Skip to main content

Parking Lot Simulation

Nov 18, 2022AustinLeath
Loading...

More C++ Posts

Two Letter Combinations

Nov 18, 2022AustinLeath

0 likes • 0 views

#include <iostream>
#include <fstream>
#include <string>
#include <cstring>
using namespace std;
//This program makes a new text file that contains all combinations of two letters.
// aa, ab, ..., zy, zz
int main(){
string filename = "two_letters.txt";
ofstream outFile;
outFile.open(filename.c_str());
if(!outFile.is_open()){
cout << "Something's wrong. Closing..." << endl;
return 0;
}
for(char first = 'a'; first <= 'z'; first++){
for(char second = 'a'; second <= 'z'; second++){
outFile << first << second << " ";
}
outFile << endl;
}
return 0;
}

set hostname syscall

Oct 7, 2023AustinLeath

0 likes • 12 views

#include <iostream>
#include <cstring>
#include <unistd.h>
#include <sys/utsname.h>
int main() {
char newHostname[] = "newhostname"; // Replace with the desired hostname
if (sethostname(newHostname, strlen(newHostname)) == 0) {
std::cout << "Hostname set to: " << newHostname << std::endl;
// Optionally, update the /etc/hostname file to make the change permanent
FILE *hostnameFile = fopen("/etc/hostname", "w");
if (hostnameFile != NULL) {
fprintf(hostnameFile, "%s\n", newHostname);
fclose(hostnameFile);
} else {
perror("Failed to update /etc/hostname");
}
} else {
perror("Failed to set hostname");
}
return 0;
}

Daily: Cutting a Wall

Dec 20, 2021aedrarian

0 likes • 0 views

/*
Good morning! Here's your coding interview problem for today.
This problem was asked by LinkedIn.
A wall consists of several rows of bricks of various integer lengths and uniform height. Your goal is to find a vertical line going from the top to the bottom of the wall that cuts through the fewest number of bricks. If the line goes through the edge between two bricks, this does not count as a cut.
For example, suppose the input is as follows, where values in each row represent the lengths of bricks in that row:
[[3, 5, 1, 1],
[2, 3, 3, 2],
[5, 5],
[4, 4, 2],
[1, 3, 3, 3],
[1, 1, 6, 1, 1]]
The best we can we do here is to draw a line after the eighth brick, which will only require cutting through the bricks in the third and fifth row.
Given an input consisting of brick lengths for each row such as the one above, return the fewest number of bricks that must be cut to create a vertical line.
AUTHORS NOTE:
Makes following assumptions:
- Each row is same length
- Data is in file called "data.dat" and formatted in space-separated rows
- The cuts at the beginning and end of the wall are not solutions
This requires the following file named data.dat that is a space separated file, or similar formatted file:
----START FILE----
3 5 1 1
2 3 3 2
5 5
4 4 2
1 3 3 3
1 1 6 1 1
----END FILE----
*/
#include <algorithm>
#include <iostream>
#include <fstream>
#include <map>
#include <sstream>
#include <string>
#include <vector>
using namespace std;
int main()
{
vector<vector<int>> wall;
ifstream in;
in.open("data.dat");
if(!in.good())
{
cout << "ERROR: File failed to open properly.\n";
}
/* Get input from space separated file */
string line;
while(!in.eof())
{
getline(in, line);
int i;
vector<int> currv;
stringstream strs(line);
while(strs >> i)
currv.push_back(i);
wall.push_back(currv);
}
/* Convert each value from "length of brick" to "position at end of brick" */
for(int y = 0; y < wall.size(); y++)
{
wall.at(y).pop_back(); //Delet last val
for(int x = 1; x < wall.at(y).size(); x++) //Skip the first bc data doesn't need change
wall.at(y).at(x) += wall.at(y).at(x-1);
}
/* Check output. COMMENT OUT */
// for(auto row : wall)
// {
// for(int pos : row)
// cout << pos << " ";
// cout << endl;
// }
/* Determine which ending position is most common, and cut there */
//Exclude final position, which will be the size of the wall
int mode = -1;
int amt = -1;
vector<int> tried;
for(auto row : wall)
{
for(int pos : row) //For each pos in the wall
{
//Guard. If pos is contained in the list, skip pos
if(find(tried.begin(), tried.end(), pos) != tried.end())
continue;
tried.push_back(pos);
/* Cycle through each row to see if it contains the pos */
int curramt = 0;
for(auto currrow : wall)
{
if( find( currrow.begin(), currrow.end(), pos ) != currrow.end() )
curramt++;
}
//cout << pos << " " << curramt << endl;
if(curramt > amt)
{
amt = curramt;
mode = pos;
}
}
}
cout << "Please cut at position " << mode << endl;
cout << "This will cut through " << (wall.size() - amt) << " bricks." << endl;
return 0;
}

Big O(n^2) Ascending Sort

Nov 18, 2022AustinLeath

1 like • 7 views

#include <iostream>
using namespace std;
int main() {
int arr[5];
for(int i = 0; i < 5; i++) {
arr[i] = i;
}
for(int i = 0; i < 5; i++) {
cout << "Outputting array info at position " << i + 1 << ": " << arr[i] << endl;
}
for(int i=0;i<5;i++)
{
for(int j=i+1;j<5;j++)
{
if(arr[i]>arr[j])
{
int temp=arr[i];
arr[i]=arr[j];
arr[j]=temp;
}
}
}
cout << endl;
for(int i = 0; i < 5; i++) {
cout << "Outputting sorted array info at position " << i + 1 << ": " << arr[i] << endl;
}
return 0;
}

Egg Problem Template

Jul 10, 2023LeifMessinger

0 likes • 4 views

#include <iostream>
#include <vector>
#include <limits>
#define DEBUG_TRIAL false
class Trial{
public:
const size_t HEIGHT;
std::string record;
//Breaking height is the index of the floor, so 0 is the bottom floor, height-1 is the top floor.
//Eggs is the eggs remaining.
//Start is the bottom floor.
//End is one above the top floor.
const size_t BREAKING_HEIGHT;
size_t eggs;
size_t start;
size_t end;
size_t floorsLeft(){
return (end-start);
}
size_t middle(){
return start + (floorsLeft()/2UL);
}
size_t drops = 0;
Trial(const size_t BREAKING_HEIGHT, size_t eggs, size_t start, size_t end): BREAKING_HEIGHT(BREAKING_HEIGHT), eggs(eggs), start(start), end(end), HEIGHT(end), record(end, '_'){
record[BREAKING_HEIGHT] = 'B'; //Marking the breaking point
}
bool foundAnswer(){
return ((record[0] == 'X') || (record.find("OX")!=std::string::npos));
}
//returns true if the egg broke.
//height is the index of the floor, so 0 is the bottom floor, height-1 is the top floor.
bool drop(size_t height){
#if DEBUG_TRIAL
std::cout << "Start: " << start << ". End: " << end << ". Floors Left: " << floorsLeft() << ". Middle Index: " << middle() << std::endl;
#endif
drops++;
bool cracked = height >= BREAKING_HEIGHT;
if(cracked) --eggs;
//Update the record
record[height] = (height >= BREAKING_HEIGHT)? 'X' : 'O';
#if DEBUG_TRIAL
//Print the record
std::cout << record << std::endl;
#endif
return cracked;
}
size_t nowWhat(){
if(foundAnswer()){
return drops;
}else if(eggs <= 0){ //Ran out of eggs
throw "Algorithm failed! No more eggs!";
return 1UL;
}else if(eggs > 1){
return wrecklessSearch();
}else{
return safeSearch();
}
}
size_t safeSearch(){
if(drop(start)){
--end;
}else{
++start;
}
return nowWhat();
}
size_t wrecklessSearch(){
//If the egg breaks
if(drop(middle())){
end -= (floorsLeft()/2UL);
}else{ //egg doesn't crack
start += (floorsLeft()/2UL);
}
return nowWhat();
}
//returns the amount of drops needed to find the answer
size_t search(){
return nowWhat();
}
};
//Height is the height of the building in floors.
//Breaking height is the index of the floor, so 0 is the bottom floor, height-1 is the top floor.
//Eggs is the eggs given.
//returns the amount of drops needed to find the answer
size_t search(const size_t height, const size_t BREAKING_HEIGHT, size_t eggs){
Trial trial(BREAKING_HEIGHT, eggs, 0, height);
return trial.search();
}
class TrialStats {
public:
size_t min = std::numeric_limits<size_t>::max();
size_t max = 0;
double mean = -1.0;
void printStats(){
// Print the results
std::cout << "Minimum drops: " << min << std::endl;
std::cout << "Maximum drops: " << max << std::endl;
std::cout << "Mean drops: " << mean << std::endl;
}
};
//Benchmarks all the possible breaking points of a single building height with a number of eggs.
TrialStats trial(const size_t HEIGHT, const size_t eggs){
TrialStats stats;
int totaldrops = 0;
//Test every possible breaking point
//Breaking height is the index of the floor, so 0 is the bottom floor, height-1 is the top floor.
for (int breakingHeight = 0; breakingHeight < HEIGHT; ++breakingHeight) {
size_t drops = search(HEIGHT, breakingHeight, eggs);
stats.min = std::min(stats.min, drops);
stats.max = std::max(stats.max, drops);
totaldrops += drops;
}
// Calculate the mean number of drops
stats.mean = static_cast<double>(totaldrops) / HEIGHT;
return stats;
}
//Benchmarks a single building height from 1 egg to MAX_EGGS
void testTower(const size_t height, const size_t MAX_EGGS){
//Drop every amount of eggs that you'd need.
for (int eggs = 1; eggs <= MAX_EGGS; ++eggs) {
std::cout << "Building height: " << height << ". Num eggs: " << eggs << std::endl;
TrialStats stats = trial(height, eggs);
stats.printStats();
std::cout << std::endl << std::endl;
}
}
//Benchmarks all buildings from 0 to MAX_HEIGHT
void benchmark(const size_t MAX_HEIGHT){
const size_t MAX_EGGS = 2;
//Test every building
for (size_t height = 1; height <= MAX_HEIGHT; ++height) {
testTower(height, std::min(height, MAX_EGGS));
}
}
int main() {
constexpr size_t MAX_HEIGHT = 36;
benchmark(MAX_HEIGHT);
return 0;
}

Get Coefficient

Nov 18, 2022AustinLeath

0 likes • 4 views

#include <iostream>
using namespace std;
/* Function: get_coeff
Parameters: double& coeff, int pos passed from bb_4ac
Return: type is void so no return, but does ask for user to input data that establishes what a b and c are.
*/
void get_coeff(double& coeff, int pos) {
char position;
if(pos == 1) {
position = 'a';
} else if(pos == 2) { //a simple system to determine what coefficient the program is asking for.
position = 'b';
} else {
position = 'c';
}
cout << "Enter the co-efficient " << position << ":"; //prompt to input coeff
coeff = 5; //input coeff
}
/* Function: bb_4ac
Parameters: no parameters passed from main, but 3 params established in function, double a, b, c.
Return: b * b - 4 * a * c
*/
double bb_4ac() {
double a, b, c; //coefficients of a quadratic equation
get_coeff(a, 1); // call function 1st time
get_coeff(b, 2); // call function 2nd time
get_coeff(c, 3); // call function 3rd time
return b * b - 4 * a * c; //return b * b - 4 * a * c
}
int main() {
cout << "Function to calculate the discriminant of the equation. . . " << endl;
double determinate = bb_4ac(); //assign double determinate to bb_4ac function
cout << "The discriminant for given values is: " << determinate << endl; //output the determinate!
}