//From https://create.arduino.cc/projecthub/abhilashpatel121/easyfft-fast-fourier-transform-fft-for-arduino-9d2677
#include <cmath>
#include <iostream>
const unsigned char sine_data[] = {	//Quarter a sine wave
	0, 
	4, 9, 13, 18, 22, 27, 31, 35, 40, 44, 
	49, 53, 57, 62, 66, 70, 75, 79, 83, 87, 
	91, 96, 100, 104, 108, 112, 116, 120, 124, 127, 
	131, 135, 139, 143, 146, 150, 153, 157, 160, 164, 
	167, 171, 174, 177, 180, 183, 186, 189, 192, 195, //Paste this at top of program
	198, 201, 204, 206, 209, 211, 214, 216, 219, 221, 
	223, 225, 227, 229, 231, 233, 235, 236, 238, 240, 
	241, 243, 244, 245, 246, 247, 248, 249, 250, 251, 
	252, 253, 253, 254, 254, 254, 255, 255, 255, 255
};
float sine(int i){	//Inefficient sine
	int j=i;
	float out;
	while(j < 0) j = j + 360;
	while(j > 360) j = j - 360;
	if(j > -1 && j < 91) out = sine_data[j];
	else if(j > 90 && j < 181) out = sine_data[180 - j];
	else if(j > 180 && j < 271) out = -sine_data[j - 180];
	else if(j > 270 && j < 361) out = -sine_data[360 - j];
	return (out / 255);
}

float cosine(int i){	//Inefficient cosine
	int j = i;
	float out;
	while(j < 0) j = j + 360;
	while(j > 360) j = j - 360;
	if(j > -1 && j < 91) out = sine_data[90 - j];
	else if(j > 90 && j < 181) out = -sine_data[j - 90];
	else if(j > 180 && j < 271) out = -sine_data[270 - j];
	else if(j > 270 && j < 361) out = sine_data[j - 270];
	return (out / 255);
}

//Example data:

//-----------------------------FFT Function----------------------------------------------//
float* FFT(int in[],unsigned int N,float Frequency){	//Result is highest frequencies in order of loudness. Needs to be deleted.
	/*
	Code to perform FFT on arduino,
	setup:
	paste sine_data [91] at top of program [global variable], paste FFT function at end of program
	Term:
	1. in[] : Data array, 
	2. N : Number of sample (recommended sample size 2,4,8,16,32,64,128...)
	3. Frequency: sampling frequency required as input (Hz)

	If sample size is not in power of 2 it will be clipped to lower side of number. 
	i.e, for 150 number of samples, code will consider first 128 sample, remaining sample will be omitted.
	For Arduino nano, FFT of more than 128 sample not possible due to mamory limitation (64 recomended)
	For higher Number of sample may arise Mamory related issue,
	Code by ABHILASH
	Contact: [email protected] 
	Documentation:https://www.instructables.com/member/abhilash_patel/instructables/
	2/3/2021: change data type of N from float to int for >=256 samples
	*/

	unsigned int sampleRates[13]={1,2,4,8,16,32,64,128,256,512,1024,2048};
	int a = N;
	int o;
	for(int i=0;i<12;i++){		//Snapping N to a sample rate in sampleRates
		if(sampleRates[i]<=a){
			o = i;
		}
	}
		 
	int in_ps[sampleRates[o]] = {}; //input for sequencing
	float out_r[sampleRates[o]] = {}; //real part of transform
	float out_im[sampleRates[o]] = {}; //imaginory part of transform
	int x = 0; 
	int c1;
	int f;
	for(int b=0;b<o;b++){ // bit reversal
		c1 = sampleRates[b];
		f = sampleRates[o] / (c1 + c1);
		for(int j = 0;j < c1;j++){ 
			x = x + 1;
			in_ps[x]=in_ps[j]+f;
		}
	}

	
	for(int i=0;i<sampleRates[o];i++){ // update input array as per bit reverse order
		if(in_ps[i]<a){
			out_r[i]=in[in_ps[i]];
		}
		if(in_ps[i]>a){
			out_r[i]=in[in_ps[i]-a];
		} 
	}


	int i10,i11,n1;
	float e,c,s,tr,ti;

	for(int i=0;i<o;i++){ //fft
		i10 = sampleRates[i]; // overall values of sine/cosine :
		i11 = sampleRates[o] / sampleRates[i+1]; // loop with similar sine cosine:
		e = 360 / sampleRates[i+1];
		e = 0 - e;
		n1 = 0;

		for(int j=0;j<i10;j++){
			c=cosine(e*j);
			s=sine(e*j); 
			n1=j;

			for(int k=0;k<i11;k++){
				tr = c*out_r[i10 + n1]-s*out_im[i10 + n1];
				ti = s*out_r[i10 + n1]+c*out_im[i10 + n1];

				out_r[n1 + i10] = out_r[n1]-tr;
				out_r[n1] = out_r[n1]+tr;

				out_im[n1 + i10] = out_im[n1]-ti;
				out_im[n1] = out_im[n1]+ti; 

				n1 = n1+i10+i10;
			} 
		}
	}

	/*
	for(int i=0;i<sampleRates[o];i++)
	{
	std::cout << (out_r[i]);
	std::cout << ("\t"); // un comment to print RAW o/p 
	std::cout << (out_im[i]); std::cout << ("i"); 
	std::cout << std::endl;
	}
	*/


	//---> here onward out_r contains amplitude and our_in conntains frequency (Hz)
	for(int i=0;i<sampleRates[o-1];i++){ // getting amplitude from compex number
		out_r[i] = sqrt(out_r[i]*out_r[i]+out_im[i]*out_im[i]); // to increase the speed delete sqrt
		out_im[i] = i * Frequency / N;
		std::cout << (out_im[i]); std::cout << ("Hz");
		std::cout << ("\t");	// un comment to print freuency bin 
		std::cout << (out_r[i]);
		std::cout << std::endl;
	}




	x = 0; // peak detection
	for(int i=1;i<sampleRates[o-1]-1;i++){
		if(out_r[i]>out_r[i-1] && out_r[i]>out_r[i+1]){
			in_ps[x] = i; //in_ps array used for storage of peak number
			x = x + 1;
		} 
	}


	s = 0;
	c = 0;
	for(int i=0;i<x;i++){ // re arraange as per magnitude
		for(int j=c;j<x;j++){
			if(out_r[in_ps[i]]<out_r[in_ps[j]]){
				s=in_ps[i];
				in_ps[i]=in_ps[j];
				in_ps[j]=s;
			}
		}
		c=c+1;
	}
	float* f_peaks = new float[sampleRates[o]];
	for(int i=0;i<5;i++){ // updating f_peak array (global variable)with descending order
		f_peaks[i]=out_im[in_ps[i]];
	}
	return f_peaks;
}

//------------------------------------------------------------------------------------//
//main.cpp
int data[64]={
14, 30, 35, 34, 34, 40, 46, 45, 30, 4, -26, -48, -55, -49, -37,
-28, -24, -22, -13, 6, 32, 55, 65, 57, 38, 17, 1, -6, -11, -19, -34, 
-51, -61, -56, -35, -7, 18, 32, 35, 34, 35, 41, 46, 43, 26, -2, -31, -50,
-55, -47, -35, -27, -24, -21, -10, 11, 37, 58, 64, 55, 34, 13, -1, -7
};

int main(){
	const unsigned int SAMPLE_RATE = 48*1000;	//48khz
	auto result = FFT(data,64,SAMPLE_RATE);
	std::cout << result[0] << " " << result[1] << " " << result[2] << " " << result[3] << std::endl;
	delete[] result;
	return 0;
}

//Get data file at https://codecatch.net/post.php?postID=91e87d73
//Iteration 1 of Wing Project. Solution breaks down around n=35

#include <iostream>
#include <fstream>
#include <string>
#include <vector>
#include <map>
using namespace std;

int getSum(map<int, int> list);
void readData(map<int, float>* data);
void lowestPrice();
void findSums(int n, vector<map<int, int>>* sumsList, map<int, float>* data);
//void findSum(map<int, int> currList, int x, int n, vector<map<int, int>>* sumsList);
void findSum(map<int, int> currList, int x, int n, vector<map<int, int>>* sumsList, map<int, float>* data);
float getPrice(map<int, int> set, map<int, float>* data);

template <typename S>
ostream& operator<<(ostream& os, const vector<S>& vector)
{
	// Printing all the elements using <<
	for (auto element : vector) {
	os << element << " ";
	}
	return os;
}

bool operator==(map<int, int> m1, map<int, int> m2)
{
	if(m1.size() != m2.size())
	return false;

	bool ret = true;

	for(auto it = m1.begin(); it !=m1.end() && ret; it++)
	{
	if(ret && m1.count(it->first) != m2.count(it->first))
	ret = false;

	if(ret && m1.count(it->first) == 1)
	{
	if(m1.at(it->first) != m2.at(it->first))
	ret = false;
	}
	}

	return ret;
}


int main()
{
	map<int, float> data;
	readData(&data);

	vector<map<int, int>> *sumsList;
	sumsList = new vector<map<int, int>>;
	findSums(40, sumsList, &data);

	for(auto el : *sumsList)
	{
	for(auto it = el.begin(); it != el.end(); it++)
	{
	cout << it->first << "->" << it->second << " ";
	}
	cout << getPrice(el, &data) << endl;
	}

	return 0;
}

/* Returns the price of wings given a set of numbers of wings to buy.
	* Returns -1 if the set contains a number that is not possible to buy.
	*/
float getPrice(map<int, int> set, map<int, float>* data)
{
	float price = 0;
	for(auto it = set.begin(); it != set.end(); it++)
	{
	//If data doesn't contain an element of set, return -1
	if(data->count(it->first) == 0)
	return -1;
	
	price += data->at(it->first) * it->second; //pricePerPacket * qtyOfPackets
	}

	return price;
}

/* Adds the elements of list.
	* Suppose mapping is <num, qty>.
	* Returns sum(num*qty)
	*/
int getSum(map<int, int> list)
{
	int sum = 0;
	for(auto it = list.begin(); it != list.end(); it++)
	sum += it->first * it->second;
	return sum;
}

void findSums(int n, vector<map<int, int>>* sumsList, map<int, float>* data)
{
	map<int, int> currList;

	//Recur when currSum < n
	auto it = data->begin();
	while(it->first <= n && it != data->end())
	{
	findSum(currList, it->first, n, sumsList, data);
	it++;
	}
}

void findSum(map<int, int> currList, int x, int n, vector<map<int, int>>* sumsList, map<int, float>* data)
{
	//Append x to currList
	if(currList.count(x) == 0)
	currList.emplace(x, 1);
	else
	{
	int val = 1+ currList.at(x);
	currList.erase(x);
	currList.emplace(x, val);
	}

	//Determine current sum, check for return cases
	int currSum = getSum(currList);

	if(currSum > n)
	return;
	else if(currSum == n)
	{

	//Check to make sure no duplicates
	for(auto list : *sumsList)
	{
	if(list == currList)
	return;
	}

	sumsList->push_back(currList);
	return;
	}

	//Recur when currSum < n
	auto it = data->begin();
	while(it->first <= n-x && it != data->end())
	{
	findSum(currList, it->first, n, sumsList, data);
	it++;
	}
}

void readData(map<int, float>* data)
{
	ifstream file ("./data", ifstream::in);

	if(file.is_open())
	{
	int i = 0;
	while(!file.eof())
	{
	float wings, price;
	string skipnl;
	file >> wings;
	file >> price;

	data->emplace(wings, price);

	getline(file, skipnl);
	i++;
	}
	}
}

/*
Good morning! Here's your coding interview problem for today.

This problem was asked by Stripe.

Given an array of integers, find the first missing positive integer in linear time and constant space. In other words, find the lowest positive integer that does not exist in the array. The array can contain duplicates and negative numbers as well.

For example, the input [3, 4, -1, 1] should give 2. The input [1, 2, 0] should give 3.

You can modify the input array in-place.
*/
#include <iostream>
using namespace std;

int calcMissing(int* input, int size)
{
	int sum = 0;
	int n = 1; //add one to account for missing value
	for(int i = 0; i < size; i++)
	{
	if(input[i] > 0)
	{
	sum += input[i];
	n++;
	}
	}

	//If no numbers higher than 0, answer is 1
	if(sum == 0)
	return 1;

	return (n*(n+1)/2) - sum; //Formula is expectedSum - actualSum
	/* expectedSum = n*(n+1)/2, the formula for sum(1, n) */
}

int main()
{

	cout << calcMissing(new int[4]{3, 4, -1, 1}, 4) << endl;
	cout << calcMissing(new int[3]{1, 2, 0}, 3) << endl;

	//No positive numbers
	cout << calcMissing(new int[1]{0}, 1) << endl;
}

#define NUM_BITS 8

#include <iostream>


struct Number{
    int num : NUM_BITS;
    Number(){}
    Number(const int& bruh){
        num = bruh;
    }
    operator int() const { return num; }
    Number& operator=(const int& bruh){
        num = bruh;
        return (*this);
    }
};

using namespace std;

bool isNegative(const int& num){
    //This gets the bitwise and of num and 10000000000000000000000000000000
    //This implicit casts to bool, which means (num & (1 << 31)) != 0
    return (num & (1 << 31));
}

void printBinaryNumber(const int& num, const int numBits){
    for(int i = numBits; i > 0; --i){
        //8..1
        int bitMask = 1 << (i-1);
        if(num & bitMask){ //Test the bit
            cout << '1';
        }else{
            cout << '0';
        }
    }
}

void printCarryBits(const int& a, const int& b, const int numBits){
    int answer = 0;
    
    bool carry = false;
    for(int i = 0; i < numBits; ++i){
        //8..1
        int bitMask = 1 << i;
        bool aBit = a & bitMask;
        bool bBit = b & bitMask;
        if(aBit && bBit || aBit && carry || bBit && carry){ //Carry bit is true next
            if(carry)
                answer |= bitMask;
            carry = true;
        }else{
            if(carry)
                answer |= bitMask;
            carry = false;
        }
    }
    printBinaryNumber(answer, 8);
}


void printBorrowBits(const int& a, const int& b, const int numBits){
    int answer = 0;
    
    bool carry = false;
    for(int i = 0; i < numBits; ++i){
        //8..1
        int bitMask = 1 << i;
        bool aBit = a & bitMask;
        bool bBit = b & bitMask;
        if((!(aBit ^ carry)) && bBit){ //Carry bit is true next
            if(carry)
                answer |= bitMask;
            carry = true;
        }else{
            if(carry)
                answer |= bitMask;
            carry = false;
        }
    }
    printBinaryNumber(answer, 8);
}

void doProblem(const int& a, const int& b, const char& sign, const int& result, const int& numBits){
    if(sign == '+'){
        cout << ' '; printCarryBits(a, b, numBits); cout << endl;
    }else{
        cout << ' '; printBorrowBits(a, b, numBits); cout << endl;
    }
    cout << ' '; printBinaryNumber(a, numBits); cout << endl;
    cout << sign; printBinaryNumber(b, numBits); cout << endl;
    cout << "----------" << endl;
    cout << ""; printBinaryNumber(result, numBits + 1); cout << " = " << result;
    cout << endl;
}

int main(){
    
    Number a = 0b110;
    Number b = 0b011;
    cout<< a << endl << b << endl;
    
    doProblem(a, b, '+', a + b, NUM_BITS);
    doProblem(a, b, '-', a - b, NUM_BITS);
    doProblem(-a, b, '+', -a + b, NUM_BITS);
    doProblem(a, b, '-', -a - b, NUM_BITS);
    

    return 0;
}

#include <iostream>
using namespace std;

main
{
	cout << "No tabbing. That's very sad :(\n";
	cout << "No in-editor highlighting either :(((\n";
	cout << "Descriptions might be niice too.";
}

#include <iostream>
int main(){
    const char* const hello = "Hello, world!";
    
    const char* bruh = hello;
    
    char* const yeet = hello;
    
    std::cout << bruh << std::endl;
    
    std::cout << yeet << std::endl;
    
    return 0;
}

/*
    Place your bets!
    
    Will the program:
    a.) Print "Hello, world!" twice?
    b.) Compile error on line 5 (bruh initialize line) because the pointer gets implicit cast to non-const?
    c.) Compile error on line 7 (yeet initialize line) because the char gets implicit cast to non-const?
    d.) Both b and c?
    e.) Compile error line 11 (print yeet) because the pointer is constant and can't be incremented
    f.) Print "Hello, world!" then print the pointer address in hexadecimal
    g.) Both b and e?
    h.) Both c and e?
    i.) B, c, and e?
    
*/

// The answer is in this base 64 string:
// 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