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const getTimezone = () => Intl.DateTimeFormat().resolvedOptions().timeZone;// ExamplegetTimezone();
const unzipWith = (arr, fn) =>arr.reduce((acc, val) => (val.forEach((v, i) => acc[i].push(v)), acc),Array.from({length: Math.max(...arr.map(x => x.length))}).map(x => [])).map(val => fn(...val));unzipWith([[1, 10, 100],[2, 20, 200],],(...args) => args.reduce((acc, v) => acc + v, 0));// [3, 30, 300]
// There are n rings and each ring is either red, green, or blue. The rings are distributed across ten rods labeled from 0 to 9.// You are given a string rings of length 2n that describes the n rings that are placed onto the rods. Every two characters in rings forms a color-position pair that is used to describe each ring where:// The first character of the ith pair denotes the ith ring's color ('R', 'G', 'B').// The second character of the ith pair denotes the rod that the ith ring is placed on ('0' to '9').// For example, "R3G2B1" describes n == 3 rings: a red ring placed onto the rod labeled 3, a green ring placed onto the rod labeled 2, and a blue ring placed onto the rod labeled 1.// Return the number of rods that have all three colors of rings on them.let rings = "B0B6G0R6R0R6G9";var countPoints = function(rings) {let sum = 0;// Always 10 Rodsfor (let i = 0; i < 10; i++) {if (rings.includes(`B${i}`) && rings.includes(`G${i}`) && rings.includes(`R${i}`)) {sum+=1;}}return sum;};console.log(countPoints(rings));
const reverse = str => str.split('').reverse().join('');reverse('hello world');// Result: 'dlrow olleh'
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const head = arr => (arr && arr.length ? arr[0] : undefined);head([1, 2, 3]); // 1head([]); // undefinedhead(null); // undefinedhead(undefined); // undefined