• Nov 19, 2022 •CodeCatch
0 likes • 0 views
const toFixed = (n, fixed) => ~~(Math.pow(10, fixed) * n) / Math.pow(10, fixed); // Examples toFixed(25.198726354, 1); // 25.1 toFixed(25.198726354, 2); // 25.19 toFixed(25.198726354, 3); // 25.198 toFixed(25.198726354, 4); // 25.1987 toFixed(25.198726354, 5); // 25.19872 toFixed(25.198726354, 6); // 25.198726
• Nov 18, 2022 •AustinLeath
// Get the text that the user has selected const getSelectedText = () => window.getSelection().toString(); getSelectedText();
0 likes • 3 views
const flat = arr => [].concat.apply([], arr.map(a => Array.isArray(a) ? flat(a) : a)); // Or const flat = arr => arr.reduce((a, b) => Array.isArray(b) ? [...a, ...flat(b)] : [...a, b], []); // Or // See the browser compatibility at https://caniuse.com/#feat=array-flat const flat = arr => arr.flat(); // Example flat(['cat', ['lion', 'tiger']]); // ['cat', 'lion', 'tiger']
• Nov 20, 2022 •Helper
0 likes • 2 views
new StringBuilder(hi).reverse().toString()
const longestPalindrome = (s) => { if(s.length === 1) return s const odd = longestOddPalindrome(s) const even = longestEvenPalindrome(s) if(odd.length >= even.length) return odd if(even.length > odd.length) return even }; const longestOddPalindrome = (s) => { let longest = 0 let longestSubStr = "" for(let i = 1; i < s.length; i++) { let currentLongest = 1 let currentLongestSubStr = "" let left = i - 1 let right = i + 1 while(left >= 0 && right < s.length) { const leftLetter = s[left] const rightLetter = s[right] left-- right++ if(leftLetter === rightLetter) { currentLongest += 2 currentLongestSubStr = s.slice(left+1, right) } else break } if(currentLongest > longest) { if(currentLongestSubStr) longestSubStr = currentLongestSubStr else longestSubStr = s[i] longest = currentLongest } } return longestSubStr } const longestEvenPalindrome = (s) => { let longest = 0 let longestSubStr = "" for(let i = 0; i < s.length - 1; i++) { if(s[i] !== s[i+1]) continue; let currentLongest = 2 let currentLongestSubStr = "" let left = i - 1 let right = i + 2 while(left >= 0 && right < s.length) { const leftLetter = s[left] const rightLetter = s[right] left-- right++ if(leftLetter === rightLetter) { currentLongest += 2 currentLongestSubStr = s.slice(left+1, right) } else break } if(currentLongest > longest) { if(currentLongestSubStr) longestSubStr = currentLongestSubStr else longestSubStr = s[i] + s[i+1] longest = currentLongest } } return longestSubStr } console.log(longestPalindrome("babad"))
const hammingDistance = (num1, num2) => ((num1 ^ num2).toString(2).match(/1/g) || '').length; hammingDistance(2, 3); // 1