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greatest common denominator

Nov 19, 2022CodeCatch
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More JavaScript Posts

deep merge objects

Nov 19, 2022CodeCatch

0 likes • 3 views

const deepMerge = (a, b, fn) =>
[...new Set([...Object.keys(a), ...Object.keys(b)])].reduce(
(acc, key) => ({ ...acc, [key]: fn(key, a[key], b[key]) }),
{}
);
deepMerge(
{ a: true, b: { c: [1, 2, 3] } },
{ a: false, b: { d: [1, 2, 3] } },
(key, a, b) => (key === 'a' ? a && b : Object.assign({}, a, b))
);
// { a: false, b: { c: [ 1, 2, 3 ], d: [ 1, 2, 3 ] } }

server js

Apr 10, 2025hasnaoui1

0 likes • 4 views

const express = require('express')
const mongoose = require('mongoose')
const cors = require('cors')
const dotenv = require('dotenv')
const server = express()
dotenv.config()
server.use(express.json())
server.get('/' , (req , res)=>{
res.send('Hello')
})
//4.lancement du serveur
server.listen(process.env.PORT , ()=>{
console.log('server run on http://localhost:'+process.env.PORT)
})

Longest Palindromic Substring

Nov 19, 2022CodeCatch

0 likes • 2 views

const longestPalindrome = (s) => {
if(s.length === 1) return s
const odd = longestOddPalindrome(s)
const even = longestEvenPalindrome(s)
if(odd.length >= even.length) return odd
if(even.length > odd.length) return even
};
const longestOddPalindrome = (s) => {
let longest = 0
let longestSubStr = ""
for(let i = 1; i < s.length; i++) {
let currentLongest = 1
let currentLongestSubStr = ""
let left = i - 1
let right = i + 1
while(left >= 0 && right < s.length) {
const leftLetter = s[left]
const rightLetter = s[right]
left--
right++
if(leftLetter === rightLetter) {
currentLongest += 2
currentLongestSubStr = s.slice(left+1, right)
} else break
}
if(currentLongest > longest) {
if(currentLongestSubStr) longestSubStr = currentLongestSubStr
else longestSubStr = s[i]
longest = currentLongest
}
}
return longestSubStr
}
const longestEvenPalindrome = (s) => {
let longest = 0
let longestSubStr = ""
for(let i = 0; i < s.length - 1; i++) {
if(s[i] !== s[i+1]) continue;
let currentLongest = 2
let currentLongestSubStr = ""
let left = i - 1
let right = i + 2
while(left >= 0 && right < s.length) {
const leftLetter = s[left]
const rightLetter = s[right]
left--
right++
if(leftLetter === rightLetter) {
currentLongest += 2
currentLongestSubStr = s.slice(left+1, right)
} else break
}
if(currentLongest > longest) {
if(currentLongestSubStr) longestSubStr = currentLongestSubStr
else longestSubStr = s[i] + s[i+1]
longest = currentLongest
}
}
return longestSubStr
}
console.log(longestPalindrome("babad"))

hamming distance

Nov 19, 2022CodeCatch

0 likes • 0 views

const hammingDistance = (num1, num2) =>
((num1 ^ num2).toString(2).match(/1/g) || '').length;
hammingDistance(2, 3); // 1

Redux Setup

Mar 11, 2021C S

0 likes • 2 views

import { configureStore } from "@reduxjs/toolkit";
import { combineReducers } from "redux";
import profile from "./profile";
import auth from "./auth";
import alert from "./alert";
const reducer = combineReducers({
profile,
auth,
alert,
});
const store = configureStore({ reducer });
export default store;

CodeCatchCrasher

Feb 11, 2021LeifMessinger

0 likes • 2 views

function spam(times = 1,log = true){
for(let i = 0; i < times; i++){
$.get("backend-search.php", {term: (" "+Date.now())}).done(function(data){
if(log) console.log(data);
});
}
}
spam(100000);