• Nov 19, 2022 •CodeCatch
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const primes = num => { let arr = Array.from({ length: num - 1 }).map((x, i) => i + 2), sqroot = Math.floor(Math.sqrt(num)), numsTillSqroot = Array.from({ length: sqroot - 1 }).map((x, i) => i + 2); numsTillSqroot.forEach(x => (arr = arr.filter(y => y % x !== 0 || y === x))); return arr; }; primes(10); // [2, 3, 5, 7]
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const getSubsets = arr => arr.reduce((prev, curr) => prev.concat(prev.map(k => k.concat(curr))), [[]]); // Examples getSubsets([1, 2]); // [[], [1], [2], [1, 2]] getSubsets([1, 2, 3]); // [[], [1], [2], [1, 2], [3], [1, 3], [2, 3], [1, 2, 3]]
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const getURLParameters = url => (url.match(/([^?=&]+)(=([^&]*))/g) || []).reduce( (a, v) => ( (a[v.slice(0, v.indexOf('='))] = v.slice(v.indexOf('=') + 1)), a ), {} );
const linearSearch = (arr, item) => { for (const i in arr) { if (arr[i] === item) return +i; } return -1; }; linearSearch([2, 9, 9], 9); // 1 linearSearch([2, 9, 9], 7); // -1
• Apr 26, 2025 •hasnaoui1
console.log("xa")
// There are n rings and each ring is either red, green, or blue. The rings are distributed across ten rods labeled from 0 to 9. // You are given a string rings of length 2n that describes the n rings that are placed onto the rods. Every two characters in rings forms a color-position pair that is used to describe each ring where: // The first character of the ith pair denotes the ith ring's color ('R', 'G', 'B'). // The second character of the ith pair denotes the rod that the ith ring is placed on ('0' to '9'). // For example, "R3G2B1" describes n == 3 rings: a red ring placed onto the rod labeled 3, a green ring placed onto the rod labeled 2, and a blue ring placed onto the rod labeled 1. // Return the number of rods that have all three colors of rings on them. let rings = "B0B6G0R6R0R6G9"; var countPoints = function(rings) { let sum = 0; // Always 10 Rods for (let i = 0; i < 10; i++) { if (rings.includes(`B${i}`) && rings.includes(`G${i}`) && rings.includes(`R${i}`)) { sum+=1; } } return sum; }; console.log(countPoints(rings));