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curry function

Nov 19, 2022CodeCatch
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Sieve of Eratosthenes

Nov 19, 2022CodeCatch

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# Given a number n, print all primes smaller than or equal to n. It is also given that n is a small number.
# For example, if n is 10, the output should be “2, 3, 5, 7”. If n is 20, the output should be “2, 3, 5, 7, 11, 13, 17, 19”.
# Python program to print all primes smaller than or equal to
# n using Sieve of Eratosthenes
def SieveOfEratosthenes(n):
# Create a boolean array "prime[0..n]" and initialize
# all entries it as true. A value in prime[i] will
# finally be false if i is Not a prime, else true.
prime = [True for i in range(n + 1)]
p = 2
while (p * p <= n):
# If prime[p] is not changed, then it is a prime
if (prime[p] == True):
# Update all multiples of p
for i in range(p * 2, n + 1, p):
prime[i] = False
p += 1
prime[0]= False
prime[1]= False
# Print all prime numbers
for p in range(n + 1):
if prime[p]:
print (p)
# driver program
if __name__=='__main__':
n = 30
print("Following are the prime numbers smaller")
print("than or equal to ", n)
print("than or equal to ", n)
SieveOfEratosthenes(n)

Untitled

Jul 24, 2024AustinLeath

0 likes • 3 views

from statistics import median, mean, mode
def print_stats(array):
print(array)
print("median =", median(array))
print("mean =", mean(array))
print("mode =", mode(array))
print()
print_stats([1, 2, 3, 3, 4])
print_stats([1, 2, 3, 3])

delay time lambda

Nov 19, 2022CodeCatch

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from time import sleep
def delay(fn, ms, *args):
sleep(ms / 1000)
return fn(*args)
delay(lambda x: print(x), 1000, 'later') # prints 'later' after one second

Append to a file

Jun 1, 2023CodeCatch

0 likes • 1 view

filename = "data.txt"
data = "Hello, World!"
with open(filename, "a") as file:
file.write(data)

Reverse a linked list

Nov 19, 2022CodeCatch

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# Python program to reverse a linked list
# Time Complexity : O(n)
# Space Complexity : O(n) as 'next'
#variable is getting created in each loop.
# Node class
class Node:
# Constructor to initialize the node object
def __init__(self, data):
self.data = data
self.next = None
class LinkedList:
# Function to initialize head
def __init__(self):
self.head = None
# Function to reverse the linked list
def reverse(self):
prev = None
current = self.head
while(current is not None):
next = current.next
current.next = prev
prev = current
current = next
self.head = prev
# Function to insert a new node at the beginning
def push(self, new_data):
new_node = Node(new_data)
new_node.next = self.head
self.head = new_node
# Utility function to print the linked LinkedList
def printList(self):
temp = self.head
while(temp):
print temp.data,
temp = temp.next
# Driver program to test above functions
llist = LinkedList()
llist.push(20)
llist.push(4)
llist.push(15)
llist.push(85)
print "Given Linked List"
llist.printList()
llist.reverse()
print "\nReversed Linked List"
llist.printList()

Sort a List of Strings

Oct 15, 2022CodeCatch

1 like • 2 views

my_list = ["blue", "red", "green"]
#1- Using sort or srted directly or with specifc keys
my_list.sort() #sorts alphabetically or in an ascending order for numeric data
my_list = sorted(my_list, key=len) #sorts the list based on the length of the strings from shortest to longest.
# You can use reverse=True to flip the order
#2- Using locale and functools
import locale
from functools import cmp_to_key
my_list = sorted(my_list, key=cmp_to_key(locale.strcoll))