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def when(predicate, when_true):return lambda x: when_true(x) if predicate(x) else xdouble_even_numbers = when(lambda x: x % 2 == 0, lambda x : x * 2)print(double_even_numbers(2)) # 4print(double_even_numbers(1)) # 1
filename = "data.txt"data = "Hello, World!"with open(filename, "a") as file:file.write(data)
def max_n(lst, n = 1):return sorted(lst, reverse = True)[:n]max_n([1, 2, 3]) # [3]max_n([1, 2, 3], 2) # [3, 2]
def key_of_min(d):return min(d, key = d.get)key_of_min({'a':4, 'b':0, 'c':13}) # b
# Function to check Armstrong numberdef is_armstrong_number(number):# Convert number to string to iterate over its digitsnum_str = str(number)# Calculate the sum of the cubes of each digitdigit_sum = sum(int(digit) ** len(num_str) for digit in num_str)# Compare the sum with the original numberif digit_sum == number:return Trueelse:return False# Prompt user for a numbernumber = int(input("Enter a number: "))# Check if the number is an Armstrong numberif is_armstrong_number(number):print(number, "is an Armstrong number.")else:print(number, "is not an Armstrong number.")
# Python code to demonstrate# method to remove i'th character# Naive Method# Initializing Stringtest_str = "CodeCatch"# Printing original stringprint ("The original string is : " + test_str)# Removing char at pos 3# using loopnew_str = ""for i in range(len(test_str)):if i != 2:new_str = new_str + test_str[i]# Printing string after removalprint ("The string after removal of i'th character : " + new_str)