• Mar 11, 2021 •C S
0 likes • 1 view
const jwt = require("jsonwebtoken"); const authToken = (req, res, next) => { const token = req.headers["x-auth-token"]; try { req.user = jwt.verify(token, process.env.ACCESS_TOKEN_SECRET); next(); } catch (err) { console.log(err.message); res.status(401).json({ msg: "Error authenticating token" }); } }; module.exports = authToken;
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require("dotenv").config(); const mongoose = require("mongoose"); const db = process.env.MONGO_URI; const connectDB = async () => { try { await mongoose.connect(db, { useNewUrlParser: true, useUnifiedTopology: true, useFindAndModify: false, useCreateIndex: true }); console.log("MongoDB Connected"); } catch (err) { console.error(err.message); } }; module.exports = connectDB;
• Nov 19, 2022 •CodeCatch
const shuffle = ([...arr]) => { let m = arr.length; while (m) { const i = Math.floor(Math.random() * m--); [arr[m], arr[i]] = [arr[i], arr[m]]; } return arr; }; const foo = [1, 2, 3]; shuffle(foo); // [2, 3, 1], foo = [1, 2, 3]
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const longestPalindrome = (s) => { if(s.length === 1) return s const odd = longestOddPalindrome(s) const even = longestEvenPalindrome(s) if(odd.length >= even.length) return odd if(even.length > odd.length) return even }; const longestOddPalindrome = (s) => { let longest = 0 let longestSubStr = "" for(let i = 1; i < s.length; i++) { let currentLongest = 1 let currentLongestSubStr = "" let left = i - 1 let right = i + 1 while(left >= 0 && right < s.length) { const leftLetter = s[left] const rightLetter = s[right] left-- right++ if(leftLetter === rightLetter) { currentLongest += 2 currentLongestSubStr = s.slice(left+1, right) } else break } if(currentLongest > longest) { if(currentLongestSubStr) longestSubStr = currentLongestSubStr else longestSubStr = s[i] longest = currentLongest } } return longestSubStr } const longestEvenPalindrome = (s) => { let longest = 0 let longestSubStr = "" for(let i = 0; i < s.length - 1; i++) { if(s[i] !== s[i+1]) continue; let currentLongest = 2 let currentLongestSubStr = "" let left = i - 1 let right = i + 2 while(left >= 0 && right < s.length) { const leftLetter = s[left] const rightLetter = s[right] left-- right++ if(leftLetter === rightLetter) { currentLongest += 2 currentLongestSubStr = s.slice(left+1, right) } else break } if(currentLongest > longest) { if(currentLongestSubStr) longestSubStr = currentLongestSubStr else longestSubStr = s[i] + s[i+1] longest = currentLongest } } return longestSubStr } console.log(longestPalindrome("babad"))
• Jan 25, 2023 •C S
0 likes • 11 views
// Vanilla JS Solution: var app = document.getElementById('app'); var typewriter = new Typewriter(app, { loop: true }); typewriter .typeString("I'm John and I'm a super cool web developer") .pauseFor(3000) .deleteChars(13) // "web developer" = 13 characters .typeString("person to talk with!") // Will display "I'm John and I'm a super cool person to talk with!" .start(); // React Solution: import Typewriter from 'typewriter-effect'; <Typewriter options={{ loop: true }} onInit={typewriter => { typewriter .typeString("I'm John and I'm a super cool web developer") .pauseFor(3000) .deleteChars(13) // "web developer" = 13 characters .typeString("person to talk with!") // Will display "I'm John and I'm a super cool person to talk with!" .start(); }} />
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const reverse = str => str.split('').reverse().join(''); reverse('hello world'); // Result: 'dlrow olleh'