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try-catch modularity

Jan 31, 2023AustinLeath
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Add Binary Numbers

Oct 15, 2022CodeCatch

0 likes • 6 views

public static String addBinary(){
// The two input Strings, containing the binary representation of the two values:
String input0 = "1010";
String input1 = "10";
// Use as radix 2 because it's binary
int number0 = Integer.parseInt(input0, 2);
int number1 = Integer.parseInt(input1, 2);
int sum = number0 + number1;
return Integer.toBinaryString(sum); //returns the answer as a binary value;
}
public static void enu2ecefCov(GMatrix ecefCov, GMatrix enuCov, LLA refLLA) {
double lambda = refLLA.longitude;
double phi = refLLA.latitude;
GMatrix R = new GMatrix(6, 6);
GMatrix Rt = new GMatrix(6, 6);
GMatrix tmp1 = new GMatrix(6, 6);
GMatrix tmp2 = new GMatrix(6, 6);
R.setElement(0, 0, -Math.sin(lambda));
R.setElement(0, 1, -Math.sin(phi)*Math.cos(lambda));
R.setElement(0, 2, Math.cos(phi)*Math.cos(lambda));
R.setElement(1, 0, Math.cos(lambda));
R.setElement(1, 1, -Math.sin(phi)*Math.sin(lambda));
R.setElement(1, 2, Math.cos(phi)*Math.sin(lambda));
R.setElement(2, 0, 0);
R.setElement(2, 1, Math.cos(phi));
R.setElement(2, 2, Math.sin(phi));
R.setElement(3, 3, -Math.sin(lambda));
R.setElement(3, 4, -Math.sin(phi)*Math.cos(lambda));
R.setElement(3, 5, Math.cos(phi)*Math.cos(lambda));
R.setElement(4, 3, Math.cos(lambda));
R.setElement(4, 4, -Math.sin(phi)*Math.sin(lambda));
R.setElement(4, 5, Math.cos(phi)*Math.sin(lambda));
R.setElement(5, 3, 0);
R.setElement(5, 4, Math.cos(phi));
R.setElement(5, 5, Math.sin(phi));
Rt.transpose(R);
tmp1.mul(enuCov, R);
ecefCov.mul(Rt, tmp1);
}

Word Counter

Nov 19, 2022CodeCatch

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import java.io.File;
import java.io.IOException;
import java.util.Map;
import java.util.Scanner;
import java.util.TreeMap;
public class SimpleWordCounter {
public static void main(String[] args) {
try {
File f = new File("ciaFactBook2008.txt");
Scanner sc;
sc = new Scanner(f);
// sc.useDelimiter("[^a-zA-Z']+");
Map<String, Integer> wordCount = new TreeMap<String, Integer>();
while(sc.hasNext()) {
String word = sc.next();
if(!wordCount.containsKey(word))
wordCount.put(word, 1);
else
wordCount.put(word, wordCount.get(word) + 1);
}
// show results
for(String word : wordCount.keySet())
System.out.println(word + " " + wordCount.get(word));
System.out.println(wordCount.size());
}
catch(IOException e) {
System.out.println("Unable to read from file.");
}
}
}

Send Email from Java

Nov 19, 2022CodeCatch

0 likes • 5 views

import javax.mail.*;
import javax.mail.internet.*;
import java.util.*;
public void postMail( String recipients[ ], String subject, String message , String from) throws MessagingException
{
boolean debug = false;
//Set the host smtp address
Properties props = new Properties();
props.put("mail.smtp.host", "smtp.example.com");
// create some properties and get the default Session
Session session = Session.getDefaultInstance(props, null);
session.setDebug(debug);
// create a message
Message msg = new MimeMessage(session);
// set the from and to address
InternetAddress addressFrom = new InternetAddress(from);
msg.setFrom(addressFrom);
InternetAddress[] addressTo = new InternetAddress[recipients.length];
for (int i = 0; i < recipients.length; i++)
{
addressTo[i] = new InternetAddress(recipients[i]);
}
msg.setRecipients(Message.RecipientType.TO, addressTo);
// Optional : You can also set your custom headers in the Email if you Want
msg.addHeader("MyHeaderName", "myHeaderValue");
// Setting the Subject and Content Type
msg.setSubject(subject);
msg.setContent(message, "text/plain");
Transport.send(msg);
}

longest sequence

Oct 7, 2023AustinLeath

0 likes • 5 views

import java.util.Arrays;
public class LongestIncreasingSubsequence {
public int lengthOfLIS(int[] nums) {
if (nums.length == 0) {
return 0;
}
int[] dp = new int[nums.length];
Arrays.fill(dp, 1); // Initialize all elements in dp array to 1, as each element itself is a valid subsequence of length 1.
int maxLength = 1; // Initialize the maximum length to 1, considering a single element as the sequence.
for (int i = 1; i < nums.length; i++) {
for (int j = 0; j < i; j++) {
if (nums[i] > nums[j]) {
dp[i] = Math.max(dp[i], dp[j] + 1); // If nums[i] is greater than nums[j], update the longest subsequence length ending at i.
}
}
maxLength = Math.max(maxLength, dp[i]); // Update the maximum length if needed.
}
return maxLength;
}
public static void main(String[] args) {
LongestIncreasingSubsequence lis = new LongestIncreasingSubsequence();
int[] nums = {10, 9, 2, 5, 3, 7, 101, 18};
int result = lis.lengthOfLIS(nums);
System.out.println("Length of the Longest Increasing Subsequence: " + result); // Output: 4
}
}

LeetCode #21: Merge Two Sorted Lists

Oct 15, 2022CodeCatch

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public class Solution {
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
ListNode head = new ListNode(0);
ListNode handler = head;
while(l1 != null && l2 != null) {
if (l1.val <= l2.val) {
handler.next = l1;
l1 = l1.next;
} else {
handler.next = l2;
l2 = l2.next;
}
handler = handler.next;
}
if (l1 != null) {
handler.next = l1;
} else if (l2 != null) {
handler.next = l2;
}
return head.next;
}
}