• Nov 19, 2022 •CodeCatch
0 likes • 1 view
# Python code to find the URL from an input string # Using the regular expression import re def Find(string): # findall() has been used # with valid conditions for urls in string regex = r"(?i)\b((?:https?://|www\d{0,3}[.]|[a-z0-9.\-]+[.][a-z]{2,4}/)(?:[^\s()<>]+|\(([^\s()<>]+|(\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\s()<>]+\)))*\)|[^\s`!()\[\]{};:'\".,<>?«»“”‘’]))" url = re.findall(regex,string) return [x[0] for x in url] # Driver Code string = 'My Profile: https://codecatch.net' print("Urls: ", Find(string))
0 likes • 3 views
# Python program for Plotting Fibonacci # spiral fractal using Turtle import turtle import math def fiboPlot(n): a = 0 b = 1 square_a = a square_b = b # Setting the colour of the plotting pen to blue x.pencolor("blue") # Drawing the first square x.forward(b * factor) x.left(90) x.forward(b * factor) x.left(90) x.forward(b * factor) x.left(90) x.forward(b * factor) # Proceeding in the Fibonacci Series temp = square_b square_b = square_b + square_a square_a = temp # Drawing the rest of the squares for i in range(1, n): x.backward(square_a * factor) x.right(90) x.forward(square_b * factor) x.left(90) x.forward(square_b * factor) x.left(90) x.forward(square_b * factor) # Proceeding in the Fibonacci Series temp = square_b square_b = square_b + square_a square_a = temp # Bringing the pen to starting point of the spiral plot x.penup() x.setposition(factor, 0) x.seth(0) x.pendown() # Setting the colour of the plotting pen to red x.pencolor("red") # Fibonacci Spiral Plot x.left(90) for i in range(n): print(b) fdwd = math.pi * b * factor / 2 fdwd /= 90 for j in range(90): x.forward(fdwd) x.left(1) temp = a a = b b = temp + b # Here 'factor' signifies the multiplicative # factor which expands or shrinks the scale # of the plot by a certain factor. factor = 1 # Taking Input for the number of # Iterations our Algorithm will run n = int(input('Enter the number of iterations (must be > 1): ')) # Plotting the Fibonacci Spiral Fractal # and printing the corresponding Fibonacci Number if n > 0: print("Fibonacci series for", n, "elements :") x = turtle.Turtle() x.speed(100) fiboPlot(n) turtle.done() else: print("Number of iterations must be > 0")
from math import pi def rads_to_degrees(rad): return (rad * 180.0) / pi rads_to_degrees(pi / 2) # 90.0
• Jun 1, 2023 •CodeCatch
0 likes • 4 views
bytes_data = b'Hello, World!' string_data = bytes_data.decode('utf-8') print("String:", string_data)
0 likes • 0 views
# Python program to reverse a linked list # Time Complexity : O(n) # Space Complexity : O(n) as 'next' #variable is getting created in each loop. # Node class class Node: # Constructor to initialize the node object def __init__(self, data): self.data = data self.next = None class LinkedList: # Function to initialize head def __init__(self): self.head = None # Function to reverse the linked list def reverse(self): prev = None current = self.head while(current is not None): next = current.next current.next = prev prev = current current = next self.head = prev # Function to insert a new node at the beginning def push(self, new_data): new_node = Node(new_data) new_node.next = self.head self.head = new_node # Utility function to print the linked LinkedList def printList(self): temp = self.head while(temp): print temp.data, temp = temp.next # Driver program to test above functions llist = LinkedList() llist.push(20) llist.push(4) llist.push(15) llist.push(85) print "Given Linked List" llist.printList() llist.reverse() print "\nReversed Linked List" llist.printList()
• Nov 18, 2022 •AustinLeath
0 likes • 9 views
#Python 3: Fibonacci series up to n def fib(n): a, b = 0, 1 while a < n: print(a, end=' ') a, b = b, a+b print() fib(1000)