find parity outliers | Python

January 2nd, 2022 05:29:52 PM

					
from collections import Counter def find_parity_outliers(nums): return [ x for x in nums if x % 2 != Counter([n % 2 for n in nums]).most_common()[0][0] ] find_parity_outliers([1, 2, 3, 4, 6]) # [1, 3]

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