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Nov 19, 2022CodeCatch
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Tree Traversal

Oct 16, 2023CHS

0 likes • 7 views

class TreeNode {
constructor(data, depth) {
this.data = data;
this.children = [];
this.depth = depth;
}
}
function buildNaryTree(hosts) {
const nodeMap = {};
// Step 1: Create a map of nodes using fqdn as the key
hosts.forEach((host) => {
nodeMap[host.fqdn] = new TreeNode(host, 0); // Initialize depth to 0
});
// Step 2: Iterate through the array and add each node to its parent's list of children
hosts.forEach((host) => {
if (host.displayParent) {
if (nodeMap[host.displayParent]) {
const parent = nodeMap[host.displayParent];
const node = nodeMap[host.fqdn];
node.depth = parent.depth + 1; // Update the depth
parent.children.push(node);
} else {
console.error(`Parent with fqdn ${host.displayParent} not found for ${host.fqdn}`);
}
}
});
// Find the root nodes (nodes with no parent)
const rootNodes = hosts.filter((host) => !host.displayParent).map((host) => nodeMap[host.fqdn]);
return rootNodes;
}
function treeToObjects(node) {
const result = [];
function inOrder(node) {
if (!node) {
return;
}
// Visit the current node and add it to the result
result.push(node.data);
// Visit children nodes first
node.children.forEach((child) => {
inOrder(child);
});
}
inOrder(node);
return result;
}
// Usage example
const hosts = [
{
fqdn: 'fqdn_1',
display_name: 'Host 1',
},
{
fqdn: 'fqdn_2',
display_name: 'Host 2',
displayParent: 'fqdn_1',
},
{
fqdn: 'fqdn_3',
display_name: 'Host 3'
},
{
fqdn: 'fqdn_4',
display_name: 'Host 4',
displayParent: 'fqdn_3',
},
{
fqdn: 'fqdn_5',
display_name: 'Host 5',
displayParent: 'fqdn_1',
},
];
const tree = buildNaryTree(hosts);
// Function to convert the tree to an array of objects
function convertTreeToArray(nodes) {
const result = [];
nodes.forEach((node) => {
result.push(...treeToObjects(node));
});
return result;
}
// Convert the tree back to an array of objects
const arrayFromTree = convertTreeToArray(tree);
console.log(arrayFromTree);

Timer

Feb 5, 2021LeifMessinger

0 likes • 2 views

class Timer{
start(){
this.startTime = Date.now();
}
stop(){
const dt = Date.now() - this.startTime;
console.log(dt);
return dt;
}
getExecTime(fun, asynchronous){
return asynchronous ? this.getAsyncExecTime(fun) : this.getSyncExecTime(fun);
}
getSyncExecTime(fun){
this.start();
fun();
return this.stop();
}
async getAsyncExecTime(fun){
this.start();
await fun();
return this.stop();
}
static average(fun, numTimes, asynchronous = false){
const times = [];
const promises = [];
let timer = new Timer();
if(asynchronous){
for(let i = 0; i < numTimes; i++){
timer.getAsyncExecTime(fun);
}
}else{
for(let i = 0; i < numTimes; i++){
timer.getSyncExecTime(fun);
}
}
return (times => times.reduce(((sum, acc) => sume + acc), 0) / times.length);
}
static async timeAsync(fun, numTimes){
if(numTimes <= 1) return new Timer().getAsyncExecTime(fun);
const promises = [];
let timer = new Timer(true);
for(let i = 0; i < numTimes; i++){
promises.push(fun().catch((e)=>{}));
}
try{
await Promise.all(promises).catch((e)=>{});
}catch(e){
//do absolutely nothing
}
return timer.stop();
}
constructor(start = false){
if(start) this.start();
}
}

getURLParameters

Nov 19, 2022CodeCatch

0 likes • 1 view

const getURLParameters = url =>
(url.match(/([^?=&]+)(=([^&]*))/g) || []).reduce(
(a, v) => (
(a[v.slice(0, v.indexOf('='))] = v.slice(v.indexOf('=') + 1)), a
),
{}
);

Convert data to yyyy mm dd format

Nov 19, 2022CodeCatch

0 likes • 1 view

// `date` is a `Date` object
const formatYmd = date => date.toISOString().slice(0, 10);
// Example
formatYmd(new Date()); // 2020-05-06

List Largest Files Google Drive

Nov 16, 2023LeifMessinger

0 likes • 5 views

function filePath(file){
let folders = file.getParents();
const parents = [];
function makePathString(folderArray){
let path = "";
folderArray.forEach((folder)=>{
path += "/" + folder.getName();
});
return path;
}
while (folders.hasNext()) {
const folder = folders.next(); //This should hopefully remove that folder from the iterator
parents.unshift(folder);
}
return makePathString(parents);
}
function myFunction() {
const myEmail = Session.getEffectiveUser().getEmail();
Logger.log("My email is " + myEmail);
// Log the name of every file in the user's Drive.
var fileIterator = DriveApp.getFiles();
const files = []; //List of [File, size] entries
const filesMaxSize = 10;
while (fileIterator.hasNext()) {
var file = fileIterator.next();
const owner = file.getOwner();
//Only files I own
if((!(owner)) || (!(owner.getEmail)) || owner.getEmail() != myEmail){
continue;
}
const entry = [file, file.getSize()];
function slideUp(arr, index){
//Let's keep sliding it up so we don't have to sort it at the end.
for(let i = index; i > 0; --i){ //Stops at 1
const nextFile = arr[i-1];
if(nextFile[1] > entry[1]){
break;
}else{
//Swap with the next file to slide the file up
const temp = arr[i];
arr[i] = arr[i - 1];
arr[i - 1] = temp;
}
}
}
if(files.length < filesMaxSize){
files.push(entry);
slideUp(files, files.length - 1);
}else{
if(entry[1] > files[files.length - 1][1]){ //If it's bigger than the smallest file in the list.
files[files.length - 1] = entry; //Replace the smallest file
slideUp(files, files.length - 1); //Slide it up
}
}
}
for(let i = 0; i < filesMaxSize; ++i){
const file = files[i][0];
const size = files[i][1];
Logger.log(size + "\t" + filePath(file) + "/" + file.getName() + "\t" + file.getOwner().getName());
}
}

Rings and Rods

Nov 19, 2022CodeCatch

0 likes • 1 view

// There are n rings and each ring is either red, green, or blue. The rings are distributed across ten rods labeled from 0 to 9.
// You are given a string rings of length 2n that describes the n rings that are placed onto the rods. Every two characters in rings forms a color-position pair that is used to describe each ring where:
// The first character of the ith pair denotes the ith ring's color ('R', 'G', 'B').
// The second character of the ith pair denotes the rod that the ith ring is placed on ('0' to '9').
// For example, "R3G2B1" describes n == 3 rings: a red ring placed onto the rod labeled 3, a green ring placed onto the rod labeled 2, and a blue ring placed onto the rod labeled 1.
// Return the number of rods that have all three colors of rings on them.
let rings = "B0B6G0R6R0R6G9";
var countPoints = function(rings) {
let sum = 0;
// Always 10 Rods
for (let i = 0; i < 10; i++) {
if (rings.includes(`B${i}`) && rings.includes(`G${i}`) && rings.includes(`R${i}`)) {
sum+=1;
}
}
return sum;
};
console.log(countPoints(rings));