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Mee6 Spam Calculator

0 likes • Mar 10, 2022
JavaScript
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JS Test

ThiccDaddyLOAF
0 likes • Mar 9, 2021
JavaScript
alert("bruh")

Truncate to fixed decimal

CodeCatch
0 likes • Nov 19, 2022
JavaScript
const toFixed = (n, fixed) => ~~(Math.pow(10, fixed) * n) / Math.pow(10, fixed);
// Examples
toFixed(25.198726354, 1); // 25.1
toFixed(25.198726354, 2); // 25.19
toFixed(25.198726354, 3); // 25.198
toFixed(25.198726354, 4); // 25.1987
toFixed(25.198726354, 5); // 25.19872
toFixed(25.198726354, 6); // 25.198726

K-means clustering

CodeCatch
0 likes • Nov 19, 2022
JavaScript
const kMeans = (data, k = 1) => {
const centroids = data.slice(0, k);
const distances = Array.from({ length: data.length }, () =>
Array.from({ length: k }, () => 0)
);
const classes = Array.from({ length: data.length }, () => -1);
let itr = true;
while (itr) {
itr = false;
for (let d in data) {
for (let c = 0; c < k; c++) {
distances[d][c] = Math.hypot(
...Object.keys(data[0]).map(key => data[d][key] - centroids[c][key])
);
}
const m = distances[d].indexOf(Math.min(...distances[d]));
if (classes[d] !== m) itr = true;
classes[d] = m;
}
for (let c = 0; c < k; c++) {
centroids[c] = Array.from({ length: data[0].length }, () => 0);
const size = data.reduce((acc, _, d) => {
if (classes[d] === c) {
acc++;
for (let i in data[0]) centroids[c][i] += data[d][i];
}
return acc;
}, 0);
for (let i in data[0]) {
centroids[c][i] = parseFloat(Number(centroids[c][i] / size).toFixed(2));
}
}
}
return classes;
};
kMeans([[0, 0], [0, 1], [1, 3], [2, 0]], 2); // [0, 1, 1, 0]

Mongoose DB Connection

JoeCamRoberon
0 likes • Mar 11, 2021
JavaScript
require("dotenv").config();
const mongoose = require("mongoose");
const db = process.env.MONGO_URI;
const connectDB = async () => {
try {
await mongoose.connect(db, {
useNewUrlParser: true,
useUnifiedTopology: true,
useFindAndModify: false,
useCreateIndex: true
});
console.log("MongoDB Connected");
} catch (err) {
console.error(err.message);
}
};
module.exports = connectDB;

linear search

CodeCatch
0 likes • Nov 19, 2022
JavaScript
const linearSearch = (arr, item) => {
for (const i in arr) {
if (arr[i] === item) return +i;
}
return -1;
};
linearSearch([2, 9, 9], 9); // 1
linearSearch([2, 9, 9], 7); // -1

Get union of arrays

CodeCatch
0 likes • Nov 19, 2022
JavaScript
const union = (...arr) => [...new Set(arr.flat())];
// Example
union([1, 2], [2, 3], [3]); // [1, 2, 3]