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levenshtein distance

0 likes • Nov 19, 2022 • 1 view
JavaScript
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Rings and Rods

0 likes • Nov 19, 2022 • 1 view
JavaScript
// There are n rings and each ring is either red, green, or blue. The rings are distributed across ten rods labeled from 0 to 9.
// You are given a string rings of length 2n that describes the n rings that are placed onto the rods. Every two characters in rings forms a color-position pair that is used to describe each ring where:
// The first character of the ith pair denotes the ith ring's color ('R', 'G', 'B').
// The second character of the ith pair denotes the rod that the ith ring is placed on ('0' to '9').
// For example, "R3G2B1" describes n == 3 rings: a red ring placed onto the rod labeled 3, a green ring placed onto the rod labeled 2, and a blue ring placed onto the rod labeled 1.
// Return the number of rods that have all three colors of rings on them.
let rings = "B0B6G0R6R0R6G9";
var countPoints = function(rings) {
let sum = 0;
// Always 10 Rods
for (let i = 0; i < 10; i++) {
if (rings.includes(`B${i}`) && rings.includes(`G${i}`) && rings.includes(`R${i}`)) {
sum+=1;
}
}
return sum;
};
console.log(countPoints(rings));

getSelectedText

0 likes • Nov 18, 2022 • 0 views
JavaScript
// Get the text that the user has selected
const getSelectedText = () => window.getSelection().toString();
getSelectedText();

Mongoose Model

CHS
0 likes • Mar 11, 2021 • 0 views
JavaScript
const mongoose = require('mongoose')
const UserSchema = new mongoose.Schema({
username: {
type: String,
required: true
},
email: {
type: String,
unique: true,
required: true
},
password: {
type: String,
required: true
},
date: {
type: Date,
default: Date.now
}
})
module.exports = User = mongoose.model('user', UserSchema)

Scrape twitter

0 likes • Sep 2, 2023 • 8 views
JavaScript
//Allegedly never tested on the twitter website
function scrapeScreen(){
let articles = Array.from(document.getElementsByTagName("article"));
let results = [];
for(let tweet of articles){
const isAnAd = Array.from(tweet.querySelectorAll("span")).map((e)=>e.textContent).includes("Ad");
if(isAnAd){
//console.log(tweet, "is an ad. Skipping...");
continue;
}
const userName = tweet.querySelector("[data-testid='User-Name'] > div:nth-child(2) > div > div")?.textContent;
const tweetContent = tweet.querySelector("[data-testid='tweetText']")?.textContent;
const timeStamp = tweet.querySelector("time")?.getAttribute("datetime");
const tweetLink = tweet.querySelector("time")?.parentElement?.getAttribute("href");
if((!userName) || (!tweetContent)) continue;
results.push({
username: userName,
tweetText: tweetContent,
timeStamp: timeStamp,
tweetLink: tweetLink
});
}
return results;
}
let scraped = scrapeScreen();
setInterval(()=>{
scraped = scraped.concat(
scrapeScreen().filter((tweet)=>{
for(let scrapedTweet of scraped){
if(scrapedTweet.username == tweet.username && scrapedTweet.tweetText == tweet.tweetText) return false;
}
return true;
})
);
}, 500); //Scrape everything on the screen twice a second
window.scrollIntervalId = setInterval(function(){
window.scrollBy(0, 1000);
}, 500); //Scroll for me
//http://bgrins.github.io/devtools-snippets/#console-save
(function(console){
console.save = function(data, filename){
if(!data) {
console.error('Console.save: No data')
return;
}
if(!filename) filename = 'console.json'
if(typeof data === "object"){
data = JSON.stringify(data, undefined, '\t')
}
var blob = new Blob([data], {type: 'text/json'}),
e = document.createEvent('MouseEvents'),
a = document.createElement('a')
a.download = filename
a.href = window.URL.createObjectURL(blob)
a.dataset.downloadurl = ['text/json', a.download, a.href].join(':')
e.initMouseEvent('click', true, false, window, 0, 0, 0, 0, 0, false, false, false, false, 0, null)
a.dispatchEvent(e)
}
})(console)
setTimeout(()=>{
clearTimeout(window.scrollIntervalId);
delete window.scrollIntervalId;
console.save(scraped, "TwitterScrape" + Date.now() + ".json");
}, 60 * 1000 * 20); //Twenty minutes

euclidean distance

0 likes • Nov 19, 2022 • 3 views
JavaScript
const euclideanDistance = (a, b) =>
Math.hypot(...Object.keys(a).map(k => b[k] - a[k]));
euclideanDistance([1, 1], [2, 3]); // ~2.2361
euclideanDistance([1, 1, 1], [2, 3, 2]); // ~2.4495

Reverse a string

0 likes • Nov 19, 2022 • 1 view
JavaScript
const reverse = str => str.split('').reverse().join('');
reverse('hello world');
// Result: 'dlrow olleh'