• Apr 10, 2025 •hasnaoui1
0 likes • 12 views
const express = require('express') const mongoose = require('mongoose') const cors = require('cors') const dotenv = require('dotenv') const server = express() dotenv.config() server.use(express.json()) server.get('/' , (req , res)=>{ res.send('Hello') }) //4.lancement du serveur server.listen(process.env.PORT , ()=>{ console.log('server run on http://localhost:'+process.env.PORT) })
• Nov 20, 2022 •Helper
0 likes • 2 views
new StringBuilder(hi).reverse().toString()
• Nov 19, 2022 •CodeCatch
// There are n rings and each ring is either red, green, or blue. The rings are distributed across ten rods labeled from 0 to 9. // You are given a string rings of length 2n that describes the n rings that are placed onto the rods. Every two characters in rings forms a color-position pair that is used to describe each ring where: // The first character of the ith pair denotes the ith ring's color ('R', 'G', 'B'). // The second character of the ith pair denotes the rod that the ith ring is placed on ('0' to '9'). // For example, "R3G2B1" describes n == 3 rings: a red ring placed onto the rod labeled 3, a green ring placed onto the rod labeled 2, and a blue ring placed onto the rod labeled 1. // Return the number of rods that have all three colors of rings on them. let rings = "B0B6G0R6R0R6G9"; var countPoints = function(rings) { let sum = 0; // Always 10 Rods for (let i = 0; i < 10; i++) { if (rings.includes(`B${i}`) && rings.includes(`G${i}`) && rings.includes(`R${i}`)) { sum+=1; } } return sum; }; console.log(countPoints(rings));
• Oct 15, 2022 •CodeCatch
2 likes • 11 views
var invertTree = function(root) { const reverseNode = node => { if (node == null) { return null } reverseNode(node.left); reverseNode(node.right); let holdLeft = node.left; node.left = node.right; node.right = holdLeft; return node; } return reverseNode(root); };
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const formatDuration = ms => { if (ms < 0) ms = -ms; const time = { day: Math.floor(ms / 86400000), hour: Math.floor(ms / 3600000) % 24, minute: Math.floor(ms / 60000) % 60, second: Math.floor(ms / 1000) % 60, millisecond: Math.floor(ms) % 1000 }; return Object.entries(time) .filter(val => val[1] !== 0) .map(([key, val]) => `${val} ${key}${val !== 1 ? 's' : ''}`) .join(', '); }; formatDuration(1001); // '1 second, 1 millisecond' formatDuration(34325055574); // '397 days, 6 hours, 44 minutes, 15 seconds, 574 milliseconds'
const primes = num => { let arr = Array.from({ length: num - 1 }).map((x, i) => i + 2), sqroot = Math.floor(Math.sqrt(num)), numsTillSqroot = Array.from({ length: sqroot - 1 }).map((x, i) => i + 2); numsTillSqroot.forEach(x => (arr = arr.filter(y => y % x !== 0 || y === x))); return arr; }; primes(10); // [2, 3, 5, 7]