• Feb 5, 2021 •LeifMessinger
0 likes • 4 views
class Timer{ start(){ this.startTime = Date.now(); } stop(){ const dt = Date.now() - this.startTime; console.log(dt); return dt; } getExecTime(fun, asynchronous){ return asynchronous ? this.getAsyncExecTime(fun) : this.getSyncExecTime(fun); } getSyncExecTime(fun){ this.start(); fun(); return this.stop(); } async getAsyncExecTime(fun){ this.start(); await fun(); return this.stop(); } static average(fun, numTimes, asynchronous = false){ const times = []; const promises = []; let timer = new Timer(); if(asynchronous){ for(let i = 0; i < numTimes; i++){ timer.getAsyncExecTime(fun); } }else{ for(let i = 0; i < numTimes; i++){ timer.getSyncExecTime(fun); } } return (times => times.reduce(((sum, acc) => sume + acc), 0) / times.length); } static async timeAsync(fun, numTimes){ if(numTimes <= 1) return new Timer().getAsyncExecTime(fun); const promises = []; let timer = new Timer(true); for(let i = 0; i < numTimes; i++){ promises.push(fun().catch((e)=>{})); } try{ await Promise.all(promises).catch((e)=>{}); }catch(e){ //do absolutely nothing } return timer.stop(); } constructor(start = false){ if(start) this.start(); } }
• Nov 19, 2022 •CodeCatch
0 likes • 2 views
const longestPalindrome = (s) => { if(s.length === 1) return s const odd = longestOddPalindrome(s) const even = longestEvenPalindrome(s) if(odd.length >= even.length) return odd if(even.length > odd.length) return even }; const longestOddPalindrome = (s) => { let longest = 0 let longestSubStr = "" for(let i = 1; i < s.length; i++) { let currentLongest = 1 let currentLongestSubStr = "" let left = i - 1 let right = i + 1 while(left >= 0 && right < s.length) { const leftLetter = s[left] const rightLetter = s[right] left-- right++ if(leftLetter === rightLetter) { currentLongest += 2 currentLongestSubStr = s.slice(left+1, right) } else break } if(currentLongest > longest) { if(currentLongestSubStr) longestSubStr = currentLongestSubStr else longestSubStr = s[i] longest = currentLongest } } return longestSubStr } const longestEvenPalindrome = (s) => { let longest = 0 let longestSubStr = "" for(let i = 0; i < s.length - 1; i++) { if(s[i] !== s[i+1]) continue; let currentLongest = 2 let currentLongestSubStr = "" let left = i - 1 let right = i + 2 while(left >= 0 && right < s.length) { const leftLetter = s[left] const rightLetter = s[right] left-- right++ if(leftLetter === rightLetter) { currentLongest += 2 currentLongestSubStr = s.slice(left+1, right) } else break } if(currentLongest > longest) { if(currentLongestSubStr) longestSubStr = currentLongestSubStr else longestSubStr = s[i] + s[i+1] longest = currentLongest } } return longestSubStr } console.log(longestPalindrome("babad"))
const shuffle = ([...arr]) => { let m = arr.length; while (m) { const i = Math.floor(Math.random() * m--); [arr[m], arr[i]] = [arr[i], arr[m]]; } return arr; }; const foo = [1, 2, 3]; shuffle(foo); // [2, 3, 1], foo = [1, 2, 3]
0 likes • 3 views
const toFixed = (n, fixed) => ~~(Math.pow(10, fixed) * n) / Math.pow(10, fixed); // Examples toFixed(25.198726354, 1); // 25.1 toFixed(25.198726354, 2); // 25.19 toFixed(25.198726354, 3); // 25.198 toFixed(25.198726354, 4); // 25.1987 toFixed(25.198726354, 5); // 25.19872 toFixed(25.198726354, 6); // 25.198726
// There are n rings and each ring is either red, green, or blue. The rings are distributed across ten rods labeled from 0 to 9. // You are given a string rings of length 2n that describes the n rings that are placed onto the rods. Every two characters in rings forms a color-position pair that is used to describe each ring where: // The first character of the ith pair denotes the ith ring's color ('R', 'G', 'B'). // The second character of the ith pair denotes the rod that the ith ring is placed on ('0' to '9'). // For example, "R3G2B1" describes n == 3 rings: a red ring placed onto the rod labeled 3, a green ring placed onto the rod labeled 2, and a blue ring placed onto the rod labeled 1. // Return the number of rods that have all three colors of rings on them. let rings = "B0B6G0R6R0R6G9"; var countPoints = function(rings) { let sum = 0; // Always 10 Rods for (let i = 0; i < 10; i++) { if (rings.includes(`B${i}`) && rings.includes(`G${i}`) && rings.includes(`R${i}`)) { sum+=1; } } return sum; }; console.log(countPoints(rings));
• Jan 25, 2023 •C S
0 likes • 15 views
// Vanilla JS Solution: var app = document.getElementById('app'); var typewriter = new Typewriter(app, { loop: true }); typewriter .typeString("I'm John and I'm a super cool web developer") .pauseFor(3000) .deleteChars(13) // "web developer" = 13 characters .typeString("person to talk with!") // Will display "I'm John and I'm a super cool person to talk with!" .start(); // React Solution: import Typewriter from 'typewriter-effect'; <Typewriter options={{ loop: true }} onInit={typewriter => { typewriter .typeString("I'm John and I'm a super cool web developer") .pauseFor(3000) .deleteChars(13) // "web developer" = 13 characters .typeString("person to talk with!") // Will display "I'm John and I'm a super cool person to talk with!" .start(); }} />