geometric progression
0 likes • Nov 19, 2022 • 0 views
JavaScript
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function formatDate(date) {return date.toLocaleDateString();}function Comment(props) {return (<div className="Comment"><div className="UserInfo"><imgclassName="Avatar"src={props.author.avatarUrl}alt={props.author.name}/><div className="UserInfo-name">{props.author.name}</div></div><div className="Comment-text">{props.text}</div><div className="Comment-date">{formatDate(props.date)}</div></div>);}const comment = {date: new Date(),text: 'I hope you enjoy learning React!',author: {name: 'Hello Kitty',avatarUrl: 'https://placekitten.com/g/64/64',},};ReactDOM.render(<Commentdate={comment.date}text={comment.text}author={comment.author}/>,document.getElementById('root'));
// Time Complexity : O(N)// Space Complexity : O(1)var isMonotonic = function(nums) {let isMono = null;for(let i = 1; i < nums.length; i++) {if(isMono === null) {if(nums[i - 1] < nums[i]) isMono = 0;else if(nums[i - 1] > nums[i]) isMono = 1;continue;}if(nums[i - 1] < nums[i] && isMono !== 0) {return false;}else if(nums[i - 1] > nums[i] && isMono !== 1) {return false;}}return true;};let nums1 = [1,2,2,3]let nums2 = [6,5,4,4]let nums3 = [1,3,2]console.log(isMonotonic(nums1));console.log(isMonotonic(nums2));console.log(isMonotonic(nums3));
const dragAndDropDiv = editor.container;dragAndDropDiv.addEventListener('dragover', function(e) {e.stopPropagation();e.preventDefault();e.dataTransfer.dropEffect = 'copy';});dragAndDropDiv.addEventListener("drop",function(e){// Prevent default behavior (Prevent file from being opened)e.stopPropagation();e.preventDefault();const files = e.dataTransfer.items; // Array of all filesconsole.assert(files.length >= 1);if (files[0].kind === 'file') {var file = e.dataTransfer.items[0].getAsFile();const fileSize = file.size;const fileName = file.name;const fileMimeType = file.type;reader = new FileReader();reader.onloadend = function(){editor.setValue(reader.result);}reader.readAsText(file);}else{//Maybe handle if text is droppedconsole.log(files[0].kind);}});
//Retries maxRetries number of times, meaning that if you have 0, then it'll run the function once.async function retryPromise(promiseFn, maxRetries = 3, delayOffset = 0, delayRandomRange = 0) {return new Promise((resolve, reject) => {promiseFn().then(resolve, (error) => { //On errorif (maxRetries <= 0) {return reject(error);} else {if(delayRandomRange * Math.random() + delayOffset < 1.0){return retryPromise(promiseFn, maxRetries - 1, delayOffset, delayRandomRange).then(resolve, reject);}else{return new Promise((resolveTwo, rejectTwo) => {setTimeout(() => {return retryPromise(promiseFn, maxRetries - 1, delayOffset, delayRandomRange).then(resolveTwo, rejectTwo);}, delayRandomRange * Math.random() + delayOffset);}).then(resolve, reject);}}});});}//Tests for that function.//Returns a function that will fail numTimes times, then will return aValuefunction functionThatReturnsAFunctionThatFailsACoupleTimes(numTimes, aValue){return async function(){if(numTimes == 0){return aValue;}numTimes--;throw false;};}const SMALL_NUMBER = 10;function testTest(failNumberOfTimes){let functionThatFailsACoupleTimes = functionThatReturnsAFunctionThatFailsACoupleTimes(failNumberOfTimes, true);//Test my testfor(let i = 0; i < (failNumberOfTimes * 2); ++i){function evalTest(val){let testTestFailedReason = "";if(val === undefined){testTestFailedReason = "Test test returned undefined for some reason.";}if((i + 1) > failNumberOfTimes){if(val === true){//We're good}else{testTestFailedReason = "Test test didn't return true when it should have.";}}else{if(val === false){//We're good}else{testTestFailedReason = "Test test didn't return false when it should have.";}}testTestFailedReason = testTestFailedReason || "Test test passed test case";console.log(testTestFailedReason, "at index", i, "where the function returned", val);}functionThatFailsACoupleTimes().then(evalTest, evalTest)};}testTest(SMALL_NUMBER);let testCaseCounter = 1;const throwsNoError = [(val)=>{if(val == true){console.log("Passed test case " + (testCaseCounter++));}else{console.error("Unexpected return value", val);}},()=>{console.error("It wasn't supposed to fail!")}]const throwsError = [(val)=>{console.error("It wasn't supposed to succeed!", val);},(val)=>{if(val == false){console.log("Passed test case " + (testCaseCounter++));}else{console.error("Unexpected return value", val);}}];//Runs SMALL_NUMBER times, because SMALL_NUMBER - 1 is the number of retries after the first onelet functionThatFailsACoupleTimes = functionThatReturnsAFunctionThatFailsACoupleTimes(SMALL_NUMBER - 1, true);retryPromise(functionThatFailsACoupleTimes, SMALL_NUMBER - 1).then(...throwsNoError)functionThatFailsACoupleTimes = functionThatReturnsAFunctionThatFailsACoupleTimes(SMALL_NUMBER - 1, true);//Runs SMALL_NUMBER - 1 times, because SMALL_NUMBER - 2 is the number of retries after the first oneretryPromise(functionThatFailsACoupleTimes, SMALL_NUMBER - 2).then(...throwsError)//Testing the delay. You'll have to wait a bit too.functionThatFailsACoupleTimes = functionThatReturnsAFunctionThatFailsACoupleTimes(SMALL_NUMBER - 1, true);//Runs SMALL_NUMBER times, because SMALL_NUMBER - 1 is the number of retries after the first oneretryPromise(functionThatFailsACoupleTimes, SMALL_NUMBER - 1, 500, 500).then(...throwsNoError)functionThatFailsACoupleTimes = functionThatReturnsAFunctionThatFailsACoupleTimes(SMALL_NUMBER - 1, true);//Runs SMALL_NUMBER - 1 times, because SMALL_NUMBER - 2 is the number of retries after the first oneretryPromise(functionThatFailsACoupleTimes, SMALL_NUMBER - 2, 500, 500).then(...throwsError)
// `date` is a `Date` objectconst formatYmd = date => date.toISOString().slice(0, 10);// ExampleformatYmd(new Date()); // 2020-05-06
const deepMerge = (a, b, fn) =>[...new Set([...Object.keys(a), ...Object.keys(b)])].reduce((acc, key) => ({ ...acc, [key]: fn(key, a[key], b[key]) }),{});deepMerge({ a: true, b: { c: [1, 2, 3] } },{ a: false, b: { d: [1, 2, 3] } },(key, a, b) => (key === 'a' ? a && b : Object.assign({}, a, b)));// { a: false, b: { c: [ 1, 2, 3 ], d: [ 1, 2, 3 ] } }