• Nov 19, 2022 •CodeCatch
0 likes • 2 views
const longestPalindrome = (s) => { if(s.length === 1) return s const odd = longestOddPalindrome(s) const even = longestEvenPalindrome(s) if(odd.length >= even.length) return odd if(even.length > odd.length) return even }; const longestOddPalindrome = (s) => { let longest = 0 let longestSubStr = "" for(let i = 1; i < s.length; i++) { let currentLongest = 1 let currentLongestSubStr = "" let left = i - 1 let right = i + 1 while(left >= 0 && right < s.length) { const leftLetter = s[left] const rightLetter = s[right] left-- right++ if(leftLetter === rightLetter) { currentLongest += 2 currentLongestSubStr = s.slice(left+1, right) } else break } if(currentLongest > longest) { if(currentLongestSubStr) longestSubStr = currentLongestSubStr else longestSubStr = s[i] longest = currentLongest } } return longestSubStr } const longestEvenPalindrome = (s) => { let longest = 0 let longestSubStr = "" for(let i = 0; i < s.length - 1; i++) { if(s[i] !== s[i+1]) continue; let currentLongest = 2 let currentLongestSubStr = "" let left = i - 1 let right = i + 2 while(left >= 0 && right < s.length) { const leftLetter = s[left] const rightLetter = s[right] left-- right++ if(leftLetter === rightLetter) { currentLongest += 2 currentLongestSubStr = s.slice(left+1, right) } else break } if(currentLongest > longest) { if(currentLongestSubStr) longestSubStr = currentLongestSubStr else longestSubStr = s[i] + s[i+1] longest = currentLongest } } return longestSubStr } console.log(longestPalindrome("babad"))
• Jan 26, 2023 •AustinLeath
0 likes • 6 views
function printHeap(heap, index, level) { if (index >= heap.length) { return; } console.log(" ".repeat(level) + heap[index]); printHeap(heap, 2 * index + 1, level + 1); printHeap(heap, 2 * index + 2, level + 1); } //You can call this function by passing in the heap array and the index of the root node, which is typically 0, and level = 0. let heap = [3, 8, 7, 15, 17, 30, 35, 2, 4, 5, 9]; printHeap(heap,0,0)
const powerset = arr => arr.reduce((a, v) => a.concat(a.map(r => r.concat(v))), [[]]); powerset([1, 2]); // [[], [1], [2], [1, 2]]
• Oct 15, 2022 •CodeCatch
2 likes • 9 views
var invertTree = function(root) { const reverseNode = node => { if (node == null) { return null } reverseNode(node.left); reverseNode(node.right); let holdLeft = node.left; node.left = node.right; node.right = holdLeft; return node; } return reverseNode(root); };
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const binomialCoefficient = (n, k) => { if (Number.isNaN(n) || Number.isNaN(k)) return NaN; if (k < 0 || k > n) return 0; if (k === 0 || k === n) return 1; if (k === 1 || k === n - 1) return n; if (n - k < k) k = n - k; let res = n; for (let j = 2; j <= k; j++) res *= (n - j + 1) / j; return Math.round(res); }; binomialCoefficient(8, 2); // 28
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const MongoClient = require('mongodb').MongoClient; const assert = require('assert'); // Connection URL const url = 'mongodb://localhost:27017'; // Database Name const dbName = 'myproject'; // Use connect method to connect to the server MongoClient.connect(url, function(err, client) { assert.equal(null, err); console.log("Connected successfully to server"); const db = client.db(dbName); client.close(); });