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arr = [] // empty arrayconst isEmpty = arr => !Array.isArray(arr) || arr.length === 0;// ExamplesisEmpty([]); // trueisEmpty([1, 2, 3]); // false
const countSubstrings = (str, searchValue) => {let count = 0,i = 0;while (true) {const r = str.indexOf(searchValue, i);if (r !== -1) [count, i] = [count + 1, r + 1];else return count;}};countSubstrings('tiktok tok tok tik tok tik', 'tik'); // 3countSubstrings('tutut tut tut', 'tut'); // 4
const toFixed = (n, fixed) => ~~(Math.pow(10, fixed) * n) / Math.pow(10, fixed);// ExamplestoFixed(25.198726354, 1); // 25.1toFixed(25.198726354, 2); // 25.19toFixed(25.198726354, 3); // 25.198toFixed(25.198726354, 4); // 25.1987toFixed(25.198726354, 5); // 25.19872toFixed(25.198726354, 6); // 25.198726
function printHeap(heap, index, level) {if (index >= heap.length) {return;}console.log(" ".repeat(level) + heap[index]);printHeap(heap, 2 * index + 1, level + 1);printHeap(heap, 2 * index + 2, level + 1);}//You can call this function by passing in the heap array and the index of the root node, which is typically 0, and level = 0.let heap = [3, 8, 7, 15, 17, 30, 35, 2, 4, 5, 9];printHeap(heap,0,0)
// There are n rings and each ring is either red, green, or blue. The rings are distributed across ten rods labeled from 0 to 9.// You are given a string rings of length 2n that describes the n rings that are placed onto the rods. Every two characters in rings forms a color-position pair that is used to describe each ring where:// The first character of the ith pair denotes the ith ring's color ('R', 'G', 'B').// The second character of the ith pair denotes the rod that the ith ring is placed on ('0' to '9').// For example, "R3G2B1" describes n == 3 rings: a red ring placed onto the rod labeled 3, a green ring placed onto the rod labeled 2, and a blue ring placed onto the rod labeled 1.// Return the number of rods that have all three colors of rings on them.let rings = "B0B6G0R6R0R6G9";var countPoints = function(rings) {let sum = 0;// Always 10 Rodsfor (let i = 0; i < 10; i++) {if (rings.includes(`B${i}`) && rings.includes(`G${i}`) && rings.includes(`R${i}`)) {sum+=1;}}return sum;};console.log(countPoints(rings));
const getURLParameters = url =>(url.match(/([^?=&]+)(=([^&]*))/g) || []).reduce((a, v) => ((a[v.slice(0, v.indexOf('='))] = v.slice(v.indexOf('=') + 1)), a),{});