Skip to main content

Parking Lot Simulation

0 likes • Nov 18, 2022
C++
Loading...
Download

More C++ Posts

Hello, World!

AustinLeath
0 likes • Nov 18, 2022
C++
#include <iostream>
using namespace std;
int main()
{
cout << "Hello, World!" << endl;
return 0;
}

Hash Table Example

AustinLeath
0 likes • Nov 18, 2022
C++
using namespace std;
class Hash
{
int BUCKET; // No. of buckets
// Pointer to an array containing buckets
list<int> *table;
public:
Hash(int V); // Constructor
// inserts a key into hash table
void insertItem(int x);
// deletes a key from hash table
void deleteItem(int key);
// hash function to map values to key
int hashFunction(int x) {
return (x % BUCKET);
}
void displayHash();
};
Hash::Hash(int b)
{
this->BUCKET = b;
table = new list<int>[BUCKET];
}
void Hash::insertItem(int key)
{
int index = hashFunction(key);
table[index].push_back(key);
}
void Hash::deleteItem(int key)
{
// get the hash index of key
int index = hashFunction(key);
// find the key in (inex)th list
list <int> :: iterator i;
for (i = table[index].begin();
i != table[index].end(); i++) {
if (*i == key)
break;
}
// if key is found in hash table, remove it
if (i != table[index].end())
table[index].erase(i);
}
// function to display hash table
void Hash::displayHash() {
for (int i = 0; i < BUCKET; i++) {
cout << i;
for (auto x : table[i])
cout << " --> " << x;
cout << endl;
}
}
// Driver program
int main()
{
// array that contains keys to be mapped
int a[] = {15, 11, 27, 8, 12};
int n = sizeof(a)/sizeof(a[0]);
// insert the keys into the hash table
Hash h(7); // 7 is count of buckets in
// hash table
for (int i = 0; i < n; i++)
h.insertItem(a[i]);
// delete 12 from hash table
h.deleteItem(12);
// display the Hash table
h.displayHash();
return 0;
}

Big O(n^2) Ascending Sort

AustinLeath
0 likes • Nov 18, 2022
C++
#include <iostream>
using namespace std;
int main() {
int dataEntry;
int arr[5];
for(int i = 0; i < 5; i++) {
cout << "Enter a number that you want to put into the array: ";
cin >> dataEntry;
arr[i] = dataEntry;
}
cout << endl;
for(int i = 0; i < 5; i++) {
cout << "Outputting array info at position " << i + 1 << ": " << arr[i] << endl;
}
for(int i=0;i<5;i++)
{
for(int j=i+1;j<5;j++)
{
if(arr[i]>arr[j])
{
int temp=arr[i];
arr[i]=arr[j];
arr[j]=temp;
}
}
}
cout << endl;
for(int i = 0; i < 5; i++) {
cout << "Outputting sorted array info at position " << i + 1 << ": " << arr[i] << endl;
}
return 0;
}

Wing Project 1

aedrarian
0 likes • Oct 31, 2021
C++
//Get data file at https://codecatch.net/post.php?postID=91e87d73
//Iteration 1 of Wing Project. Solution breaks down around n=35
#include <iostream>
#include <fstream>
#include <string>
#include <vector>
#include <map>
using namespace std;
int getSum(map<int, int> list);
void readData(map<int, float>* data);
void lowestPrice();
void findSums(int n, vector<map<int, int>>* sumsList, map<int, float>* data);
//void findSum(map<int, int> currList, int x, int n, vector<map<int, int>>* sumsList);
void findSum(map<int, int> currList, int x, int n, vector<map<int, int>>* sumsList, map<int, float>* data);
float getPrice(map<int, int> set, map<int, float>* data);
template <typename S>
ostream& operator<<(ostream& os, const vector<S>& vector)
{
// Printing all the elements using <<
for (auto element : vector) {
os << element << " ";
}
return os;
}
bool operator==(map<int, int> m1, map<int, int> m2)
{
if(m1.size() != m2.size())
return false;
bool ret = true;
for(auto it = m1.begin(); it !=m1.end() && ret; it++)
{
if(ret && m1.count(it->first) != m2.count(it->first))
ret = false;
if(ret && m1.count(it->first) == 1)
{
if(m1.at(it->first) != m2.at(it->first))
ret = false;
}
}
return ret;
}
int main()
{
map<int, float> data;
readData(&data);
vector<map<int, int>> *sumsList;
sumsList = new vector<map<int, int>>;
findSums(40, sumsList, &data);
for(auto el : *sumsList)
{
for(auto it = el.begin(); it != el.end(); it++)
{
cout << it->first << "->" << it->second << " ";
}
cout << getPrice(el, &data) << endl;
}
return 0;
}
/* Returns the price of wings given a set of numbers of wings to buy.
* Returns -1 if the set contains a number that is not possible to buy.
*/
float getPrice(map<int, int> set, map<int, float>* data)
{
float price = 0;
for(auto it = set.begin(); it != set.end(); it++)
{
//If data doesn't contain an element of set, return -1
if(data->count(it->first) == 0)
return -1;
price += data->at(it->first) * it->second; //pricePerPacket * qtyOfPackets
}
return price;
}
/* Adds the elements of list.
* Suppose mapping is <num, qty>.
* Returns sum(num*qty)
*/
int getSum(map<int, int> list)
{
int sum = 0;
for(auto it = list.begin(); it != list.end(); it++)
sum += it->first * it->second;
return sum;
}
void findSums(int n, vector<map<int, int>>* sumsList, map<int, float>* data)
{
map<int, int> currList;
//Recur when currSum < n
auto it = data->begin();
while(it->first <= n && it != data->end())
{
findSum(currList, it->first, n, sumsList, data);
it++;
}
}
void findSum(map<int, int> currList, int x, int n, vector<map<int, int>>* sumsList, map<int, float>* data)
{
//Append x to currList
if(currList.count(x) == 0)
currList.emplace(x, 1);
else
{
int val = 1+ currList.at(x);
currList.erase(x);
currList.emplace(x, val);
}
//Determine current sum, check for return cases
int currSum = getSum(currList);
if(currSum > n)
return;
else if(currSum == n)
{
//Check to make sure no duplicates
for(auto list : *sumsList)
{
if(list == currList)
return;
}
sumsList->push_back(currList);
return;
}
//Recur when currSum < n
auto it = data->begin();
while(it->first <= n-x && it != data->end())
{
findSum(currList, it->first, n, sumsList, data);
it++;
}
}
void readData(map<int, float>* data)
{
ifstream file ("./data", ifstream::in);
if(file.is_open())
{
int i = 0;
while(!file.eof())
{
float wings, price;
string skipnl;
file >> wings;
file >> price;
data->emplace(wings, price);
getline(file, skipnl);
i++;
}
}
}

SAM 5 words with bitmaps

ThiccDaddyLOAF
0 likes • Oct 23, 2022
C++
//Leif Messinger
//Finds all sets of 5 5 letter words that don't have duplicate letters in either themselves or each other.
//First it reads the words in and puts them in groups of their bitmasks
//After that, we recurse on each group. Before doing that, we remove the group from the set of other groups to check it against.
#include <cstdio> //getchar, printf
#include <cassert> //assert
#include <vector>
#include <set>
#include <algorithm> //std::copy_if
#include <iterator> //std::back_inserter
#define CHECK_FOR_CRLF true
#define MIN_WORDS 5
#define MAX_WORDS 5
#define WORD_TOO_LONG(len) (len != 5)
const unsigned int charToBitmask(const char bruh){
assert(bruh >= 'a' && bruh <= 'z');
return (1 << (bruh - 'a'));
}
void printBitmask(unsigned int bitmask){
char start = 'a';
while(bitmask != 0){
if(bitmask & 1){
putchar(start);
}
bitmask >>= 1;
++start;
}
}
//Pointer needs to be deleted
const std::set<unsigned int>* getBitmasks(){
std::set<unsigned int>* bitmasksPointer = new std::set<unsigned int>;
std::set<unsigned int>& bitmasks = (*bitmasksPointer);
unsigned int bitmask = 0;
unsigned int wordLength = 0;
bool duplicateLetters = false;
for(char c = getchar(); c >= 0; c = getchar()){
if(CHECK_FOR_CRLF && c == '\r'){
continue;
}
if(c == '\n'){
if(!(WORD_TOO_LONG(wordLength) || duplicateLetters)) bitmasks.insert(bitmask);
bitmask = 0;
wordLength = 0;
duplicateLetters = false;
continue;
}
if((bitmask & charToBitmask(c)) != 0) duplicateLetters = true;
bitmask |= charToBitmask(c);
++wordLength;
}
return bitmasksPointer;
}
void printBitmasks(const std::vector<unsigned int>& bitmasks){
for(unsigned int bruh : bitmasks){
printBitmask(bruh);
putchar(','); putchar(' ');
}
puts("");
}
//Just to be clear, when I mean "word", I mean a group of words with the same letters.
void recurse(std::vector<unsigned int>& oldBitmasks, std::vector<unsigned int> history, const unsigned int currentBitmask){
//If there's not enough words left
if(oldBitmasks.size() + (-(history.size())) + (-MIN_WORDS) <= 0){
//If there's enough words
if(history.size() >= MIN_WORDS){
//Print the list
printBitmasks(history);
}
return;
//To make it faster, we can stop it after 5 words too
}else if(history.size() >= MAX_WORDS){
//Print the list
printBitmasks(history);
return;
}
//Thin out the array with only stuff that matches the currentBitmask.
std::vector<unsigned int> newBitmasks;
std::copy_if(oldBitmasks.begin(), oldBitmasks.end(), std::back_inserter(newBitmasks), [&currentBitmask](unsigned int bruh){
return (bruh & currentBitmask) == 0;
});
while(newBitmasks.size() > 0){
//I know this modifies 'oldBitmasks' too. It's intentional.
//This makes it so that the word is never involved in any of the child serches or any of the later searches in this while loop.
const unsigned int word = newBitmasks.back(); newBitmasks.pop_back();
std::vector<unsigned int> newHistory = history;
newHistory.push_back(word);
recurse(newBitmasks, newHistory, currentBitmask | word);
}
}
int main(){
const std::set<unsigned int>* bitmasksSet = getBitmasks();
std::vector<unsigned int> bitmasks(bitmasksSet->begin(), bitmasksSet->end());
delete bitmasksSet;
recurse(bitmasks, std::vector<unsigned int>(), 0);
return 0;
}

Daily: Find missing array value

aedrarian
0 likes • Dec 24, 2021
C++
/*
Good morning! Here's your coding interview problem for today.
This problem was asked by Stripe.
Given an array of integers, find the first missing positive integer in linear time and constant space. In other words, find the lowest positive integer that does not exist in the array. The array can contain duplicates and negative numbers as well.
For example, the input [3, 4, -1, 1] should give 2. The input [1, 2, 0] should give 3.
You can modify the input array in-place.
*/
#include <iostream>
using namespace std;
int calcMissing(int* input, int size)
{
int sum = 0;
int n = 1; //add one to account for missing value
for(int i = 0; i < size; i++)
{
if(input[i] > 0)
{
sum += input[i];
n++;
}
}
//If no numbers higher than 0, answer is 1
if(sum == 0)
return 1;
return (n*(n+1)/2) - sum; //Formula is expectedSum - actualSum
/* expectedSum = n*(n+1)/2, the formula for sum(1, n) */
}
int main()
{
cout << calcMissing(new int[4]{3, 4, -1, 1}, 4) << endl;
cout << calcMissing(new int[3]{1, 2, 0}, 3) << endl;
//No positive numbers
cout << calcMissing(new int[1]{0}, 1) << endl;
}