• Oct 15, 2022 •CodeCatch
2 likes • 9 views
var invertTree = function(root) { const reverseNode = node => { if (node == null) { return null } reverseNode(node.left); reverseNode(node.right); let holdLeft = node.left; node.left = node.right; node.right = holdLeft; return node; } return reverseNode(root); };
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const express = require('express') const app = express() const port = 3000 app.get('/', (req, res) => { res.send('Hello World!') }) app.listen(port, () => { console.log(`Example app listening on port ${port}`) })
• Nov 19, 2022 •CodeCatch
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let nums = [1,2,3,1] var containsDuplicate = function(nums) { let obj = {}; for(let i =0; i< nums.length; i++){ if(obj[nums[i]]){ obj[nums[i]] += 1; return true; }else{ obj[nums[i]] = 1; } } return false; }; console.log(containsDuplicate(nums));
const primes = num => { let arr = Array.from({ length: num - 1 }).map((x, i) => i + 2), sqroot = Math.floor(Math.sqrt(num)), numsTillSqroot = Array.from({ length: sqroot - 1 }).map((x, i) => i + 2); numsTillSqroot.forEach(x => (arr = arr.filter(y => y % x !== 0 || y === x))); return arr; }; primes(10); // [2, 3, 5, 7]
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const getSubsets = arr => arr.reduce((prev, curr) => prev.concat(prev.map(k => k.concat(curr))), [[]]); // Examples getSubsets([1, 2]); // [[], [1], [2], [1, 2]] getSubsets([1, 2, 3]); // [[], [1], [2], [1, 2], [3], [1, 3], [2, 3], [1, 2, 3]]
const union = (...arr) => [...new Set(arr.flat())]; // Example union([1, 2], [2, 3], [3]); // [1, 2, 3]