• Jan 17, 2021 •C S
0 likes • 0 views
const getSearchTerm = delimiter => { let searchTerm = ""; for (let i = 1; i < commands.length - 1; i++) searchTerm = searchTerm + commands[i] + delimiter; searchTerm += commands[commands.length - 1]; return searchTerm; };
• Mar 11, 2021 •C S
1 like • 3 views
if (process.env.NODE_ENV === "production") { app.use(express.static("client/build")); app.get("*", (req, res) => { res.sendFile(path.resolve(__dirname, "client", "build", "index.html")); }); }
0 likes • 2 views
const mongoose = require('mongoose') const UserSchema = new mongoose.Schema({ username: { type: String, required: true }, email: { type: String, unique: true, required: true }, password: { type: String, required: true }, date: { type: Date, default: Date.now } }) module.exports = User = mongoose.model('user', UserSchema)
• Nov 19, 2022 •CodeCatch
0 likes • 1 view
const heapsort = arr => { const a = [...arr]; let l = a.length; const heapify = (a, i) => { const left = 2 * i + 1; const right = 2 * i + 2; let max = i; if (left < l && a[left] > a[max]) max = left; if (right < l && a[right] > a[max]) max = right; if (max !== i) { [a[max], a[i]] = [a[i], a[max]]; heapify(a, max); } }; for (let i = Math.floor(l / 2); i >= 0; i -= 1) heapify(a, i); for (i = a.length - 1; i > 0; i--) { [a[0], a[i]] = [a[i], a[0]]; l--; heapify(a, 0); } return a; }; heapsort([6, 3, 4, 1]); // [1, 3, 4, 6]
const formatDuration = ms => { if (ms < 0) ms = -ms; const time = { day: Math.floor(ms / 86400000), hour: Math.floor(ms / 3600000) % 24, minute: Math.floor(ms / 60000) % 60, second: Math.floor(ms / 1000) % 60, millisecond: Math.floor(ms) % 1000 }; return Object.entries(time) .filter(val => val[1] !== 0) .map(([key, val]) => `${val} ${key}${val !== 1 ? 's' : ''}`) .join(', '); }; formatDuration(1001); // '1 second, 1 millisecond' formatDuration(34325055574); // '397 days, 6 hours, 44 minutes, 15 seconds, 574 milliseconds'
// There are n rings and each ring is either red, green, or blue. The rings are distributed across ten rods labeled from 0 to 9. // You are given a string rings of length 2n that describes the n rings that are placed onto the rods. Every two characters in rings forms a color-position pair that is used to describe each ring where: // The first character of the ith pair denotes the ith ring's color ('R', 'G', 'B'). // The second character of the ith pair denotes the rod that the ith ring is placed on ('0' to '9'). // For example, "R3G2B1" describes n == 3 rings: a red ring placed onto the rod labeled 3, a green ring placed onto the rod labeled 2, and a blue ring placed onto the rod labeled 1. // Return the number of rods that have all three colors of rings on them. let rings = "B0B6G0R6R0R6G9"; var countPoints = function(rings) { let sum = 0; // Always 10 Rods for (let i = 0; i < 10; i++) { if (rings.includes(`B${i}`) && rings.includes(`G${i}`) && rings.includes(`R${i}`)) { sum+=1; } } return sum; }; console.log(countPoints(rings));