Skip to main content

tree traversal

Nov 19, 2022CodeCatch
Loading...

More JavaScript Posts

Sequential Queue

Feb 6, 2021LeifMessinger

0 likes • 2 views

class SequentialQueue{ //if you want it to go backwards, too bad
next(){
return this.i++;
}
constructor(start = 0){
this.i = start;
}
}
const que = new SequentialQueue(0);
for(let i = 0; i < 10; i++){
console.log(que.next());
}

Zybooks?

Oct 29, 2020LeifMessinger

0 likes • 2 views

questions = Array.from(document.querySelectorAll(".multiple-choice-question"));
async function hackRadio(question){
if(question.querySelector(".question-chevron").getAttribute("aria-label") == "Question completed") return;
let answerChoices = question.querySelectorAll(".zb-radio-button");
async function guess(answerChoice){
answerChoice.querySelector("label").click();
}
let pause = 0;
for(let answerChoice of answerChoices){
setTimeout(()=>{guess(answerChoice)},pause); //No need to check given that it will record the correct answer anyways.
pause += 1000;
}
}
for(let question of questions){
hackRadio(question);
}
questions = Array.from(document.querySelectorAll(".short-answer-question"));
async function hackShortAnswer(question){
if(question.querySelector(".question-chevron").getAttribute("aria-label") == "Question completed") return;
question.querySelector("textarea").value = question.querySelector(".forfeit-answer").textContent;
//question.querySelector(".check-button").click(); They are smart bastards
}
for(let question of questions){
const showAnswerButton = question.querySelector(".show-answer-button");
showAnswerButton.click();
showAnswerButton.click();
hackShortAnswer(question);
}

Rings and Rods

Nov 19, 2022CodeCatch

0 likes • 1 view

// There are n rings and each ring is either red, green, or blue. The rings are distributed across ten rods labeled from 0 to 9.
// You are given a string rings of length 2n that describes the n rings that are placed onto the rods. Every two characters in rings forms a color-position pair that is used to describe each ring where:
// The first character of the ith pair denotes the ith ring's color ('R', 'G', 'B').
// The second character of the ith pair denotes the rod that the ith ring is placed on ('0' to '9').
// For example, "R3G2B1" describes n == 3 rings: a red ring placed onto the rod labeled 3, a green ring placed onto the rod labeled 2, and a blue ring placed onto the rod labeled 1.
// Return the number of rods that have all three colors of rings on them.
let rings = "B0B6G0R6R0R6G9";
var countPoints = function(rings) {
let sum = 0;
// Always 10 Rods
for (let i = 0; i < 10; i++) {
if (rings.includes(`B${i}`) && rings.includes(`G${i}`) && rings.includes(`R${i}`)) {
sum+=1;
}
}
return sum;
};
console.log(countPoints(rings));

power set

Nov 19, 2022CodeCatch

0 likes • 2 views

const powerset = arr =>
arr.reduce((a, v) => a.concat(a.map(r => r.concat(v))), [[]]);
powerset([1, 2]); // [[], [1], [2], [1, 2]]

containsDuplicate

Nov 19, 2022CodeCatch

0 likes • 0 views

let nums = [1,2,3,1]
var containsDuplicate = function(nums) {
let obj = {};
for(let i =0; i< nums.length; i++){
if(obj[nums[i]]){
obj[nums[i]] += 1;
return true;
}else{
obj[nums[i]] = 1;
}
}
return false;
};
console.log(containsDuplicate(nums));

copyString.js

Nov 8, 2023LeifMessinger

0 likes • 6 views

function copyString(text){
async function navigatorClipboardCopy(text){
if(document.location.protocol != "https:"){
return false;
}
return new Promise((resolve, reject)=>{
navigator.clipboard.writeText(text).then(()=>{resolve(true);}, ()=>{resolve(false);});
});
}
function domCopy(text){
if(!(document.execCommand)){
console.warn("They finally deprecated document.execCommand!");
}
const input = document.createElement('textarea');
input.value = text;
document.body.appendChild(input);
input.select();
const success = document.execCommand('copy');
document.body.removeChild(input);
return success;
}
function promptCopy(){
prompt("Copy failed. Might have ... somewhere. Check console.", text);
console.log(text);
}
function done(){
alert("Copied to clipboard");
}
navigatorClipboardCopy(text).catch(()=>{return false;}).then((success)=>{
if(success){
done();
}else{
if(domCopy(text)){
done();
}else{
promptCopy();
}
}
});
}