key of minimum value
0 likes • Nov 19, 2022 • 0 views
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primes=[]products=[]def prime(num):if num > 1:for i in range(2,num):if (num % i) == 0:return Falseelse:primes.append(num)return Truefor n in range(30,1000):if len(primes) >= 20:break;else:prime(n)for previous, current in zip(primes[::2], primes[1::2]):products.append(previous * current)print (products)
# Deleting all even numbers from a lista = [1,2,3,4,5]del a[1::2]print(a)
# Input for row and columnR = int(input())C = int(input())# Using list comprehension for inputmatrix = [[int(input()) for x in range (C)] for y in range(R)]
# Python program for implementation of Selection# Sortimport sysA = [64, 25, 12, 22, 11]# Traverse through all array elementsfor i in range(len(A)):# Find the minimum element in remaining# unsorted arraymin_idx = ifor j in range(i+1, len(A)):if A[min_idx] > A[j]:min_idx = j# Swap the found minimum element with# the first elementA[i], A[min_idx] = A[min_idx], A[i]# Driver code to test aboveprint ("Sorted array")for i in range(len(A)):print("%d" %A[i]),
#84 48 13 20 61 20 33 97 34 45 6 63 71 66 24 57 92 74 6 25 51 86 48 15 64 55 77 30 56 53 37 99 9 59 57 61 30 97 50 63 59 62 39 32 34 4 96 51 8 86 10 62 16 55 81 88 71 25 27 78 79 88 92 50 16 8 67 82 67 37 84 3 33 4 78 98 39 64 98 94 24 82 45 3 53 74 96 9 10 94 13 79 15 27 56 66 32 81 77# xor a list of integers to find the lonely integerres = a[0]for i in range(1,len(a)):res = res ^ a[i]
def check_prop(fn, prop):return lambda obj: fn(obj[prop])check_age = check_prop(lambda x: x >= 18, 'age')user = {'name': 'Mark', 'age': 18}check_age(user) # True