• Nov 19, 2022 •CodeCatch
0 likes • 2 views
const longestPalindrome = (s) => { if(s.length === 1) return s const odd = longestOddPalindrome(s) const even = longestEvenPalindrome(s) if(odd.length >= even.length) return odd if(even.length > odd.length) return even }; const longestOddPalindrome = (s) => { let longest = 0 let longestSubStr = "" for(let i = 1; i < s.length; i++) { let currentLongest = 1 let currentLongestSubStr = "" let left = i - 1 let right = i + 1 while(left >= 0 && right < s.length) { const leftLetter = s[left] const rightLetter = s[right] left-- right++ if(leftLetter === rightLetter) { currentLongest += 2 currentLongestSubStr = s.slice(left+1, right) } else break } if(currentLongest > longest) { if(currentLongestSubStr) longestSubStr = currentLongestSubStr else longestSubStr = s[i] longest = currentLongest } } return longestSubStr } const longestEvenPalindrome = (s) => { let longest = 0 let longestSubStr = "" for(let i = 0; i < s.length - 1; i++) { if(s[i] !== s[i+1]) continue; let currentLongest = 2 let currentLongestSubStr = "" let left = i - 1 let right = i + 2 while(left >= 0 && right < s.length) { const leftLetter = s[left] const rightLetter = s[right] left-- right++ if(leftLetter === rightLetter) { currentLongest += 2 currentLongestSubStr = s.slice(left+1, right) } else break } if(currentLongest > longest) { if(currentLongestSubStr) longestSubStr = currentLongestSubStr else longestSubStr = s[i] + s[i+1] longest = currentLongest } } return longestSubStr } console.log(longestPalindrome("babad"))
• Jan 17, 2021 •C S
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const getSearchTerm = delimiter => { let searchTerm = ""; for (let i = 1; i < commands.length - 1; i++) searchTerm = searchTerm + commands[i] + delimiter; searchTerm += commands[commands.length - 1]; return searchTerm; };
const geometricProgression = (end, start = 1, step = 2) => Array.from({ length: Math.floor(Math.log(end / start) / Math.log(step)) + 1, }).map((_, i) => start * step ** i); geometricProgression(256); // [1, 2, 4, 8, 16, 32, 64, 128, 256] geometricProgression(256, 3); // [3, 6, 12, 24, 48, 96, 192] geometricProgression(256, 1, 4); // [1, 4, 16, 64, 256]
• Jan 25, 2023 •C S
0 likes • 11 views
// Vanilla JS Solution: var app = document.getElementById('app'); var typewriter = new Typewriter(app, { loop: true }); typewriter .typeString("I'm John and I'm a super cool web developer") .pauseFor(3000) .deleteChars(13) // "web developer" = 13 characters .typeString("person to talk with!") // Will display "I'm John and I'm a super cool person to talk with!" .start(); // React Solution: import Typewriter from 'typewriter-effect'; <Typewriter options={{ loop: true }} onInit={typewriter => { typewriter .typeString("I'm John and I'm a super cool web developer") .pauseFor(3000) .deleteChars(13) // "web developer" = 13 characters .typeString("person to talk with!") // Will display "I'm John and I'm a super cool person to talk with!" .start(); }} />
• Feb 5, 2021 •LeifMessinger
class Timer{ start(){ this.startTime = Date.now(); } stop(){ const dt = Date.now() - this.startTime; console.log(dt); return dt; } getExecTime(fun, asynchronous){ return asynchronous ? this.getAsyncExecTime(fun) : this.getSyncExecTime(fun); } getSyncExecTime(fun){ this.start(); fun(); return this.stop(); } async getAsyncExecTime(fun){ this.start(); await fun(); return this.stop(); } static average(fun, numTimes, asynchronous = false){ const times = []; const promises = []; let timer = new Timer(); if(asynchronous){ for(let i = 0; i < numTimes; i++){ timer.getAsyncExecTime(fun); } }else{ for(let i = 0; i < numTimes; i++){ timer.getSyncExecTime(fun); } } return (times => times.reduce(((sum, acc) => sume + acc), 0) / times.length); } static async timeAsync(fun, numTimes){ if(numTimes <= 1) return new Timer().getAsyncExecTime(fun); const promises = []; let timer = new Timer(true); for(let i = 0; i < numTimes; i++){ promises.push(fun().catch((e)=>{})); } try{ await Promise.all(promises).catch((e)=>{}); }catch(e){ //do absolutely nothing } return timer.stop(); } constructor(start = false){ if(start) this.start(); } }
• Sep 13, 2023 •C S
/** * @param {number[]} nums * @param {number} target * @return {number[]} */ var twoSum = function(nums, target) { for(let i = 0; i < nums.length; i++) { for(let j = 0; j < nums.length; j++) { if(nums[i] + nums[j] === target && i !== j) { return [i, j] } } } };