• Nov 19, 2022 •CodeCatch
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const getTimezone = () => Intl.DateTimeFormat().resolvedOptions().timeZone; // Example getTimezone();
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//JavaScript program to swap two variables //take input from the users let a = prompt('Enter the first variable: '); let b = prompt('Enter the second variable: '); //using destructuring assignment [a, b] = [b, a]; console.log(`The value of a after swapping: ${a}`); console.log(`The value of b after swapping: ${b}`);
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const powerset = arr => arr.reduce((a, v) => a.concat(a.map(r => r.concat(v))), [[]]); powerset([1, 2]); // [[], [1], [2], [1, 2]]
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const toFixed = (n, fixed) => ~~(Math.pow(10, fixed) * n) / Math.pow(10, fixed); // Examples toFixed(25.198726354, 1); // 25.1 toFixed(25.198726354, 2); // 25.19 toFixed(25.198726354, 3); // 25.198 toFixed(25.198726354, 4); // 25.1987 toFixed(25.198726354, 5); // 25.19872 toFixed(25.198726354, 6); // 25.198726
• Jan 17, 2021 •C S
const getSearchTerm = delimiter => { let searchTerm = ""; for (let i = 1; i < commands.length - 1; i++) searchTerm = searchTerm + commands[i] + delimiter; searchTerm += commands[commands.length - 1]; return searchTerm; };
// There are n rings and each ring is either red, green, or blue. The rings are distributed across ten rods labeled from 0 to 9. // You are given a string rings of length 2n that describes the n rings that are placed onto the rods. Every two characters in rings forms a color-position pair that is used to describe each ring where: // The first character of the ith pair denotes the ith ring's color ('R', 'G', 'B'). // The second character of the ith pair denotes the rod that the ith ring is placed on ('0' to '9'). // For example, "R3G2B1" describes n == 3 rings: a red ring placed onto the rod labeled 3, a green ring placed onto the rod labeled 2, and a blue ring placed onto the rod labeled 1. // Return the number of rods that have all three colors of rings on them. let rings = "B0B6G0R6R0R6G9"; var countPoints = function(rings) { let sum = 0; // Always 10 Rods for (let i = 0; i < 10; i++) { if (rings.includes(`B${i}`) && rings.includes(`G${i}`) && rings.includes(`R${i}`)) { sum+=1; } } return sum; }; console.log(countPoints(rings));