Using list comprehension for input
matrix = [[int(input()) for x in range (C)] for y in range(R)]

Untitled

Jul 24, 2024AustinLeath

0 likes • 3 views

from statistics import median, mean, mode
def print_stats(array):
print(array)
print("median =", median(array))
print("mean =", mean(array))
print("mode =", mode(array))
print()
print_stats([1, 2, 3, 3, 4])
print_stats([1, 2, 3, 3])

Rock paper scissors

Nov 19, 2022CodeCatch

0 likes • 0 views

""" Rock Paper Scissors
----------------------------------------
"""
import random
import os
import re
os.system('cls' if os.name=='nt' else 'clear')
while (1 < 2):
print "\n"
print "Rock, Paper, Scissors - Shoot!"
userChoice = raw_input("Choose your weapon [R]ock], [P]aper, or [S]cissors: ")
if not re.match("[SsRrPp]", userChoice):
print "Please choose a letter:"
print "[R]ock, [S]cissors or [P]aper."
continue
// Echo the user's choice
print "You chose: " + userChoice
choices = ['R', 'P', 'S']
opponenetChoice = random.choice(choices)
print "I chose: " + opponenetChoice
if opponenetChoice == str.upper(userChoice):
print "Tie! "
#if opponenetChoice == str("R") and str.upper(userChoice) == "P"
elif opponenetChoice == 'R' and userChoice.upper() == 'S':
print "Scissors beats rock, I win! "
continue
elif opponenetChoice == 'S' and userChoice.upper() == 'P':
print "Scissors beats paper! I win! "
continue
elif opponenetChoice == 'P' and userChoice.upper() == 'R':
print "Paper beat rock, I win! "
continue
else:
print "You win!"

Copy file to destination

Nov 18, 2022AustinLeath

0 likes • 1 view

# importing the modules
import os
import shutil
# getting the current working directory
src_dir = os.getcwd()
# printing current directory
print(src_dir)
# copying the files
shutil.copyfile('test.txt', 'test.txt.copy2') #copy src to dst
# printing the list of new files
print(os.listdir())

Propositional logic with itertools

Nov 18, 2022AustinLeath

0 likes • 5 views

from itertools import product
V='∀'
E='∃'
def tt(f,n) :
xss=product((0,1),repeat=n)
print('function:',f.__name__)
for xs in xss : print(*xs,':',int(f(*xs)))
print('')
# p \/ (q /\ r) = (p \/ q) /\ (p \/ r)
def prob1(p,q,r) :
x=p or (q and r)
y= (p or q) and (p or r)
return x==y
tt(prob1,3)
# p/\(q\/r)=(p/\q)\/(p/\r)
def prob2(p,q,r) :
x=p and ( q or r )
y=(p and q) or (p and r)
return x==y
tt(prob2,3)
#~(p/\q)=(~p\/~q)
def prob3(p,q) :
x=not (p and q)
y=(not p) or (not q)
return x==y
tt(prob3,2)
#(~(p\/q))=((~p)/\~q)
def prob4(p, q):
x = not(p or q)
y = not p and not q
return x == y
tt(prob4, 2)
#(p/\(p=>q)=>q)
def prob5(p,q):
x= p and ( not p or q)
return not x or q
tt(prob5,2)
# (p=>q)=((p\/q)=q)
def prob6(p,q) :
x = (not p or q)
y=((p or q) == q)
return x==y
tt(prob6,2)
#((p=>q)=(p\/q))=q
def prob7(p,q):
if ((not p or q)==(p or q))==q:
return 1
tt(prob7,2)
#(p=>q)=((p/\q)=p)
def prob8(p,q):
if (not p or q)==((p and q)==p):
return 1
tt(prob8,2)
#((p=>q)=(p/\q))=p
def prob9(p,q):
if ((not p or q)==(p and q))==p:
return '1'
tt(prob9,2)
#(p=>q)/\(q=>r)=>(p=>r)
def prob10(p,q,r) :
x = not ((not p or q) and (not q or r)) or (not p or r)
return x
tt(prob10, 3)
# (p = q) /\ (q => r) => (p => r)
#answer 1
def prob11(p,q,r) :
x = not((p is q) and (not q or r)) or (not p or r)
return x
tt(prob11, 3)
#(p=q)/\(q=>r)=>(p=>r)
#answer 2
def prob11(p,q,r):
x=(p==q) and (not q or r)
y=not p or r
return not x or y
tt(prob11,3)
#((p=>q)/\(q=r))=>(p=>r)
def prob12(p,q,r):
x=(not p or q) and ( q==r )
y=not p or r
return not x or y
tt(prob12,3)
#(p=>q)=>((p/\r)=>(q/\r))
def prob13(p,q,r):
x=not p or q
y=(not(p and r) or ( q and r))
return not x or y
tt(prob13,3)
#Question#2----------------------------------------
#(p=>q)=>r=p=>(q=>r)
def prob14(p,q,r):
x=(not(not p or q) or r)
y=(not p or (not q or r))
return x==y
tt(prob14,3)
def prob15(p, q):
x = not(p and q)
y = not p and not q
return x == y
tt(prob15, 2)
def prob16(p, q):
x = not(p or q)
y = not p or not q
return x == y
tt(prob16, 2)
def prob17(p):
x = p
y = not p
return x == y
tt(prob17, 1)

Create a Pascal’s Triangle

May 31, 2023CodeCatch

0 likes • 1 view

def generate_pascals_triangle(num_rows):
triangle = []
for row in range(num_rows):
# Initialize the row with 1
current_row = [1]
# Calculate the values for the current row
if row > 0:
previous_row = triangle[row - 1]
for i in range(len(previous_row) - 1):
current_row.append(previous_row[i] + previous_row[i + 1])
# Append 1 at the end of the row
current_row.append(1)
# Add the current row to the triangle
triangle.append(current_row)
return triangle
def display_pascals_triangle(triangle):
for row in triangle:
for number in row:
print(number, end=" ")
print()
# Prompt the user for the number of rows
num_rows = int(input("Enter the number of rows for Pascal's Triangle: "))
# Generate Pascal's Triangle
pascals_triangle = generate_pascals_triangle(num_rows)
# Display Pascal's Triangle
display_pascals_triangle(pascals_triangle)