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import sys# sample TuplesTuple1 = ("A", 1, "B", 2, "C", 3)Tuple2 = ("Geek1", "Raju", "Geek2", "Nikhil", "Geek3", "Deepanshu")Tuple3 = ((1, "Lion"), ( 2, "Tiger"), (3, "Fox"), (4, "Wolf"))# print the sizes of sample Tuplesprint("Size of Tuple1: " + str(sys.getsizeof(Tuple1)) + "bytes")print("Size of Tuple2: " + str(sys.getsizeof(Tuple2)) + "bytes")print("Size of Tuple3: " + str(sys.getsizeof(Tuple3)) + "bytes")
#Loop back to this point once code finishesloop = 1while (loop < 10):#All the questions that the program asks the usernoun = input("Choose a noun: ")p_noun = input("Choose a plural noun: ")noun2 = input("Choose a noun: ")place = input("Name a place: ")adjective = input("Choose an adjective (Describing word): ")noun3 = input("Choose a noun: ")#Displays the story based on the users inputprint ("------------------------------------------")print ("Be kind to your",noun,"- footed", p_noun)print ("For a duck may be somebody's", noun2,",")print ("Be kind to your",p_noun,"in",place)print ("Where the weather is always",adjective,".")print ()print ("You may think that is this the",noun3,",")print ("Well it is.")print ("------------------------------------------")#Loop back to "loop = 1"loop = loop + 1
import mathdef factorial(n):print(math.factorial(n))return (math.factorial(n))factorial(5)factorial(10)factorial(15)
# Python program for Bitonic Sort. Note that this program# works only when size of input is a power of 2.# The parameter dir indicates the sorting direction, ASCENDING# or DESCENDING; if (a[i] > a[j]) agrees with the direction,# then a[i] and a[j] are interchanged.*/def compAndSwap(a, i, j, dire):if (dire==1 and a[i] > a[j]) or (dire==0 and a[i] > a[j]):a[i],a[j] = a[j],a[i]# It recursively sorts a bitonic sequence in ascending order,# if dir = 1, and in descending order otherwise (means dir=0).# The sequence to be sorted starts at index position low,# the parameter cnt is the number of elements to be sorted.def bitonicMerge(a, low, cnt, dire):if cnt > 1:k = cnt/2for i in range(low , low+k):compAndSwap(a, i, i+k, dire)bitonicMerge(a, low, k, dire)bitonicMerge(a, low+k, k, dire)# This funcion first produces a bitonic sequence by recursively# sorting its two halves in opposite sorting orders, and then# calls bitonicMerge to make them in the same orderdef bitonicSort(a, low, cnt,dire):if cnt > 1:k = cnt/2bitonicSort(a, low, k, 1)bitonicSort(a, low+k, k, 0)bitonicMerge(a, low, cnt, dire)# Caller of bitonicSort for sorting the entire array of length N# in ASCENDING orderdef sort(a,N, up):bitonicSort(a,0, N, up)# Driver code to test abovea = [3, 7, 4, 8, 6, 2, 1, 5]n = len(a)up = 1sort(a, n, up)print ("\n\nSorted array is")for i in range(n):print("%d" %a[i]),
def print_x_pattern(size):i,j = 0,size - 1while j >= 0 and i < size:initial_spaces = ' '*min(i,j)middle_spaces = ' '*(abs(i - j) - 1)final_spaces = ' '*(size - 1 - max(i,j))if j == i:print(initial_spaces + '*' + final_spaces)else:print(initial_spaces + '*' + middle_spaces + '*' + final_spaces)i += 1j -= 1print_x_pattern(7)
# Function to multiply two matricesdef multiply_matrices(matrix1, matrix2):# Check if the matrices can be multipliedif len(matrix1[0]) != len(matrix2):print("Error: The number of columns in the first matrix must be equal to the number of rows in the second matrix.")return None# Create the result matrix filled with zerosresult = [[0 for _ in range(len(matrix2[0]))] for _ in range(len(matrix1))]# Perform matrix multiplicationfor i in range(len(matrix1)):for j in range(len(matrix2[0])):for k in range(len(matrix2)):result[i][j] += matrix1[i][k] * matrix2[k][j]return result# Example matricesmatrix1 = [[1, 2, 3],[4, 5, 6],[7, 8, 9]]matrix2 = [[10, 11],[12, 13],[14, 15]]# Multiply the matricesresult_matrix = multiply_matrices(matrix1, matrix2)# Display the resultif result_matrix is not None:print("Result:")for row in result_matrix:print(row)