• Feb 4, 2021 •aedrarian
0 likes • 0 views
#include <iostream> using namespace std; main { cout << "No tabbing. That's very sad :(\n"; cout << "No in-editor highlighting either :(((\n"; cout << "Descriptions might be niice too."; }
• Dec 24, 2021 •aedrarian
3 likes • 21 views
/* Good morning! Here's your coding interview problem for today. This problem was asked by Stripe. Given an array of integers, find the first missing positive integer in linear time and constant space. In other words, find the lowest positive integer that does not exist in the array. The array can contain duplicates and negative numbers as well. For example, the input [3, 4, -1, 1] should give 2. The input [1, 2, 0] should give 3. You can modify the input array in-place. */ #include <iostream> using namespace std; int calcMissing(int* input, int size) { int sum = 0; int n = 1; //add one to account for missing value for(int i = 0; i < size; i++) { if(input[i] > 0) { sum += input[i]; n++; } } //If no numbers higher than 0, answer is 1 if(sum == 0) return 1; return (n*(n+1)/2) - sum; //Formula is expectedSum - actualSum /* expectedSum = n*(n+1)/2, the formula for sum(1, n) */ } int main() { cout << calcMissing(new int[4]{3, 4, -1, 1}, 4) << endl; cout << calcMissing(new int[3]{1, 2, 0}, 3) << endl; //No positive numbers cout << calcMissing(new int[1]{0}, 1) << endl; }
• Aug 25, 2023 •LeifMessinger
1 like • 12 views
#include <iostream> int main(){ const char* const hello = "Hello, world!"; const char* bruh = hello; char* const yeet = hello; std::cout << bruh << std::endl; std::cout << yeet << std::endl; return 0; } /* Place your bets! Will the program: a.) Print "Hello, world!" twice? b.) Compile error on line 5 (bruh initialize line) because the pointer gets implicit cast to non-const? c.) Compile error on line 7 (yeet initialize line) because the char gets implicit cast to non-const? d.) Both b and c? e.) Compile error line 11 (print yeet) because the pointer is constant and can't be incremented f.) Print "Hello, world!" then print the pointer address in hexadecimal g.) Both b and e? h.) Both c and e? i.) B, c, and e? */ // The answer is in this base 64 string: // 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
• Apr 16, 2023 •LeifMessinger
#include <iostream> #include <string> //Should already be in iostream #include <cstdlib> //A word score adds up the character values. a-z gets mapped to 1-26 for the values of the characters. //wordScore [wordValue] //Pipe in the input into stdin, or type the words yourself. //Lowercase words only int characterValue(const char b){ return ((b >= 'a') && (b <= 'z'))? ((b - 'a') + 1) : 0; } int main(int argc, char** argv){ //The first argument specifies if you are trying to look for a certain word score int wordValue = (argc > 1)? std::atoi(argv[1]) : 0; std::string line; while(std::getline(std::cin, line)){ int sum = 0; for(const char c : line){ sum += characterValue(c); } if(wordValue){ //If wordValue is 0 or the sum is the correct value if(wordValue == sum){ std::cout << line << std::endl; } } else { std::cout << sum << "\t" << line << std::endl; } } return 0; }
• Apr 15, 2025 •hasnaoui1
0 likes • 4 views
int main()
• Jun 30, 2023 •Iceman_71
0 likes • 8 views
#include <iostream> using namespace std; int main() { int arr[] = {5, 1, 4, 20, 10, 2, 13, 11, 6, 21}; int greed[] = {0, 0, 0, 0}; int k = 0; int i; int set_index; while (k < 4) { i = 0; while (i < 10) { if (arr[i] > greed[k]) { greed[k] = arr[i]; set_index = i; } i++; } arr[set_index] = 0; k++; } cout << greed[0] << " " << greed[1] << " " << greed[2] << " " << greed[3] << endl; }