• Nov 19, 2022 •CodeCatch
0 likes • 0 views
//JavaScript program to swap two variables //take input from the users let a = prompt('Enter the first variable: '); let b = prompt('Enter the second variable: '); //using destructuring assignment [a, b] = [b, a]; console.log(`The value of a after swapping: ${a}`); console.log(`The value of b after swapping: ${b}`);
0 likes • 2 views
const luhnCheck = num => { let arr = (num + '') .split('') .reverse() .map(x => parseInt(x)); let lastDigit = arr.splice(0, 1)[0]; let sum = arr.reduce( (acc, val, i) => (i % 2 !== 0 ? acc + val : acc + ((val *= 2) > 9 ? val - 9 : val)), 0 ); sum += lastDigit; return sum % 10 === 0; }; luhnCheck('4485275742308327'); // true luhnCheck(6011329933655299); // true luhnCheck(123456789); // false
• Sep 13, 2023 •C S
0 likes • 11 views
/** * @param {number[]} nums * @return {number[]} */ var productExceptSelf = function(nums) { var output = []; var leftMult = 1; var rightMult = 1; for (var i=nums.length - 1; i >= 0; i--) { output[i] = rightMult; rightMult *= nums[i]; console.log({output: JSON.stringify(output), i}) } for (var j=0; j < nums.length; j++) { output[j] *= leftMult; leftMult *= nums[j]; console.log({output: JSON.stringify(output), j}) } return output; }; console.log(productExceptSelf([1, 2, 3, 4]))
0 likes • 1 view
// There are n rings and each ring is either red, green, or blue. The rings are distributed across ten rods labeled from 0 to 9. // You are given a string rings of length 2n that describes the n rings that are placed onto the rods. Every two characters in rings forms a color-position pair that is used to describe each ring where: // The first character of the ith pair denotes the ith ring's color ('R', 'G', 'B'). // The second character of the ith pair denotes the rod that the ith ring is placed on ('0' to '9'). // For example, "R3G2B1" describes n == 3 rings: a red ring placed onto the rod labeled 3, a green ring placed onto the rod labeled 2, and a blue ring placed onto the rod labeled 1. // Return the number of rods that have all three colors of rings on them. let rings = "B0B6G0R6R0R6G9"; var countPoints = function(rings) { let sum = 0; // Always 10 Rods for (let i = 0; i < 10; i++) { if (rings.includes(`B${i}`) && rings.includes(`G${i}`) && rings.includes(`R${i}`)) { sum+=1; } } return sum; }; console.log(countPoints(rings));
const formatDuration = ms => { if (ms < 0) ms = -ms; const time = { day: Math.floor(ms / 86400000), hour: Math.floor(ms / 3600000) % 24, minute: Math.floor(ms / 60000) % 60, second: Math.floor(ms / 1000) % 60, millisecond: Math.floor(ms) % 1000 }; return Object.entries(time) .filter(val => val[1] !== 0) .map(([key, val]) => `${val} ${key}${val !== 1 ? 's' : ''}`) .join(', '); }; formatDuration(1001); // '1 second, 1 millisecond' formatDuration(34325055574); // '397 days, 6 hours, 44 minutes, 15 seconds, 574 milliseconds'
0 likes • 3 views
const euclideanDistance = (a, b) => Math.hypot(...Object.keys(a).map(k => b[k] - a[k])); euclideanDistance([1, 1], [2, 3]); // ~2.2361 euclideanDistance([1, 1, 1], [2, 3, 2]); // ~2.4495