• Nov 19, 2022 •CodeCatch
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const getTimezone = () => Intl.DateTimeFormat().resolvedOptions().timeZone; // Example getTimezone();
• Oct 15, 2022 •CodeCatch
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var invertTree = function(root) { const reverseNode = node => { if (node == null) { return null } reverseNode(node.left); reverseNode(node.right); let holdLeft = node.left; node.left = node.right; node.right = holdLeft; return node; } return reverseNode(root); };
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// `date` is a `Date` object const formatYmd = date => date.toISOString().slice(0, 10); // Example formatYmd(new Date()); // 2020-05-06
• Sep 13, 2023 •C S
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/** * @param {number[]} nums * @return {number[]} */ var productExceptSelf = function(nums) { var output = []; var leftMult = 1; var rightMult = 1; for (var i=nums.length - 1; i >= 0; i--) { output[i] = rightMult; rightMult *= nums[i]; console.log({output: JSON.stringify(output), i}) } for (var j=0; j < nums.length; j++) { output[j] *= leftMult; leftMult *= nums[j]; console.log({output: JSON.stringify(output), j}) } return output; }; console.log(productExceptSelf([1, 2, 3, 4]))
// There are n rings and each ring is either red, green, or blue. The rings are distributed across ten rods labeled from 0 to 9. // You are given a string rings of length 2n that describes the n rings that are placed onto the rods. Every two characters in rings forms a color-position pair that is used to describe each ring where: // The first character of the ith pair denotes the ith ring's color ('R', 'G', 'B'). // The second character of the ith pair denotes the rod that the ith ring is placed on ('0' to '9'). // For example, "R3G2B1" describes n == 3 rings: a red ring placed onto the rod labeled 3, a green ring placed onto the rod labeled 2, and a blue ring placed onto the rod labeled 1. // Return the number of rods that have all three colors of rings on them. let rings = "B0B6G0R6R0R6G9"; var countPoints = function(rings) { let sum = 0; // Always 10 Rods for (let i = 0; i < 10; i++) { if (rings.includes(`B${i}`) && rings.includes(`G${i}`) && rings.includes(`R${i}`)) { sum+=1; } } return sum; }; console.log(countPoints(rings));
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const euclideanDistance = (a, b) => Math.hypot(...Object.keys(a).map(k => b[k] - a[k])); euclideanDistance([1, 1], [2, 3]); // ~2.2361 euclideanDistance([1, 1, 1], [2, 3, 2]); // ~2.4495