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Invert Binary Tree

Oct 15, 2022CodeCatch
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More JavaScript Posts

Sequential Queue

Feb 6, 2021LeifMessinger

0 likes • 2 views

class SequentialQueue{ //if you want it to go backwards, too bad
next(){
return this.i++;
}
constructor(start = 0){
this.i = start;
}
}
const que = new SequentialQueue(0);
for(let i = 0; i < 10; i++){
console.log(que.next());
}

Untitled

Apr 26, 2025hasnaoui1

0 likes • 1 view

console.log("xa")

Rings and Rods

Nov 19, 2022CodeCatch

0 likes • 1 view

// There are n rings and each ring is either red, green, or blue. The rings are distributed across ten rods labeled from 0 to 9.
// You are given a string rings of length 2n that describes the n rings that are placed onto the rods. Every two characters in rings forms a color-position pair that is used to describe each ring where:
// The first character of the ith pair denotes the ith ring's color ('R', 'G', 'B').
// The second character of the ith pair denotes the rod that the ith ring is placed on ('0' to '9').
// For example, "R3G2B1" describes n == 3 rings: a red ring placed onto the rod labeled 3, a green ring placed onto the rod labeled 2, and a blue ring placed onto the rod labeled 1.
// Return the number of rods that have all three colors of rings on them.
let rings = "B0B6G0R6R0R6G9";
var countPoints = function(rings) {
let sum = 0;
// Always 10 Rods
for (let i = 0; i < 10; i++) {
if (rings.includes(`B${i}`) && rings.includes(`G${i}`) && rings.includes(`R${i}`)) {
sum+=1;
}
}
return sum;
};
console.log(countPoints(rings));

deep merge objects

Nov 19, 2022CodeCatch

0 likes • 3 views

const deepMerge = (a, b, fn) =>
[...new Set([...Object.keys(a), ...Object.keys(b)])].reduce(
(acc, key) => ({ ...acc, [key]: fn(key, a[key], b[key]) }),
{}
);
deepMerge(
{ a: true, b: { c: [1, 2, 3] } },
{ a: false, b: { d: [1, 2, 3] } },
(key, a, b) => (key === 'a' ? a && b : Object.assign({}, a, b))
);
// { a: false, b: { c: [ 1, 2, 3 ], d: [ 1, 2, 3 ] } }

server js

Apr 10, 2025hasnaoui1

0 likes • 4 views

const express = require('express')
const mongoose = require('mongoose')
const cors = require('cors')
const dotenv = require('dotenv')
const server = express()
dotenv.config()
server.use(express.json())
server.get('/' , (req , res)=>{
res.send('Hello')
})
//4.lancement du serveur
server.listen(process.env.PORT , ()=>{
console.log('server run on http://localhost:'+process.env.PORT)
})

kNearestNeighbors

Nov 19, 2022CodeCatch

0 likes • 6 views

const kNearestNeighbors = (data, labels, point, k = 3) => {
const kNearest = data
.map((el, i) => ({
dist: Math.hypot(...Object.keys(el).map(key => point[key] - el[key])),
label: labels[i]
}))
.sort((a, b) => a.dist - b.dist)
.slice(0, k);
return kNearest.reduce(
(acc, { label }, i) => {
acc.classCounts[label] =
Object.keys(acc.classCounts).indexOf(label) !== -1
? acc.classCounts[label] + 1
: 1;
if (acc.classCounts[label] > acc.topClassCount) {
acc.topClassCount = acc.classCounts[label];
acc.topClass = label;
}
return acc;
},
{
classCounts: {},
topClass: kNearest[0].label,
topClassCount: 0
}
).topClass;
};
const data = [[0, 0], [0, 1], [1, 3], [2, 0]];
const labels = [0, 1, 1, 0];
kNearestNeighbors(data, labels, [1, 2], 2); // 1
kNearestNeighbors(data, labels, [1, 0], 2); // 0