Finding NULL values within set
0 likes • Oct 7, 2022 • 1 view
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# Given a number n, print all primes smaller than or equal to n. It is also given that n is a small number.# For example, if n is 10, the output should be “2, 3, 5, 7”. If n is 20, the output should be “2, 3, 5, 7, 11, 13, 17, 19”.# Python program to print all primes smaller than or equal to# n using Sieve of Eratosthenesdef SieveOfEratosthenes(n):# Create a boolean array "prime[0..n]" and initialize# all entries it as true. A value in prime[i] will# finally be false if i is Not a prime, else true.prime = [True for i in range(n + 1)]p = 2while (p * p <= n):# If prime[p] is not changed, then it is a primeif (prime[p] == True):# Update all multiples of pfor i in range(p * 2, n + 1, p):prime[i] = Falsep += 1prime[0]= Falseprime[1]= False# Print all prime numbersfor p in range(n + 1):if prime[p]:print (p)# driver programif __name__=='__main__':n = 30print("Following are the prime numbers smaller")print("than or equal to ", n)print("than or equal to ", n)SieveOfEratosthenes(n)
import os# Get the current directorycurrent_dir = os.getcwd()# Loop through each file in the current directoryfor filename in os.listdir(current_dir):# Check if the file name starts with a number followed by a period and a spaceif filename[0].isdigit() and filename[1] == '.' and filename[2] == ' ':# Remove the number, period, and space from the file namenew_filename = filename[3:]# Rename the fileos.rename(os.path.join(current_dir, filename), os.path.join(current_dir, new_filename))
primes=[]products=[]def prime(num):if num > 1:for i in range(2,num):if (num % i) == 0:return Falseelse:primes.append(num)return Truefor n in range(30,1000):if len(primes) >= 20:break;else:prime(n)for previous, current in zip(primes[::2], primes[1::2]):products.append(previous * current)print (products)
# Python program for implementation of Bubble Sortdef bubbleSort(arr):n = len(arr)# Traverse through all array elementsfor i in range(n-1):# range(n) also work but outer loop will repeat one time more than needed.# Last i elements are already in placefor j in range(0, n-i-1):# traverse the array from 0 to n-i-1# Swap if the element found is greater# than the next elementif arr[j] > arr[j+1] :arr[j], arr[j+1] = arr[j+1], arr[j]# Driver code to test abovearr = [64, 34, 25, 12, 22, 11, 90]bubbleSort(arr)print ("Sorted array is:")for i in range(len(arr)):print ("%d" %arr[i]),
def hex_to_rgb(hex):return tuple(int(hex[i:i+2], 16) for i in (0, 2, 4))hex_to_rgb('FFA501') # (255, 165, 1)
# @return a list of strings, [s1, s2]def letterCombinations(self, digits):if '' == digits: return []kvmaps = {'2': 'abc','3': 'def','4': 'ghi','5': 'jkl','6': 'mno','7': 'pqrs','8': 'tuv','9': 'wxyz'}return reduce(lambda acc, digit: [x + y for x in acc for y in kvmaps[digit]], digits, [''])