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class SequentialQueue{ //if you want it to go backwards, too badnext(){return this.i++;}constructor(start = 0){this.i = start;}}const que = new SequentialQueue(0);for(let i = 0; i < 10; i++){console.log(que.next());}
questions = Array.from(document.querySelectorAll(".multiple-choice-question"));async function hackRadio(question){if(question.querySelector(".question-chevron").getAttribute("aria-label") == "Question completed") return;let answerChoices = question.querySelectorAll(".zb-radio-button");async function guess(answerChoice){answerChoice.querySelector("label").click();}let pause = 0;for(let answerChoice of answerChoices){setTimeout(()=>{guess(answerChoice)},pause); //No need to check given that it will record the correct answer anyways.pause += 1000;}}for(let question of questions){hackRadio(question);}questions = Array.from(document.querySelectorAll(".short-answer-question"));async function hackShortAnswer(question){if(question.querySelector(".question-chevron").getAttribute("aria-label") == "Question completed") return;question.querySelector("textarea").value = question.querySelector(".forfeit-answer").textContent;//question.querySelector(".check-button").click(); They are smart bastards}for(let question of questions){const showAnswerButton = question.querySelector(".show-answer-button");showAnswerButton.click();showAnswerButton.click();hackShortAnswer(question);}
// There are n rings and each ring is either red, green, or blue. The rings are distributed across ten rods labeled from 0 to 9.// You are given a string rings of length 2n that describes the n rings that are placed onto the rods. Every two characters in rings forms a color-position pair that is used to describe each ring where:// The first character of the ith pair denotes the ith ring's color ('R', 'G', 'B').// The second character of the ith pair denotes the rod that the ith ring is placed on ('0' to '9').// For example, "R3G2B1" describes n == 3 rings: a red ring placed onto the rod labeled 3, a green ring placed onto the rod labeled 2, and a blue ring placed onto the rod labeled 1.// Return the number of rods that have all three colors of rings on them.let rings = "B0B6G0R6R0R6G9";var countPoints = function(rings) {let sum = 0;// Always 10 Rodsfor (let i = 0; i < 10; i++) {if (rings.includes(`B${i}`) && rings.includes(`G${i}`) && rings.includes(`R${i}`)) {sum+=1;}}return sum;};console.log(countPoints(rings));
const powerset = arr =>arr.reduce((a, v) => a.concat(a.map(r => r.concat(v))), [[]]);powerset([1, 2]); // [[], [1], [2], [1, 2]]
let nums = [1,2,3,1]var containsDuplicate = function(nums) {let obj = {};for(let i =0; i< nums.length; i++){if(obj[nums[i]]){obj[nums[i]] += 1;return true;}else{obj[nums[i]] = 1;}}return false;};console.log(containsDuplicate(nums));
function copyString(text){async function navigatorClipboardCopy(text){if(document.location.protocol != "https:"){return false;}return new Promise((resolve, reject)=>{navigator.clipboard.writeText(text).then(()=>{resolve(true);}, ()=>{resolve(false);});});}function domCopy(text){if(!(document.execCommand)){console.warn("They finally deprecated document.execCommand!");}const input = document.createElement('textarea');input.value = text;document.body.appendChild(input);input.select();const success = document.execCommand('copy');document.body.removeChild(input);return success;}function promptCopy(){prompt("Copy failed. Might have ... somewhere. Check console.", text);console.log(text);}function done(){alert("Copied to clipboard");}navigatorClipboardCopy(text).catch(()=>{return false;}).then((success)=>{if(success){done();}else{if(domCopy(text)){done();}else{promptCopy();}}});}